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Médias (91)
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Richard Stallman et le logiciel libre
19 octobre 2011, par
Mis à jour : Mai 2013
Langue : français
Type : Texte
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Stereo master soundtrack
17 octobre 2011, par
Mis à jour : Octobre 2011
Langue : English
Type : Audio
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Elephants Dream - Cover of the soundtrack
17 octobre 2011, par
Mis à jour : Octobre 2011
Langue : English
Type : Image
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#7 Ambience
16 octobre 2011, par
Mis à jour : Juin 2015
Langue : English
Type : Audio
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#6 Teaser Music
16 octobre 2011, par
Mis à jour : Février 2013
Langue : English
Type : Audio
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#5 End Title
16 octobre 2011, par
Mis à jour : Février 2013
Langue : English
Type : Audio
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Sur d’autres sites (13072)
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Set path while installing [duplicate]
12 janvier 2021, par Education 4FunMy requirement is to set a path(C :/ffmpeg) while installing the software itself for my application(which I made)

A reference that it's possible(While installing python 3.8.0 we have check box by ticking it we can add the path of python automatically)

This is the main requirement which I wanna do with my application



About My application :

My application is a simple video editing application that runs on cmd as it uses FFmpeg its path should be set only then the application will work
The application is coded in python and the GUI is made using pyqt5 The application runs on cmd like the commands and all here is a reference image for observation enter image description here



So it's mandatory to add the path else FFmpeg will not recognize. If there is any way to do in building setup like how python can add the path as per user requirement refer to the image (1st image)


About Files in C :/ffmpeg
Files in FFmpeg folder refer to image for that info




Hope the query is a bit clear.
Thanks a lot


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How to make ffmpeg follow a variable file path [closed]
2 septembre 2023, par WessieI have a little Python script. What it should do is to take the last file out a folder and convert it to another with the same filename.


The Script :


from moviepy.editor import *
import glob
import os.path

#Variabels
folder_path = r'/pathtofolder/Recordings'
file_type = r'/*h264'
file_type_conv = r'/*mp4'
files = glob.glob(folder_path + file_type)
files_conv = glob.glob(folder_path + file_type_conv)
clip_latest = max(files, key=os.path.getctime)
clip_conv = max(files_conv, key=os.path.getctime)

#print(clip_latest)
#print(clip_conv)

ffmpeg -i clip_latest -r 25 clip_conv 



This gives me back :


SyntaxError: invalid syntax



When I 'print" the code it gives me the path I need. But I cannot get the path into the ffmpeg code.
What anm I doing wrong ?


Thanks in advance !


I tried to place the variables in "" and in {}.
When I give a full path it works good.


UPDATE :


Got it working ! Thaqnks to the advise of@Daviid I've used python-ffmpeg library.
Here's the code :


import glob
import os.path
import subprocess

#Variabels
folder_path = r'/home/wessie/Halloween/Recordings'
file_type = r'/*h264'
file_type_conv = r'/*mp4'
files = glob.glob(folder_path + file_type)
files_conv = glob.glob(folder_path + file_type_conv)
clip_latest = max(files, key=os.path.getctime)
clip_conv = clip_latest + '.mp4'

print(clip_latest)
print(clip_conv)

subprocess.run(['ffmpeg', '-i', clip_latest, clip_conv])




Thanks !


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ffmpeg library does not work from path but directly
19 juin 2020, par Ángel BarriosI want to add a watermark to a video.



I'm trying with windows 10 and ffmpeg library



The command I am using.



ffmpeg -i example.mp4 -i watermark.png -filter_complex "overlay=0-0+0:main_h-overlay_h-0+0" watermark.mp4




When I use it this way accesing the path I get this error :






But when I execute it not from path but opening cmd right on the executable folder it works fine



I did some research and couldn't find the answers I was looking for.



Why does this happen ? I can´t understand really



Thank you !