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Autres articles (99)
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MediaSPIP 0.1 Beta version
25 avril 2011, parMediaSPIP 0.1 beta is the first version of MediaSPIP proclaimed as "usable".
The zip file provided here only contains the sources of MediaSPIP in its standalone version.
To get a working installation, you must manually install all-software dependencies on the server.
If you want to use this archive for an installation in "farm mode", you will also need to proceed to other manual (...) -
Multilang : améliorer l’interface pour les blocs multilingues
18 février 2011, parMultilang est un plugin supplémentaire qui n’est pas activé par défaut lors de l’initialisation de MediaSPIP.
Après son activation, une préconfiguration est mise en place automatiquement par MediaSPIP init permettant à la nouvelle fonctionnalité d’être automatiquement opérationnelle. Il n’est donc pas obligatoire de passer par une étape de configuration pour cela. -
L’agrémenter visuellement
10 avril 2011MediaSPIP est basé sur un système de thèmes et de squelettes. Les squelettes définissent le placement des informations dans la page, définissant un usage spécifique de la plateforme, et les thèmes l’habillage graphique général.
Chacun peut proposer un nouveau thème graphique ou un squelette et le mettre à disposition de la communauté.
Sur d’autres sites (13375)
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how to allow a worker to run a ffmpeg command on heroku for my python/django app ?
10 mars 2013, par GetItDoneI've been stuck trying to figure this out for weeks. I previously asked a similar question found here but I never got any replies. I really cannot find any good documentation anywhere. All I need to do is use a worker (don't care what worker have django-celery and rq installed) to convert a file to flv when it is uploaded from a form. I was able to get this done easily locally, but after over a week I haven't been able to get it to work no matter what I have tried. I tried adding a tasks.py file for celery, or a worker.py file for rq, and I have no idea what else (if anything) needs to be done, such as in my settings.py or Procfile. My procfile looks like :
web: gunicorn lftv.wsgi -b 0.0.0.0:$PORT
celeryd: celery -A tasks worker --loglevel=info
worker: python worker.pyMy requirements.txt showing what I have installed looks like this :
Django==1.4.3
Logbook==0.4.1
amqp==1.0.6
anyjson==0.3.3
billiard==2.7.3.19
boto==2.6.0
celery==3.0.13
celery-with-redis==3.0
distribute==0.6.31
dj-database-url==0.2.1
django-celery==3.0.11
django-s3-folder-storage==0.1
django-storages==1.1.6
gunicorn==0.16.1
kombu==2.5.4
pil==1.1.7
psycopg2==2.4.5
python-dateutil==1.5
pytz==2012j
redis==2.7.2
requests==1.1.0
rq==0.3.2
six==1.2.0
times==0.6The only thing relevant in my settings.py are as follows :
BROKER_BACKEND = 'django'
BROKER_URL = #For this I copy/pasted the code from my redistogo add-on from heroku. Not sure if correct
BROKER_TRANSPORT_OPTIONS = {'visibility_timeout': 1800}Without trying to take up too much more space, my tasks.py looks like this :
import subprocess
@task
def ffmpeg_conversion(input_file):
converted_file = subprocess.call(input_file)
return converted_fileI use S3 to store my static and media files, and the upload works (adding uploads to my bucket), however no matter what I try the conversion never will. Is there a good tutorial for absolute beginners ? I followed the heroku redis tutorial, celery docs, rq docs, and whatever else I can find, and got the examples to work, but the worker will not execute the command from my view. For example one of the many things I tried :
...
ffmpeg = "ffmpeg -i %s -acodec mp3 -ar 22050 -f flv -s 320x240 %s" % (sourcefile, targetfile)
ffmpegresult = ffmpeg_conversion.delay(ffmpeg)
...or using rq
...
q = Queue(connection=conn)
result = q.enqueue(ffmpeg_conversion, ffmpeg)
...I seems like it should be simple, however I am completely self-taught and have never deployed a project whatsoever, and there just doesn't seem to be any good documentation or tutorial available for what I am trying to do. I can't judge whether I am completely off and completely missing something significant or relatively close to getting this to work. I really do appreciate any input whatsoever, this is driving me nuts. Thanks in advance.
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passing script variable of filename with spaces in bash to external program (ffmpeg) fails
13 janvier 2016, par BostonScottShort story : I’m trying to write a script that will use FFmpeg to convert the many files stored in one directory to a "standard" mp4 format and save the converted files in another directory. It’s been a learning experience (a fun one !) since I haven’t done any real coding since using Pascal and FORTRAN on an IBM 370 mainframe was in vogue.
Essentially the script takes the filename, strips the path and extension off it, reassembles the filename with the path and an mp4 extension and calls FFmpeg with some set parameters to do the conversion. If the directory contains only video files with without spaces in the names, then everything works fine. If the filenames contain spaces, then FFmpeg is not able to process the file and moves on to the next one. The error indicates that FFMpeg is only seeing the filename up to the first space. I’ve included both the script and output below.
Thanks for any help and suggestions you may have. If you think I should be doing this in another way, please by all means, give me your suggestions. As I said, it’s been a long time since I did anything like this. I’m enjoying it though.
