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• Using command line find to encode files and save to same directory

  15 janvier 2017, par Ali Samii

  I am trying to execute a find bash command to process hundreds of video files that are all named video-original.mp4 but are in subdirectories of a parent directory.

  Here’s an example of the directory structure :

  videos
  
  ├── 01a
  
  │   └── video-original.mp4
  
  ├── 01b
  
  │   └── video-original.mp4
  
  ├── 02a
  
  │   └── video-original.mp4
  
  ├── 02b
  
  │   └── video-original.mp4
  
  ├── 03a
  
  │   └── video-original.mp4
  
  └── 03b
  
      └── video-original.mp4

  I am using the following command :

  find ./ -name 'video-original.mp4' -exec bash -c 'ffmpeg -i "$0" -f mp4 -vcodec libx264 -preset veryslow -profile:v high -acodec aac -movflags faststart video.mp4 -hide_banner' {} \;

  The problem I am having is that it is saving the file video.mp4 in the parent videos directory, instead of in the subdirectory next to the original video-original.mp4

  Afterwards, I want to delete the file video-original.mp4. Currently, my process entails waiting for all the videos to be reencoded, and then once complete, issuing a separate command to delete the file video-original.mp4 :

  find ./ -name 'video-original.mp4' -exec bash -c 'rm -rf "$0"' {} \;

  And my final step would be to extract a screenshot of the new video.mp4 at 10 seconds and save it as thumbnail.jpg. Again, I am currently doing that as a separate step that I execute after the previous two steps are completed.

  find ./ -name 'video.mp4' -exec bash -c 'ffmpeg -i "$0" -ss 00:00:10 -vframes 1 thumbnail.jpg' {} \;

  What I would like to do is combine these three steps into a single command so the end result will be :

  videos
  
  ├── 01a
  
  │   ├── thumbnail.jpg
  
  │   └── video.mp4
  
  ├── 01b
  
  │   ├── thumbnail.jpg
  
  │   └── video.mp4
  
  ├── 02a
  
  │   ├── thumbnail.jpg
  
  │   └── video.mp4
  
  ├── 02b
  
  │   ├── thumbnail.jpg
  
  │   └── video.mp4
  
  ├── 03a
  
  │   ├── thumbnail.jpg
  
  │   └── video.mp4
  
  └── 03b
  
      ├── thumbnail.jpg
  
      └── video.mp4

  Finally, it would be great to save that as a bash script and include it in my path in /usr/local/bin or ~/bin as an executable so I could just issue the command reencode and it would run. Would be even better if the input file could have any video file, for example, random_name.mp4 or random_name.mov or random_name.webm, basically any video file (but skipping video.mp4 at the encoding step).

• avformat/utils : inject audio skip side data before the side data merge code

  21 novembre 2013, par Michael Niedermayer

  avformat/utils : inject audio skip side data before the side data merge code
  This ensures that its handled the same way as other side data
  Signed-off-by : Michael Niedermayer <michaelni@gmx.at>
  

  • [DH] libavformat/utils.c
  • [DH] tests/ref/seek/acodec-mp2

• How to Convert video into mp3 using ffmpeg in nodejs and angular and save converted audio into the database

  2 septembre 2021, par Amir Shahzad

  This is nodejs server side code

  


  const express = require('express');
const ffmpeg  = require('fluent-ffmpeg');
const fileUpload = require('express-fileupload');
const mongoose = require('mongoose');
const cors   = require('cors')
const app = express();
const Video = require('./models/video');
mongoose.connect('mongodb://localhost:27017/YoutubeApp', {
    useNewUrlParser: true,
    useUnifiedTopology: true,
});
const db = mongoose.connection;
db.on('error', console.error.bind(console, 'connection error'));
db.once('open', () => {
   console.log('Data Base Connected Successfully!');
});

app.use(fileUpload({
   useTempFiles: true,
   tempFileDir: 'temp/'
}));
app.use(express.json());
app.use(express.urlencoded({ extended: true }));
app.use(cors({ origin: 'http://localhost:4200' }));


ffmpeg.setFfmpegPath('/usr/bin/ffmpeg');

app.post('/mp4tomp3', (req, res) => {
const data = new Video({
     mp4: req.body.mp4
});
res.contentType('video/avi');
res.attachment('output.mp3');
req.files.mp4val.mv("temp/" + req.body, function(err) {
    if(err){
        res.sendStatus(500).send(err)
    }else{
        console.log("Fiel Uploaded Successfully.!");
    }
});
// Convertin Mp4 To Avi
ffmpeg('temp/' + req.files.mp4val.mp4)
.toFormat('mp3')
.on('end', function() {
    console.log('Done');
})
.on('error', function(err){
    console.log('An Error Occured' + err.message)
})
 .pipe(res, {end: true})
 })

 app.listen(3000, () => {
    console.log('Server Start On Port 3000')
 })


  


  Here i want to get input from the user with input tag and then want to convert video into audio and save into the database but i not know how i can do this

  


  This is video model file

  


  const mongoose = require("mongoose");
const Schema = mongoose.Schema;

const videoSchema = new Schema({
    mp4: String,
});
module.exports = mongoose.model("Videos", videoSchema);


  


  **This is Typescript code in angular client side that handle user input and select video **

  


  import { ThrowStmt } from '@angular/compiler';
import { Component, OnInit } from '@angular/core';
import { FormBuilder, FormGroup, Validators } from '@angular/forms';
import { VideoConversionService } from 'src/services/video-conversion.service';

@Component({
  selector: 'app-root',
  templateUrl: './app.component.html',
  styleUrls: ['./app.component.css']
})
export class AppComponent implements OnInit {

   submitted =false;
   form! : FormGroup
   data:any

   constructor(private formBuilder: FormBuilder,
       private videoService: VideoConversionService){}

   creatForm(){
    this.form = this.formBuilder.group({
    mp4: ['', Validators.required],
  });
  }
   ngOnInit(): void {
   this.creatForm();

  }


  convertVideo(){
    this.submitted = true
    this.videoService.conversion(this.form.value).subscribe(res => {
    this.data = res;
 })
 }

 }


  


  I do not know how to create logic to do that (convert video into audio using angular framework)

  


  This is app.component.html file where i want to get video from the user using input field

  


  <div class="container">&#xA;   <h1>Video Proccessing App</h1>&#xA;   <form>&#xA;     <input type="file" formcontrolname="mp4" />&#xA;     <input type="submit" value="Convert" />&#xA;  </form>&#xA;</div>&#xA;

  


  


  But my code is not working and video is not converting into audio

  


  This is my video service file where i calling nodejs api to perform the task

  


  import { Injectable } from '@angular/core';
import { HttpClient  } from '@angular/common/http';
@Injectable({
   providedIn: 'root'
})
export class VideoConversionService {

constructor(private httpClient: HttpClient) { }

conversion(data: any){
   return this.httpClient.post('http://localhost:3000/mp4tomp3', data)
}
}


  


  Please anyone can solve my problem Thanks in advance