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Autres articles (62)

  • Utilisation et configuration du script

    19 janvier 2011, par

    Informations spécifiques à la distribution Debian
    Si vous utilisez cette distribution, vous devrez activer les dépôts "debian-multimedia" comme expliqué ici :
    Depuis la version 0.3.1 du script, le dépôt peut être automatiquement activé à la suite d’une question.
    Récupération du script
    Le script d’installation peut être récupéré de deux manières différentes.
    Via svn en utilisant la commande pour récupérer le code source à jour :
    svn co (...)

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    1er décembre 2010, par

    La gestion de la ferme passe par l’exécution à intervalle régulier de plusieurs tâches répétitives dites Cron.
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    Cette tâche, planifiée chaque minute, a pour simple effet d’appeler le Cron de l’ensemble des instances de la mutualisation régulièrement. Couplée avec un Cron système sur le site central de la mutualisation, cela permet de simplement générer des visites régulières sur les différents sites et éviter que les tâches des sites peu visités soient trop (...)

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Sur d’autres sites (4170)

  • RTSP Streaming on HTML page [on hold]

    20 décembre 2018, par Sajal Gupta

    I’m streaming from my IP Camera via RTSP protocol and able to watch live stream on VLC Player but I want to receive this stream in Java Code and save it into a file and also stream it on HTML page simultaneously. I tried using multiple plugins which are either unable to transcode or read RTSP URL. I also tried to read this stream via inputStream but getting null from it. I also tried websocket to listen to this stream but websocket is also returning null. I’m able to create file using ffmpeg from terminal but I want to do this through Java Code. I used vlcj library in java but it is also returning a deadlock error. Streamedian is paid and VXG Media Player is stuck on loader forever.
    Is there a way to stream and save RSTP stream simultaneously via Java/Grails code ?

  • Download from YouTube as ".wav" instead of ".webm"

    11 août 2022, par Bastian Gerjol

    I am trying to extract an audio from a YouTube Video as an .wav file.
However, the script that I am running keeps giving me .webm files.
The code I am using is the following :

    


    from __future__ import unicode_literals
import youtube_dl

ydl_opts = {
    'format': 'bestaudio/best',
    'postprocessors': [{
        'key': 'FFmpegExtractAudio',
        'preferredcodec': 'wav',
        'preferredquality': '192'
    }],
    'postprocessor_args': [
        '-ar', '16000'
    ],
    'prefer_ffmpeg': True,
    'keepvideo': True
}

with youtube_dl.YoutubeDL(ydl_opts) as ydl:
    ydl.download(['https://www.youtube.com/watch?v=2Xq7iJKzhR4'])


    


    Is there a way to change the output and keep the highest possible audio quality ?

    


    I tried setting prefer_ffmpeg': True to False & keepvideo': True to False but that did not change anything.

    


    I would appreciate suggestions and please keep in mind that I never used Python before.

    


  • YouTube's HD Video Streaming Server Technology ?

    30 septembre 2013, par bgentry

    Lately I've been researching different methods for streaming MP4s to the browser. Flash Media Server is an obvious choice here (using Cloudfront), and most solutions I've seen use the RTMP protocol.

    However, I spent some time on YouTube with Firebug and Chrome debugger figuring out how their streaming worked and I discovered some interesting differences between some of their videos and quality rates.

    My two sample videos are A and B. A is available up to 480p and B is available up to 1080p. For both videos, all rates up to 480p are served in an FLV container with H.264 video and AAC audio, over HTTP. What's interesting here is that if you have not yet downloaded (cached) the entire video, and you try to skip forward to an uncached part of the video, a new request will be made with a 'begin' parameter equal to the target offset in milliseconds. Example from Video A at 480p :

    http://v11.lscache8.c.youtube.com/videoplayback?ip=0.0.0.0&sparams=id%2Cexpire%2Cip%2Cipbits%2Citag%2Calgorithm%2Cburst%2Cfactor%2Coc%3AU0dWTldQVF9FSkNNNl9PSlhJ&fexp=904806%2C902906%2C903711&algorithm=throttle-factor&itag=35&ipbits=0&burst=40&sver=3&expire=1279756800&key=yt1&signature=D2D704D63C242CF187CAA5B5D5BAFB8DFACAC5FF.39180C01559C976717B651A7EB1D0C6249231EB7&factor=1.25&id=8568eb3135971f6f&begin=111863

    Response Headers:
    Cache-Control:public,max-age=23472
    Connection:close
    Content-Length:14320637
    Content-Type:video/x-flv
    Date:Wed, 21 Jul 2010 17:23:48 GMT
    Expires:Wed, 21 Jul 2010 23:55:00 GMT
    Last-Modified:Wed, 19 May 2010 12:31:41 GMT
    Server:gvs 1.0
    X-Content-Type-Options:nosniff

    The file returned by this URL is a fully valid FLV containing only the portion of the video after the requested offset.

    I did the same kind of test on the higher resolution versions of Video B. At 720p and 1080p, YouTube will return a video in an MP4 container, also with H.264 video and AAC audio. What's impressive to me is that their server takes the same type of offset for an MP4 video (via the 'begin' parameter) and returns a valid, streamable MP4 (moov atom at the front of the file with correct offsets) that also only includes the requested portion of the video.

    So, how does YouTube do this ? How do they generate the FLV or MP4 container on the fly with the correct headers and only the desired segment of the requested video ? I know this can be accomplished using FFMPEG to seek to the desired start point and the qt-faststart script to reposition the moov atom to the front of the stream, but it seems like this would be too slow to handle on-demand for millions of YouTube viewers.

    Ideas ?

    Thanks in advance !

    Footnote : I am not allowed to include more than 1 link at this point, so here is Video A's URL : http:// www.youtube .com/watch ?v=hWjrMTWXH28 "Video available up to 480p"