I’ve include the code first followed by example output.
for file in ./TBC/*.mp4
do
echo "Start of iteration"
echo "Full text of file name:" $file
#Remove everything up to "C/" (filename without path)
fn_orig=${file#*C/}
echo "Original file name:" $fn_orig
#Length of file name
fn_len=${#fn_orig}
echo "Filename Length:" $fn_len
#file name without path or extension
fn_base=${fn_orig:0:$fn_len-4}
echo "Base file name:" $fn_base
#new filename suffix
newsuffix=".conv.mp4"
fn_out=./CONV/$fn_base$newsuffix
echo "Converted file name:" $fn_out
ffmpeg -i $file -metadata title="$fn_orig" -c:v libx264 -c:a libfdk_aac -b:a 128k $fn_out
echo "End of iteration"
echo
done
echo "Script completed"With the ffmpeg line commented out, and two files in the ./TBC directory, this is the output that I get
Start of iteration
Full text of file name: ./TBC/Test file with spaces.mp4
Original filename: Test file with spaces.mp4
Filename Length: 25
Base filename: Test file with spaces
Converted file name: ./CONV/Test file with spaces.conv.mp4
End of iteration
Start of iteration
Full text of file name: ./TBC/Test_file_with_NO_spaces.mp4
Original file name: Test_file_with_NO_spaces.mp4
Filename Length: 28
Base file name: Test_file_with_NO_spaces
Converted file name: ./CONV/Test_file_with_NO_spaces.conv.mp4
End of iteration
Script completedI won’t bother to post the results when ffmpeg is uncommented, other than to state that it fails with the error :
./TBC/Test : No such file or directoryThe script then continues to the next file which completes successfully because it has no spaces in its name. The actual filename is "Test file with spaces.mp4" so you can see that ffmpeg stops after the word "Test" when it encounters a space.
I hope this has been clear and concise and hopefully someone will be able to point me in the right direction. There is a lot more that I want to do with this script such as parsing subdirectories and ignoring non-video files, etc.
I look forward to any insight you can give !
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Android + ffmpeg + AudioTrack produces bad audio output
12 septembre 2014, par Goddchenhere is what I am trying to do : use an
AudioRecord
and "pipe" the output ofAudioRecord.read(byte[],...)
to an ffmpeg process’ stdin that will convert to a 3gp (AAC) file.The ffmpeg call is as follows :
ProcessBuilder processBuilder = new ProcessBuilder(BINARY.getAbsolutePath(),
"-y",
"-ar", "44100", "-c:a", "pcm_s16le", "-ac", "1","-f","s16le",
"-i", "-",
"-strict", "-2", "-c:a", "aac",
outFile.getAbsolutePath());The AudioRecord is setup as follows :
AudioRecord record = new AudioRecord(/*AudioSource.VOICE_RECOGNITION,*/ AudioSource.MIC,
SAMPLING_RATE,
AudioFormat.CHANNEL_IN_MONO,
AudioFormat.ENCODING_PCM_16BIT,
bufferSize);SAMPLING_RATE = 44100
andbufferSize
is the one returned byAudioRecord.getMinBufferSize(...)
I am writing the data to ffmpeg like this :
try {
IOUtils.write(data, getFFmpegHelper().getCurrentProcessOutputStream());
} catch (Exception e) {
Log.e(Application.LOG_TAG, "Error writing data to ffmpeg process", e);
//TODO notify user, stop the recording, etc...
}So far so good, the ffmpeg runs and created a proper 3gp file. But the audio in the file is totally off. It seems "choppy" (not sure if this is the correct english word ;) ) and also the pace is wrong, is plays too fast.
Check out this sample : http://goddchen.de/android/tmp/tmp.3gp
This is the output of the ffmpeg process :
[s16le @ 0x23634d0] Estimating duration from bitrate, this may be inaccurate
Guessed Channel Layout for Input Stream #0.0 : mono
Input #0, s16le, from 'pipe:':
Duration: N/A, start: 0.000000, bitrate: 705 kb/s
Stream #0:0: Audio: pcm_s16le, 44100 Hz, mono, s16, 705 kb/s
[aformat @ 0x2363100] auto-inserting filter 'auto-inserted resampler 0' between the filter 'src' and the filter 'aformat'
[aresample @ 0x235b0a0] chl:mono fmt:s16 r:44100Hz -> chl:mono fmt:flt r:44100Hz
Output #0, 3gp, to '/data/data/com.test.audio/files/tmp.3gp':
Metadata:
encoder : Lavf54.6.100
Stream #0:0: Audio: aac (mp4a / 0x6134706D), 44100 Hz, mono, flt, 128 kb/s
Stream mapping:
Stream #0:0 -> #0:0 (pcm_s16le -> aac)
size= 3kB time=00:00:00.18 bitrate= 132.5kbits/s
size= 8kB time=00:00:00.55 bitrate= 120.9kbits/s
size= 12kB time=00:00:00.83 bitrate= 121.8kbits/s
size= 16kB time=00:00:01.04 bitrate= 122.8kbits/s
size= 20kB time=00:00:01.32 bitrate= 122.5kbits/s
size= 23kB time=00:00:01.53 bitrate= 121.6kbits/s
size= 27kB time=00:00:01.81 bitrate= 121.0kbits/s
size= 31kB time=00:00:02.11 bitrate= 120.7kbits/s
size= 35kB time=00:00:02.32 bitrate= 123.4kbits/s
video:0kB audio:34kB global headers:0kB muxing overhead 3.031610%