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Médias (91)
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Spitfire Parade - Crisis
15 mai 2011, par
Mis à jour : Septembre 2011
Langue : English
Type : Audio
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Wired NextMusic
14 mai 2011, par
Mis à jour : Février 2012
Langue : English
Type : Video
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Video d’abeille en portrait
14 mai 2011, par
Mis à jour : Février 2012
Langue : français
Type : Video
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Sintel MP4 Surround 5.1 Full
13 mai 2011, par
Mis à jour : Février 2012
Langue : English
Type : Video
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Carte de Schillerkiez
13 mai 2011, par
Mis à jour : Septembre 2011
Langue : English
Type : Texte
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Publier une image simplement
13 avril 2011, par ,
Mis à jour : Février 2012
Langue : français
Type : Video
Autres articles (34)
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L’utiliser, en parler, le critiquer
10 avril 2011La première attitude à adopter est d’en parler, soit directement avec les personnes impliquées dans son développement, soit autour de vous pour convaincre de nouvelles personnes à l’utiliser.
Plus la communauté sera nombreuse et plus les évolutions seront rapides ...
Une liste de discussion est disponible pour tout échange entre utilisateurs. -
Contribute to documentation
13 avril 2011Documentation is vital to the development of improved technical capabilities.
MediaSPIP welcomes documentation by users as well as developers - including : critique of existing features and functions articles contributed by developers, administrators, content producers and editors screenshots to illustrate the above translations of existing documentation into other languages
To contribute, register to the project users’ mailing (...) -
Publier sur MédiaSpip
13 juin 2013Puis-je poster des contenus à partir d’une tablette Ipad ?
Oui, si votre Médiaspip installé est à la version 0.2 ou supérieure. Contacter au besoin l’administrateur de votre MédiaSpip pour le savoir
Sur d’autres sites (4218)
-
ffmpeg save highly quality video by using rtsp link [closed]
22 août 2023, par Shivam SinghI'm trying to download good quality of video from the camera stream by using ffmpeg


ffmpeg -i rtsp://admin:admin@123@117.216.143.251:556 -r 15 /home/Documents/Yolo/yolo/251.avi



How to download good quality of video by using ffmpeg ?


-
pyav - cannot save stream as mono
3 août 2022, par ZvikaI'm trying to use
pyav
to convert arbitrary audio file to a low quality, mono, wave file.

I almost managed to do it, but it's stereo, and I couldn't find how to make it mono. Furthermore, I think I made some mistake here, as I had to repeat the
rate
in theoutput_container.add_stream
and in theAudioResampler
- it seems redundant, and I can't understand what would happen if those numbers won't match.

My code is :


import av
 
 input_file = 'some.mp3'
 output_file = 'new.wav'
 
 rate = 22000
 
 output_container = av.open(output_file, 'w')

 # can I tell `output_stream` to just use `resampler`'s info?
 # or, if not, how can I tell it to have only 1 channel?
 output_stream = output_container.add_stream('pcm_u8', rate) 
 
 resampler = av.audio.resampler.AudioResampler('u8p', 'mono', rate)
 
 input_container = av.open(input_file)
 for frame in input_container.decode(audio=0):
 out_frames = resampler.resample(frame)
 for out_frame in out_frames:
 for packet in output_stream.encode(out_frame):
 output_container.mux(packet)
 output_container.close()



And not related to my main question, but any comments regarding my code, or pointing out mistakes, are welcomed. I hardly could find usage examples to use a reference, and PyAV API documentation isn't very detailed...


-
Convert video into mp3 format using ffmpeg in nodejs and angular and then save converted audio into the database(mongodb)
6 septembre 2021, par Amir ShahzadThis is nodejs server side file


const express = require('express');
const ffmpeg = require('fluent-ffmpeg');
const fileUpload = require('express-fileupload');
const mongoose = require('mongoose');
const cors = require('cors')
const app = express();
const Video = require('./models/video');
mongoose.connect('mongodb://localhost:27017/YoutubeApp', {
 useNewUrlParser: true,
 useUnifiedTopology: true,
});
const db = mongoose.connection;
db.on('error', console.error.bind(console, 'connection error'));
db.once('open', () => {
 console.log('Data Base Connected Successfully!');
});

app.use(fileUpload({
 useTempFiles: true,
 tempFileDir: 'temp/'
}));
app.use(express.json());
app.use(express.urlencoded({ extended: true }));
app.use(cors({ origin: 'http://localhost:4200' }));


ffmpeg.setFfmpegPath('/usr/bin/ffmpeg');

app.post('/mp4tomp3', (req, res) => {
 convertdata = req.body;
 console.log('path of innput is', req.body);
 function convert(input, output, callback) {
 ffmpeg(input)
 .output(output)
 .on('end', function() { 
 console.log('conversion ended');
 callback(null);
 }).on('error', function(err){
 console.log('error: ', err.code, err.msg);
 callback(err);
 }).run();
 }
 convert(convertdata, './temp/output.mp3', function(err){
 if(!err) {
 console.log('conversion complete');

 
 }
 })

 app.listen(3000, () => {
 console.log('Server Start On Port 3000')
 })



In Convert function i not know how i can get input by the user i'm new in angular Please anyone can solve this out thanks in advance


This is video model file


const mongoose = require("mongoose");
const Schema = mongoose.Schema;

const videoSchema = new Schema({
 mp4: String,
});
module.exports = mongoose.model("Videos", videoSchema);



**This is Typescript code in angular client side that handle user input and select video **


import { ThrowStmt } from '@angular/compiler';
import { Component, OnInit } from '@angular/core';
import { FormBuilder, FormGroup, Validators } from '@angular/forms';
import { VideoConversionService } from 'src/services/video-conversion.service';

@Component({
 selector: 'app-root',
 templateUrl: './app.component.html',
 styleUrls: ['./app.component.css']
})
export class AppComponent implements OnInit {

 submitted =false;
 form! : FormGroup
 data:any

 constructor(private formBuilder: FormBuilder,
 private videoService: VideoConversionService){}

 creatForm(){
 this.form = this.formBuilder.group({
 mp4: ['', Validators.required],
 });
 }
 ngOnInit(): void {
 this.creatForm();

 }


 convertVideo(){
 this.submitted = true
 this.videoService.conversion(this.form.value).subscribe(res => {
 this.data = res;
 })
 }

 }



I do not know how to create logic to do that (convert video into audio using angular framework)


This is app.component.html file where i want to get video from the user using input field


<div class="container">
 <h1>Video Proccessing App</h1>
 <form>
 <input type="file" formcontrolname="mp4" />
 <input type="submit" value="Convert" />
 </form>
</div>





But my code is not working and video is not converting into audio


This is my video service file where i calling nodejs api to perform the task


import { Injectable } from '@angular/core';
import { HttpClient } from '@angular/common/http';
@Injectable({
 providedIn: 'root'
})
export class VideoConversionService {

constructor(private httpClient: HttpClient) { }

conversion(data: any){
 return this.httpClient.post('http://localhost:3000/mp4tomp3', data)
}
}



Please anyone can solve my problem Thanks in advance