Recherche avancée

Sur d’autres sites (1549)

• What should be the timing to capture screenshots as images and then convert the images to video file using ffmpeg ?

  22 juillet 2016, par TheLost Lostit

  I have a timer tick event where i take screenshots every 10ms

          int count = 0;
  
          private void timer1_Tick(object sender, EventArgs e)
  
          {
  
              Bitmap bmp = new Bitmap(sc.CaptureScreen());
  
              bmp.Save(@"D:\SavedScreenshots\screenshot" + count + ".bmp", System.Drawing.Imaging.ImageFormat.Bmp);
  
              bmp.Dispose();
  
              count ++;
  
          }

  Then i i’m using ffmpeg command line in command prompt window to create a video file from all the images :

  ffmpeg -framerate 2 -i screenshot%d.bmp -c:v libx264 -r 30  -pix_fmt yuv420p out.mp4

  Every bitmap file on hard disk it’s size is 7.91 MB
  The details : 1920x 1080 and Bit depth 32

  The problem is when making the ffmpeg command line with -framerate 2 then when i play the video file in windows media player it’s very very slow.
  When i saet the framerate to 10 then it’s too fast.
  When i set the framerate to 4 i’m getting error in yellow say too large.

  But maybe the problem is that i’m taking a screenshot every 10ms ? Maybe i should take a screenshot every 1000ms ? And then what should i change in the ffmpeg command line ?

  I want it to be like a regular video file speed. Not too fast and not too slow.
  What i’m capturing in the screenshot is my desktop screen and later i want to upload and show it to some support help in a forum.

• Capturing FFmpeg Progress with Progress Bar in C#

  24 juillet 2023, par sadra hoseini

  I'm working on a C# application where I'm using FFmpeg to encode multiple video files. I want to display a progress bar to show the encoding progress for each video. I have tried using the Process.OutputDataReceived event to capture FFmpeg's progress updates, but it doesn't seem to work reliably.

  


  Here's the relevant part of my code :

  


  // Code snippet
int i = 1;
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
    progressBar1.Maximum = openFileDialog1.FileNames.Length;

    foreach (string file in openFileDialog1.FileNames)
    {
        // Output file naming code here

        Process process = new Process();
        process.StartInfo.FileName = "ffmpeg.exe";
        process.StartInfo.CreateNoWindow = true;
        process.StartInfo.RedirectStandardError = true;
        process.StartInfo.UseShellExecute = false;

        process.OutputDataReceived += (sender, e) =>
        {
            // Progress parsing code here
            // This part doesn't seem to receive any data
        };

        process.Start();
        process.BeginOutputReadLine();
        process.WaitForExit();

        i++;
    }
}


  


  However, the OutputDataReceived event doesn't seem to receive any data from FFmpeg's stderr, and the progress bar doesn't update as expected.

  


  Is there a better way to capture FFmpeg's progress updates for encoding videos and use them to update the progress bar in C# ? How can I achieve this ?

  


  Any help or suggestions would be greatly appreciated. Thank you !

  


• Discord bot : Fix ‘FFMPEG not found’

  14 mars, par Travis Sova

  I want to make my Discord bot join voice chat, but every time I run the command, I get an error message in the log(cmd) saying, FFMPEG not found.

  


  Picture of the error :

  


  

  


  This is the code :

  


  client.on('message', message => {
  // Voice only works in guilds, if the message does not come from a guild,
  // we ignore it
  if (!message.guild) return;

  if (message.content === '/join') {
    // Only try to join the sender's voice channel if they are in one themselves
    if (message.member.voiceChannel) {
      message.member.voiceChannel.join()
        .then(connection => { // Connection is an instance of VoiceConnection
          message.reply('I have successfully connected to the channel!');
        })
        .catch(console.log);
    } else {
      message.reply('You need to join a voice channel first!');
    }
  }
});


  


  this is my package.json file :

  


  {
  "name": "x",
  "version": "1.0.0",
  "main": "index.js",
  "scripts": {
    "start": "node index.js",
    "dev": "nodemon index.js"
  },
  "dependencies": {
    "discord.js": "^11.4.2",
    "dotenv": "^6.2.0",
    "ffmpeg": "0.0.4",
    "opusscript": "0.0.6"
  },
  "devDependencies": {
    "nodemon": "^1.18.9"
  }
}