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• No Implementation Found for init method in Youtube Live Streaming Watch me project

  17 mai 2017, par Basha

  I am new to android development.presently I am Working on Youtube Live Streaming and downloaded watchMe project.I am getting the error in my class where I used to load FFMPEG libffmpeg.so file and the error was cannot resolve "init" method. and getting error while running the application as below

  java.lang.UnsatisfiedLinkError: No implementation found for boolean com.google.sai.apps.watchme.Ffmpeg.init(int, int, int, java.lang.String) (tried Java_com_google_sai_apps_watchme_Ffmpeg_init and Java_com_google_sai_apps_watchme_Ffmpeg_init__IIILjava_lang_String_2)
  
                                                                                       at com.google.sai.apps.watchme.Ffmpeg.init(Native Method)
  
                                                                                       at com.google.sai.apps.watchme.VideoStreamingConnection.open(VideoStreamingConnection.java:71)
  
                                                                                       at com.google.sai.apps.watchme.StreamerService.startStreaming(StreamerService.java:73)
  
                                                                                       at com.google.sai.apps.watchme.StreamerActivity.startStreaming(StreamerActivity.java:163)
  
                                                                                       at com.google.sai.apps.watchme.StreamerActivity.access$200(StreamerActivity.java:39)
  
                                                                                       at com.google.sai.apps.watchme.StreamerActivity$1.onServiceConnected(StreamerActivity.java:55)
  
                                                                                       at android.app.LoadedApk$ServiceDispatcher.doConnected(LoadedApk.java:1223)
  
                                                                                       at android.app.LoadedApk$ServiceDispatcher$RunConnection.run(LoadedApk.java:1240)
  
                                                                                       at android.os.Handler.handleCallback(Handler.java:739)
  
                                                                                       at android.os.Handler.dispatchMessage(Handler.java:95)
  
                                                                                       at android.os.Looper.loop(Looper.java:148)
  
                                                                                       at android.app.ActivityThread.main(ActivityThread.java:5438)
  
                                                                                       at java.lang.reflect.Method.invoke(Native Method)
  
                                                                                       at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:762)
  
                                                                                       at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:652)
  
      05-17 11:31:41.415 23434-25678/com.google.sai.apps.watchme E/ImageFetcher: Error in downloadBitmap - java.io.FileNotFoundException: https://i.ytimg.com/vi/FFvfpXcOpYk/default_live.jpg

  and FFMPEG class was

  public class Ffmpeg {
  
  
  
  
  
      static {
  
          System.loadLibrary("ffmpeg");
  
      }
  
  
  
  
  
      public static native boolean init(int width, int height, int audio_sample_rate, String rtmpUrl);
  
  
  
      public static native void shutdown();
  
  
  
      // Returns the size of the encoded frame.
  
      public static native int encodeVideoFrame(byte[] yuv_image);
  
  
  
      public static native int encodeAudioFrame(short[] audio_data, int length);
  
  }

  please someone help me.

• I ues FFMPEG to convert bitmap to yuv,and try to save it,but failed

  20 avril 2013, par liaoyuandeyehuo

  I use this way to convert bitmap to yuv
  Save bitmap to video (libavcodec ffmpeg)
  and then save the buffer like this :

  FILE* fp=fopen("aha.yuv","w");
  
  if(!fp) return NULL;
  
  fwrite(outPic->data[0],nbytes,1,fp);
  
  fwrite(outBuffer,nbytes,1,fp);
  
  fclose(fp);

  but it has only several lines. All most all of the .yuv file is gray.
  I am sure the inbuffer points to the input BGR32 data. So where is wrong ?
  Is The way to save the outBuffer right ?

• Passing commands with double quotes to subprocess.call in python

  7 juin 2018, par Georgе Stoyanov

  I want to pass a command to a Linux machine running ffmpeg using python containing a double quotes. That’s my script :

  drawtext = "drawtext=\"fontfile=DejaVuSans: text='Random Name': fontcolor=white: fontsize=24: box=1: boxcolor=black@0.5: boxborderw=5: x=20: y=20\""
  
  subprocess.call(["ffmpeg", "-v", "error", "-i", input.mp4, "-vf", drawtext, output.mp4])

  If I print the drawtext variable this is the output :

  drawtext="fontfile=DejaVuSans: text='Reference Image': fontcolor=white: fontsize=24: box=1: boxcolor=black@0.5: boxborderw=5: x=20: y=20"

  And this is my error in ffmpeg :

  [Parsed_drawtext_0 @ 0x564ad79f99c0] [Eval @ 0x7ffd41131810] Invalid chars '"' at the end of expression '20"'
  
  [Parsed_drawtext_0 @ 0x564ad79f99c0] Failed to configure input pad on Parsed_drawtext_0
  
  Error reinitializing filters!
  
  Failed to inject frame into filter network: Invalid argument
  
  Error while processing the decoded data for stream #0:0

  If I execute the following command in Linux shell it works just fine :

  $ ffmpeg -ss 10 -i input.mp4 -vf drawtext="fontfile=DejaVuSans: text='Random Name': fontcolor=white: fontsize=24: box=1: boxcolor=black@0.5: boxborderw=5: x=20: y=20" output.mp4