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• How to concatenate two MP4 files, which require http basic Authorization : Bearer , using ffmpeg ?

  8 juillet 2023, par Jeff Strongman

  Hello dear ffmpeg experts ! 🧠 🎯

  


  I ran the following command, which worked perfectly :

  


  ffmpeg -protocol_whitelist https,concat,tls,tcp -i "concat :https://dash.akamaized.net/akamai/bbb_30fps/bbb_30fps_1280x720_4000k/bbb_30fps_1280x720_4000k_0.m4v|https://dash.akamaized.net/akamai/bbb_30fps/bbb_30fps_1280x720_4000k/bbb_30fps_1280x720_4000k_1.m4v|https://dash.akamaized.net/akamai/bbb_30fps/bbb_30fps_1280x720_4000k/bbb_30fps_1280x720_4000k_2.m4v" -c:v copy -vframes 180 -y Movie_of_6_seconds.mp4

  


  I followed the recommended solution of the following post :
How to concatenate two MP4 files using FFmpeg ?

  


  You can execute the command on your local computer and see that it should run just fine...

  


  I used 3. concat protocol, which does indeed concat init + progressive segments

  


  However... when every segment on a server I refer to, is password protected, it fails with 401 Unauthorized, even though I added the following line :
-headers "Authorization : Bearer bas64user:password" , before specifying the -i "concat :...".

  


  It seems to me... that the headers don't pass to the concat command inside of the input of ffmpeg... and it simply ignores them. When I used the same -headers command, on a single file, without concat, it passed the authorization successfully

  


  Notes :

  


  

  • Even though every segment has a length of 120 frames (So in maximum, I could have generated 2*120 = 240 frames... I wanted a movie of 6 seconds and not 8... And by this way, to test that ffmpeg is smart enough to stop processing the whole input). To do that, I used -vframes 180, where 180 / 30 (FPS) = 6 seconds

  


  • I used -c:v copy, to get without re-encoding, only the video part (No audio !)

  


  • I used -y to override existing file...

  


  • 0.m4v, is the init file ! it is a small file, that has metadata of the original video which was produced with mpeg-dash

  


  • 1.m4v and 2.m4v, are the progressive segments

  


  


  Is there a way, to pass the http basic headers (Authorization : Bearer) to all of the chained files ?

  


  Like :

  


  

  • Via a json content type on the ffmpeg request

  


  • Or user:password@video_segment (Although... it seems to me it's not a header ?)

  


  • Somehow specify header inside the concat command ?

  


  


  I don't want to first download all files and then get rid of the password protected... as it both takes ridiculous time & other resources... and I would like to record from a segment that is "endless", meaning a camera that keeps streaming data.

  


  Thanks in advance 🙏🏻,

  


  FFmpeg noobie 🙈

  


• Basic to use FFMPEG in Python (Django Rest Framework)

  31 juillet 2018, par Feed Git

  I’m writing a viewset in Django Rest Framework to convert images sequence into video by using FFMPEG but I don’t understand how I can do it. I tried but not success. Please help me with my code.

  My code :

  class VideoRenderSerializer(ModelSerializer):
  
      imageSequence = ListField(required=False, child=FileField(max_length=100000, allow_empty_file=False, use_url=False))
  
      class Meta:
  
          model = Video
  
          fields = [
  
              'imageSequence',
  
          ]
  
  
  
  class VideoRenderView(ModelViewSet):
  
      queryset = Video.objects.all()
  
      serializer_class = VideoRenderSerializer
  
  
  
      def render_video(self, request):
  
          imgSequences = request.FILES.getlist('imageSequence')
  
          render_from_img_sequences_cmd = 'ffmpeg -loop 1 -i image.png -vf format=yuv420p -t 30 C:\output.mp4'
  
          ffmpegresult = subprocess.call(render_from_img_sequences_cmd, shell=True, stdout=open(os.devnull, "w"), stderr=subprocess.STDOUT)
  
          return Response(ffmpegresult, status=200)

  Output is : 1 and I cant find where is output file !

• ffmpeg php video basic uses and types [theoritical]

  15 mai 2014, par HackerManiac

  Can anyone give a code on how do i covert a video using ffmpeg.

  As thought currently i have only uploading system.

  vu.php(only a part is shown)

  define('UPLOAD','../../videos/');
  
      $fileName = time().$file['name']; 
  
      $target = UPLOAD.$fileName;
  
  
  
    if(move_uploaded_file($file['tmp_name'],$target)){                
  
        exec("ffmpeg -i ".UPLOAD." ".UPLOAD.$filename.".flv"); 
  
    }

  This pice of code block just uploads the video on video folder but does not converts it to .flv.
  I am not sure how to use ffmpeg.

  My diretory looks like this

  www[localhost]->videos[videos folder]
  
  www[localhost]->pictures[pictures folder]
  
  www[localhost]->resources[folder]->php[folder]->vu.php

  I also want to return a .jpg image of any frame of video through json by converting via ffmpeg and uploading it to pictures folder.

  return json_encode(array("thumbnail"=>$image_src));

  UPDATE 1

  The above stuff was solved but now i have a question regarding video conversion.
  Suppose i have a file.avi and i want to convert it in 3 sizes of .flv format -> Low(320p) ,Medium (720p)and HD(1080p)

  what commands will i have to send to shell_exec(); and will that be fast enough ?
  CUrrently what i have is

  $vidSize = "640x480";
  
  $ffmpeg -i $videoFile -ar 22050 -ab 32 -f flv -s $vidSize $vidFile

  And i am not sure what -ar and -ab means and what value will be good for all those 3 sized videos ?