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Autres articles (58)
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Les autorisations surchargées par les plugins
27 avril 2010, parMediaspip core
autoriser_auteur_modifier() afin que les visiteurs soient capables de modifier leurs informations sur la page d’auteurs -
Publier sur MédiaSpip
13 juin 2013Puis-je poster des contenus à partir d’une tablette Ipad ?
Oui, si votre Médiaspip installé est à la version 0.2 ou supérieure. Contacter au besoin l’administrateur de votre MédiaSpip pour le savoir -
HTML5 audio and video support
13 avril 2011, parMediaSPIP uses HTML5 video and audio tags to play multimedia files, taking advantage of the latest W3C innovations supported by modern browsers.
The MediaSPIP player used has been created specifically for MediaSPIP and can be easily adapted to fit in with a specific theme.
For older browsers the Flowplayer flash fallback is used.
MediaSPIP allows for media playback on major mobile platforms with the above (...)
Sur d’autres sites (10846)
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Updated version number.
1er septembre 2011, par Sebastian Tschanm jquery.fileupload-ui.js Updated version number.
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ffmpeg - extract exact number of frames from video
29 mars 2017, par Michael BI want to create a maximum of 30 images from a video (and tile them for a sprite sheet).
I’ve tried using the ’select’ with ’mod’ but if the total number of frames does not fit neatly into the desired number of images (30) then I sometimes end up with more images, sometimes less.
For example if my video is 72 frames long, my ’mod’ would be 72 / 30, which is 2.4.
I’m running this from a python script so i’m doing something like the following for the filter :
select='not(mod(n\," + str(mod) + "))'
I think the mod has to be an integer (?) so I could either round down and use 2 which gives me 36 images or round up which gives me 24 images
Whats the best way to get exactly 30 ? - obviously the interval wouldn’t be identical but thats fine.
Maybe I could use a for loop to generate a list of the frames closest to the desired interval and then pass that in as the select filter ?
e.g. to get the frames I would do something like this :
nframes = 72 # number of frames in video
outImages = 30 # number of images I want
mod = float(nframes) / outImages # 2.4
frames = []
idx = 1
while i < nframes:
print str(idx) + ": " + str(math.floor(i+0.5))
frames.append(int(math.floor(i+0.5)))
idx += 1
i += modThen am I able to pass that (the frames list) into the ffmpeg command ? Or can I tell ffmpeg to do something similar ?
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Round number of bits read to next byte
4 décembre 2014, par watwat2014I have a header that can be any number of bits, and there is a variable called ByteAlign that’s calculated by subtracting the current file position from the file position at the beginning of the file, the point of this variable is to pad the header to the next complete byte. so if the header is taking up 57 bits, the ByteAlign variable needs to be 7 bits in length to pad the header to 64 bits total, or 8 bytes.
Solutions that don’t work :
Variable % 8 - 8, the result is the answer, but negative.
8 % Variable ; this is completely inaccurate, and gives answers like 29, which is blatantly wrong, the largest number it should be is 7.
how exactly do I do this ?