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• I have installed FFMPEG and can't find it inside a PHP script

  14 novembre 2019, par Antop

  I have installed FFMPeg in CentOS. It works perfectly.
  It’s inside /usr/bin directory. Also, I have PHP 7.2.24 that comes with Plesk 18.0.20.

  I want to use FFMPeg inside a PHP script, but that script can’t find the executable of FFMpeg. I have tried giving the exact route (/usr/bin/ffmpeg) but doesn’t work.

  It’s a production server. The same script, in my development server (macOS) works perfectly.

  I tried using :

  var_dump(getenv('PATH'));
  
  var_dump(exec('which ffmpeg'));
  
  var_dump(ini_get('open_basedir'));
  
  var_dump(is_file(exec('which ffmpeg')));
  
  var_dump(is_executable(exec('which ffmpeg')));

  And it returns me :

  string(49) "/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin"
  
  string(0) ""
  
  string(44) "/var/www/vhosts/name-of-the-domain.com/:/tmp/"
  
  bool(false)
  
  bool(false)
  
  NULL

  ¿What could be happening ?

  A very strange thing I’ve noticed is that I can’t access any command via php :
  I tried using it with echo

  var_dump(exec('which echo'));
  
  var_dump(is_file(exec('which echo')));
  
  var_dump(is_executable(exec('which echo')));

  And it returns me :

  string(0) ""
  
  bool(false)
  
  bool(false)
  
  NULL

  And the permissions are right :

  [root@vps bin]# ls -lha echo
  
  -rwxr-xr-x 1 root root 33K ago 20 08:25 echo
  
  
  
  [root@vps bin]# ls -lha ffmpeg
  
  -rwxr-xr-x 1 root root 217K abr  4  2019 ffmpeg

  But if I make a

  var_dump(exec('echo "HELLO"'))

  it returns me

  string(5) "HELLO"

• How can I pass a variable containing spaces as an argument in a bash script ?

  8 décembre 2017, par Bill D

  I am trying to pass a variable containing a filename with spaces as an argument to ffmpeg in a bash script, and I am not having success.

  varToPass="file name with spaces.mp4"
  
  
  
  ffmpeg -i "$varToPass" -ss "${array[j]}" -t "${anotherArray[j]}" output.mp4

  I have tried passing the argument as "$varToPass" with double quotes as suggested by this answer and others, but I’m still unable to get it to work.

  I’ve also tried putting escape characters in the string like this :

  varToPass=`echo $varToPass | sed 's/ /\ /'`

  But still no luck.

  Any suggestions for how this can be done ?

• ffmpeg shell script globbing

  10 novembre 2015, par AD0AE

  I have a pretty straight forward question. I have a bunch of individual directories that are labeled as ./001 ./002 ... ./201
  within each directory contains files that have the identifier *_IO.PNG

  I can use the shell command : ffmpeg -framerate 20 -pattern_type glob -i './066/*IO.PNG' -c:v libx264 -pix_fmt yuv420p 066.mp4 and this works great. It does exactly what I want.

  However, I tried to write a shell script, which is below but this does not work. It seems to be loading individual files instead of all of them at once. Any help would be appreciated.

   #!/bin/bash
  
   for i in {1..5}
  
   do
  
     FILE=$(printf %03d $i)
  
     echo " This file: $FILE"
  
     infile='./$FILE/*IO.PNG'
  
     echo $infile
  
     ffmpeg -framerate 20 -pattern_type glob -i $infile -c:v libx264 -pix_fmt yuv420p './$FILE.mp4'
  
   done