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• Capture FFMPEG output

  2 mai 2017, par Andrew

  I need to read the output from ffmpeg in order to even try the solution to my question from yesterday. This is a separate issue from my problem there, so I made a new question.

  How the heck do I get the output from an ffmpeg -i command in PHP ?

  This is what I’ve been trying :

  <?PHP
  
      error_reporting(E_ALL);
  
      $src = "/var/videos/video1.wmv";
  
      $command = "/usr/bin/ffmpeg -i " . $src;
  
      echo "<b>",$command,"</b><br />";
  
      $command = escapeshellcmd($command);
  
  
  
      echo "backtick:<br /><pre>";
  
      `$command`;
  
  
  
      echo "</pre><br />system:<br /><pre>";
  
      echo system($command);
  
  
  
      echo "</pre><br />shell_exec:<br /><pre>";
  
      echo shell_exec($command);
  
  
  
      echo "</pre><br />passthru:<br /><pre>";
  
      passthru($command);
  
  
  
      echo "</pre><br />exec:<br /><pre>";
  
      $output = array();
  
      exec($command,$output,$status);
  
      foreach($output AS $o)
  
      {
  
              echo $o , "<br />";
  
      }
  
      echo "</pre><br />popen:<br /><pre>";
  
      $handle = popen($command,'r');
  
      echo fread($handle,1048576);
  
      pclose($handle);
  
      echo "</pre><br />";
  
  ?>

  This is my output :

  <b>/usr/bin/ffmpeg -i /var/videos/video1.wmv</b><br />
  
  backtick:<br />
  
      <pre></pre><br />
  
  system:<br />
  
      <pre></pre><br />
  
  shell_exec:<br />
  
      <pre></pre><br />
  
  passthru:<br />
  
      <pre></pre><br />
  
  exec:<br />
  
      <pre></pre><br />
  
  popen:<br />
  
      <pre></pre><br />

  I don’t get it. safe_mode is off. There’s nothing in disable_functions. The directory is owned by www-data (the apache user on my Ubuntu system). I get a valid status back from exec() and system() and running the same command from the command line give me tons of output. I feel like I must be missing something obvious but I have no idea what it is.

• Capture FFMPEG output in PHP

  22 novembre 2012, par Andrew

  I need to read the output from ffmpeg in order to even try the solution to my question from yesterday. This is a separate issue from my problem there, so I made a new question.

  How the heck do I get the output from an ffmpeg -i command in PHP ?

  This is what I've been trying :

  <?PHP
  
      error_reporting(E_ALL);
  
      $src = "/var/videos/video1.wmv";
  
      $command = "/usr/bin/ffmpeg -i " . $src;
  
      echo "<b>",$command,"</b><br />";
  
      $command = escapeshellcmd($command);
  
  
  
      echo "backtick:<br /><pre>";
  
      `$command`;
  
  
  
      echo "</pre><br />system:<br /><pre>";
  
      echo system($command);
  
  
  
      echo "</pre><br />shell_exec:<br /><pre>";
  
      echo shell_exec($command);
  
  
  
      echo "</pre><br />passthru:<br /><pre>";
  
      passthru($command);
  
  
  
      echo "</pre><br />exec:<br /><pre>";
  
      $output = array();
  
      exec($command,$output,$status);
  
      foreach($output AS $o)
  
      {
  
              echo $o , "<br />";
  
      }
  
      echo "</pre><br />popen:<br /><pre>";
  
      $handle = popen($command,&#39;r&#39;);
  
      echo fread($handle,1048576);
  
      pclose($handle);
  
      echo "</pre><br />";
  
  ?>

  This is my output :

  <b>/usr/bin/ffmpeg -i /var/videos/video1.wmv</b><br />
  
  backtick:<br />
  
      <pre></pre><br />
  
  system:<br />
  
      <pre></pre><br />
  
  shell_exec:<br />
  
      <pre></pre><br />
  
  passthru:<br />
  
      <pre></pre><br />
  
  exec:<br />
  
      <pre></pre><br />
  
  popen:<br />
  
      <pre></pre><br />

  I don't get it. safe_mode is off. There's nothing in disable_functions. The directory is owned by www-data (the apache user on my Ubuntu system). I get a valid status back from exec() and system() and running the same command from the command line give me tons of output. I feel like I must be missing something obvious but I have no idea what it is.

