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• Concat audio files then call create file

  11 mai 2020, par bleepbloopbleep

  I am new and am trying to concat a folder of audio files and then stream the create file with ffmpeg in node.js.

  



  I thought I could call the function that creates the file with await and then when it's done the code would continue allowing me to call the created file. However thats not whats happening. I am getting a "file undefined"

  



  Main function

  



  //CONCATS THE FILES
  await concatAudio(supportedFileTypes.supportedAudioTypes, `${path}${config[typeKey].audio_directory}`);

  // CALLS THE FILE CREATED FROM concatAudio
  const randomSong = await getRandomFileWithExtensionFromPath(
    supportedFileTypes.supportedAudioTypes,
    `${path}${config[typeKey].audio_final}`
  );


  



  concatAudio function

  



  var audioconcat = require('audioconcat');
const getRandomFileWithExtensionFromPath = require('./randomFile');
const find = require('find');

// Async Function to get a random file from a path
module.exports = async (extensions, path) => {
  // Find al of our files with the extensions
  let allFiles = [];

  extensions.forEach(extension => {
    allFiles = [...allFiles, ...find.fileSync(extension, path)];
  });

  await audioconcat(allFiles)
    .concat('./live-stream-radio/final/all.mp3')
    .on('start', function(command) {
      console.log('ffmpeg process started:', command);
    })
    .on('error', function(err, stdout, stderr) {
      console.error('Error:', err);
      console.error('ffmpeg stderr:', stderr);
    })
    .on('end', function(output) {
      console.error('Audio created in:', output);
    });

  // Return a random file

  // return '/Users/Semmes/Downloads/live-stream-radio-ffmpeg-builds/live-stream-radio/final/all.mp3';
};


  


• Smartly concatenating gopro mp4 files - file-001.mp4 + file-002.mp4

  12 décembre 2017, par molly78

  Hello much smarter than me people out there...

  I have a folder of GoPro files which I have already renamed using this awesome utility : https://github.com/kcha/gopro_renamer

  However, I now have a folder of 110 files which should make up about 50 continuous videos...

  Some of which have only filename-001.mp4 parts, some are filename-001.mp4 and filename-002.mp4 parts. It could go on an on to say 10 parts per video, for argument sake.

  I’d like to get a hand with a script that would scan the folder and then join all the parts together into a new file.

  In windows 10 I know I can do a simple

  copy /b "C:\Filename-001.mp4" + "C:\Filename-002.mp4" Filename.mp4

  Just a bit lost how to loop thru this scenario with a (python is fine) script. I do not wish to re-encode them, simply join the parts that correspond to the base filename.

  So go from files looking like

  filename1-001.mp4 - 87 MB
  
  filename2-001.mp4 - 100 MB
  
  filename2-002.mp4 - 100 MB
  
  filename2-003.mp4 - 22 MB
  
  filename3-001.mp4 - 100 MB
  
  filename3-002.mp4 - 34 MB

  after concatenating the parts it would look like :

  filename1.mp4 - 87 MB (nothing done other than rename)
  
  filename2.mp4 - 222 MB (all joined)
  
  filename3.mp4 - 134 MB (all joined)

  Your help is greatly appreciated.

• Parsing file-like object into create_ffmpeg_player in discord.py not working

  3 août 2018, par user4757174

  The API documentation for create_ffmpeg_player says it allows passing file-like objects into create_ffmpeg_player as it will be passed to stdin.

  create_ffmpeg_player(filename, *, use_avconv=False, pipe=False, stderr=None, options=None, before_options=None, headers=None, after=None)

  filename – The filename that ffmpeg will take and convert to PCM bytes. If pipe is True then this is a file-like object that is passed to the stdin of ffmpeg

  here’s what I am inputting :

  buffer = BytesIO()
  
  c.setopt(c.WRITEDATA, buffer)
  
  c.perform()
  
  player = voice.create_ffmpeg_player(buffer,pipe=True)

  The PycURL object writes data to buffer which is the BytesIO object.

  Then I try to parse the file-like object into create_ffmpeg_player() but I get the following error :

      Traceback (most recent call last):
  
    File "C:\Users\user\AppData\Local\Programs\Python\Python36\lib\site-packages\discord\client.py", line 307, in _run_event
  
      yield from getattr(self, event)(*args, **kwargs)
  
    File "test.py", line 116, in on_message
  
      player = voice.create_ffmpeg_player(buffer,pipe=True)
  
    File "C:\Users\user\AppData\Local\Programs\Python\Python36\lib\site-packages\discord\voice_client.py", line 431, in create_ffmpeg_player
  
      p = subprocess.Popen(args, stdin=stdin, stdout=subprocess.PIPE, stderr=stderr)
  
    File "C:\Users\user\AppData\Local\Programs\Python\Python36\lib\subprocess.py", line 667, in __init__
  
      errread, errwrite) = self._get_handles(stdin, stdout, stderr)
  
    File "C:\Users\user\AppData\Local\Programs\Python\Python36\lib\subprocess.py", line 904, in _get_handles
  
      p2cread = msvcrt.get_osfhandle(stdin.fileno())
  
  io.UnsupportedOperation: fileno

  The error shows me that somewhere in the stack, a routine is trying to get the fileno() of the object, but since this is not a real file, there is no file handle, or "fileno". For a temporary work-around I am creating a physical file on disk and parsing that file into the function, but for this program, the function will be run many times so doing physical read/writes is not practical. Is it possible to work around this, or at least create a file on memory with the ability to get/spoof a fileno ?