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The pirate bay depuis la Belgique
1er avril 2013, par
Mis à jour : Avril 2013
Langue : français
Type : Image
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Menus personnalisés
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Sur d’autres sites (5866)
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FFmpeg : canvas and crop work separately but result in black screen when combined
25 janvier, par didi00I'm working on a video processing pipeline with FFmpeg, where I :


- 

- Create a black canvas using the color filter.
- Crop a region from my video input.
- Overlay the cropped region onto the black canvas.








Both the canvas and the crop display correctly when tested individually. However, when I attempt to combine them (overlay the crop onto the canvas), the result is a black screen.
What Works :


Black Canvas Alone :


ffmpeg -filter_complex "color=c=black:s=1920x1080[out]" -map "[out]" -f nut - | ffplay 
-


This shows a plain black screen, as expected.


Cropped Region Alone :


ffmpeg -f v4l2 -input_format yuyv422 -framerate 60 -video_size 1920x1080 -i /dev/video0 
\ -vf "crop=1024:192:0:0" -f nut - | ffplay -


This shows the cropped region of the video correctly.


When I combine these steps to overlay the crop onto the black canvas, I get a black screen :


ffmpeg -f v4l2 -input_format yuyv422 -framerate 60 -video_size 1920x1080 -i /dev/video0 
\-filter_complex "color=c=black:s=1920x1080,format=yuv420p[background]; \
[0:v]crop=1024:192:0:0,format=yuv420p[region0]; \
[background][region0]overlay=x=0:y=0[out]" \
-map "[out]" -f nut - | ffplay -


Environment :


- 

- OS : Linux (Debian-based)
- FFmpeg Version : [Insert version, e.g., 4.x or 5.x]
- Capture Card Format : yuyv422








Question :


Why does the pipeline result in a black screen when combining the canvas and the crop, even though both work separately ? Is this an issue with pixel format compatibility, or is there something I'm overlooking in the overlay filter setup ?


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How to Show result after uploaded file in PHP
23 avril 2022, par i0x4rI have a script that uploads the video to a server, everything is correct but there is a problem, after the upload of the video to the server is completed
it shows all the uploaded files in the (uploads) folder as array !


I only want the result of the file I just uploaded, and it doesn't show me the previous files !
I need ffmpeg to improve video quality


index.php


<?php
//index.php

?>


 
 
 
 <code class="echappe-js"><script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.0/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js"></script>
 
<script src="https://cdnjs.cloudflare.com/ajax/libs/dropzone/5.5.1/dropzone.js"></script>
 
 
 



 
 
 








 



<script>&#xA;&#xA;$(document).ready(function(){&#xA; &#xA; Dropzone.options.dropzoneFrom = {&#xA; autoProcessQueue: true,&#xA; timeout: 300000,&#xA; acceptedFiles:"video/*",&#xA; init: function(){&#xA; var submitButton = document.querySelector(&#x27;#submit-all&#x27;);&#xA; myDropzone = this;&#xA; submitButton.addEventListener("click", function(){&#xA; myDropzone.processQueue();&#xA; });&#xA; this.on("complete", function(){&#xA; if(this.getQueuedFiles().length == 0 &amp;&amp; this.getUploadingFiles().length == 0)&#xA; {&#xA; var _this = this;&#xA; _this.removeAllFiles();&#xA; }&#xA; list_image();&#xA; });&#xA; },&#xA; };&#xA;&#xA; list_image();&#xA;&#xA; function list_image()&#xA; {&#xA; $.ajax({&#xA; url:"upload.php",&#xA; success:function(data){&#xA; $("#preview").html(data);&#xA; }&#xA; });&#xA; }&#xA;&#xA; $(document).on(&#x27;click&#x27;, &#x27;.remove_image&#x27;, function(){&#xA; var name = $(this).attr(&#x27;id&#x27;);&#xA; $.ajax({&#xA; url:"upload.php",&#xA; method:"POST",&#xA; data:{name:name},&#xA; success:function(data)&#xA; {&#xA; list_image();&#xA; }&#xA; })&#xA; });&#xA; &#xA;});&#xA;</script>


upload.php


<?php

//upload.php

$folder_name = 'upload/';
$tumb_name = 'thumb/';
$imageext = '.png';

if(!empty($_FILES))
{

 $temp_file = $_FILES['file']['tmp_name'];
 $location = $folder_name . $_FILES['file']['name'];
 move_uploaded_file($temp_file, $location);
 $upload = $_FILES['file']['name'];
 $uploadStr = str_replace(" ", "\ ",$upload);
 $locationStr = str_replace(" ","\ ",$location);
 $cmd = "ffmpeg -y -i {$locationStr} -ss 00:00:15 -vframes 1 thumb/{$uploadStr}.png 2>&1";
 echo shell_exec($cmd);
}

if(isset($_POST["name"]))
{
 $filename = $folder_name.$_POST["name"];
 $imagename = $thumb_name.$_POST["name"].$imageext;
 unlink($filename);
 unlink($imagename);
}