  Help. Please.

• FFMPEG Command in Android Failing to Execute

  15 janvier 2015, par Zoe

  I’m trying to execute ffmpeg commands through an android app I’m developing.

  I found this post which has been somewhat useful :
  Problems with ffmpeg command line on android

  and I downloaded a static build of ffmpeg from here : http://ffmpeg.gusari.org/static/

  The problem is, when this code runs

  public void merge_video(){
  
  
  
  
  
        String[] ffmpegCommand = new String[5];
  
        ffmpegCommand[0] = "/data/data/com.example.zovideo/ffmpeg";
  
        ffmpegCommand[1] = "-i";
  
        ffmpegCommand[2] = "concat:storage/emulated/0/DCIM/Camera/VID30141106_211509.mp4|storage/emulated/0/DCIM/Camera/VID30141106_211509.mp4";
  
        ffmpegCommand[3] = "copy";
  
        ffmpegCommand[4] = "storage/emulated/0/DCIM/ZoVideo/Output.mp4";  
  
  
  
        try {
  
            Process ffmpegProcess = new ProcessBuilder(ffmpegCommand).redirectErrorStream(true).start();
  
  
  
            String line;
  
            BufferedReader reader = new BufferedReader(new InputStreamReader(ffmpegProcess.getInputStream()));
  
            Log.d(null, "*******Starting FFMPEG");
  
  
  
            while((line = reader.readLine())!=null){
  
  
  
                Log.d(null, "***"+line+"***"); 
  
            }
  
            Log.d(null,"****ending FFMPEG****");
  
  
  
      } catch (IOException e) {
  
          e.printStackTrace();
  
      }
  
    }

  It fails when trying to start the process with

  Java.io.IOException: Error running exec(). Command: [/data/data/com.example.zovideo/ffmpeg, -i, concat:storage/emulated/0/DCIM/Camera/VID30141106_211509.mp4|storage/emulated/0/DCIM/Camera/VID30141106_211509.mp4, copy, storage/emulated/0/DCIM/ZoVideo/Output.mp4] Working Directory: null Environment: [ANDROID_ROOT=/system, EMULATED_STORAGE_SOURCE=/mnt/shell/emulated, LOOP_MOUNTPOINT=/mnt/obb, LD_PRELOAD=libsigchain.so, ANDROID_BOOTLOGO=1, EMULATED_STORAGE_TARGET=/storage/emulated, EXTERNAL_STORAGE=/storage/emulated/legacy, SYSTEMSERVERCLASSPATH=/system/framework/services.jar:/system/framework/ethernet-service.jar:/system/framework/wifi-service.jar, ANDROID_SOCKET_zygote=10, PATH=/sbin:/vendor/bin:/system/sbin:/system/bin:/system/xbin, ANDROID_DATA=/data, ANDROID_ASSETS=/system/app, ASEC_MOUNTPOINT=/mnt/asec, BOOTCLASSPATH=/system/framework/core-libart.jar:/system/framework/conscrypt.jar:/system/framework/okhttp.jar:/system/framework/core-junit.jar:/system/framework/bouncycastle.jar:/system/framework/ext.jar:/system/framework/framework.jar:/system/framework/telephony-common.jar:/system/framework/voip-common.jar:/system/framework/ims-common.jar:/system/framework/mms-common.jar:/system/framework/android.policy.jar:/system/framework/apache-xml.jar, ANDROID_PROPERTY_WORKSPACE=9,0, ANDROID_STORAGE=/storage]

  I understand from the stackoverflow post I mentioned above that the ffmpeg static build needs to be on my device otherwise my app cannot use it.

  However I’m unsure how to get it in the /data/data/com.example.zovideo folder as needed.

  I have done is download the latest static ffmpeg build from http://ffmpeg.gusari.org/static/ and copied it into my libs/armeabi and libs/armeabi-v7a folders but this obviously hasn’t succeeded in getting into the data/data folder when my app is installed onto my device.
  (I feel like I’m being an idiot by copy/pasting the files but I don’t know what else to do. I don’t know how to compile it myself - I have compiled ffmpeg using a Roman10 tutorial but this produces .so files which from which I understand is not what I need)

  So I’m a little stuck.
  Any advice is greatly appreciated. Thanks