$result = array();

$files = scandir('upload');

$output = '<div class="row">';

if(false !== $files)
{
 foreach($files as $file)
 {
 if('.' != $file && '..' != $file)
 {
 $output .= '
 <a href="http://stackoverflow.com/view.php?file=&#x27;.$file.&#x27;" target="_blank"> <img src="http://stackoverflow.com/feeds/tag/thumb/&#x27;.$file.&#x27;.png" class="img-thumbnail" width='246' height='138' /></a>
 <button type="button" class="btn btn-link remove_image">Remove</button>
 ';
 }
 }
}
$output .= '</div>';
echo $output;

?>


EDIT :
I put the example on an Array, I don't want it, I just want it to show the downloaded video I just uploaded as a result.


EDIT 2 :
There are some who say type $location and it displays the downloaded file, but this does not work !!!
I just tried more than once and with several uses, there is no display where the text is empty


This is an example of that


<?php

//upload.php

$folder_name = 'upload/';
$tumb_name = 'thumb/';
$imageext = '.png';

if(!empty($_FILES))
{

 $temp_file = $_FILES['file']['tmp_name'];
 $location = $folder_name . $_FILES['file']['name'];
 move_uploaded_file($temp_file, $location);
 $upload = $_FILES['file']['name'];
 $uploadStr = str_replace(" ", "\ ",$upload);
 $locationStr = str_replace(" ","\ ",$location);
 $cmd = "ffmpeg -y -i {$locationStr} -ss 00:00:15 -vframes 1 thumb/{$uploadStr}.png 2>&1";
 echo shell_exec($cmd);
}

if(isset($_POST["name"]))
{
 $filename = $folder_name.$_POST["name"];
 $imagename = $thumb_name.$_POST["name"].$imageext;
 unlink($filename);
 unlink($imagename);
}


$output .= 'Successfly file is "'.$location.'"';
echo $output;

?>


Result : Successfly file is ""
no name file :(


EDIT 3 :


this code upload.php
functions not working


<?php

//upload.php

$folder_name = 'upload/';
$tumb_name = 'thumb/';
$imageext = '.png';

if(!empty($_FILES))
{

 $temp_file = $_FILES['file']['tmp_name'];
 $location = $folder_name . $_FILES['file']['name'];
 move_uploaded_file($temp_file, $location);
 $upload = $_FILES['file']['name'];
 $uploadStr = str_replace(" ", "\ ",$upload);
 $locationStr = str_replace(" ","\ ",$location);
 $cmd = "ffmpeg -y -i {$locationStr} -ss 00:00:15 -vframes 1 thumb/{$uploadStr}.png 2>&1";
 echo shell_exec($cmd);
}


echo "The file " . $location . " has been uploaded";
// not working
echo "<br />";
echo "The file " . $upload . " has been uploaded";
// not working
echo "<br />";
echo "The file " . $uploadStr . " has been uploaded";
// not working
echo "<br />";
echo "The file " . $locationStr . " has been uploaded";
// not working

?>




this error :
[23-Apr-2022 12:31:56 Asia/Riyadh] PHP Notice : Undefined variable : location in /home/prdix/public_html/test/upload.php on line 38


line 38 : echo $location ;


About the developer solution Markus AO


I did the experiment and it is quite good, but dropzone is still missing, because I will upload a large video and the normal upload compresses the video before uploading, here is a picture from my mobile while uploading, but this does not happen with dropzone



I want to implement this in dropzone as well, because this library does not compress the video, but upload it in full size.


Thank you bro.


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Why does this ffmpeg conversion result in variable bitrate ? [closed]
6 juin 2013, par TraceI have this command
ffmpeg -i test.mp3 -ac 1 -ab 64000 -ar 44100 output.mp3The requirements are
mp3 (mpeg-1 layer 3)
Bit rate: 64kbps CBR(constant Bit Rate)
Sampling rate: 44.1
Bit depth: 16bit
Channels: monoThe sample rate is correct, but file came through with a variable bit rate, not constant bit rate.
Any ideas what I'm missing here ?
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