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Médias (29)

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Autres articles (109)

  • Support de tous types de médias

    10 avril 2011

    Contrairement à beaucoup de logiciels et autres plate-formes modernes de partage de documents, MediaSPIP a l’ambition de gérer un maximum de formats de documents différents qu’ils soient de type : images (png, gif, jpg, bmp et autres...) ; audio (MP3, Ogg, Wav et autres...) ; vidéo (Avi, MP4, Ogv, mpg, mov, wmv et autres...) ; contenu textuel, code ou autres (open office, microsoft office (tableur, présentation), web (html, css), LaTeX, Google Earth) (...)

  • Supporting all media types

    13 avril 2011, par

    Unlike most software and media-sharing platforms, MediaSPIP aims to manage as many different media types as possible. The following are just a few examples from an ever-expanding list of supported formats : images : png, gif, jpg, bmp and more audio : MP3, Ogg, Wav and more video : AVI, MP4, OGV, mpg, mov, wmv and more text, code and other data : OpenOffice, Microsoft Office (Word, PowerPoint, Excel), web (html, CSS), LaTeX, Google Earth and (...)

  • List of compatible distributions

    26 avril 2011, par

    The table below is the list of Linux distributions compatible with the automated installation script of MediaSPIP. Distribution nameVersion nameVersion number Debian Squeeze 6.x.x Debian Weezy 7.x.x Debian Jessie 8.x.x Ubuntu The Precise Pangolin 12.04 LTS Ubuntu The Trusty Tahr 14.04
    If you want to help us improve this list, you can provide us access to a machine whose distribution is not mentioned above or send the necessary fixes to add (...)

Sur d’autres sites (22814)

  • I want the mp4 file shooting date to be the xml file name

    21 novembre 2019, par re6

    In Windows 10 environment, I would like to change the name of both “file with extension mp4” and “file with extension xml” to the shooting date of mp4 file.

    C0001.MP4
    C0001M01.XML
    C0002.MP4
    C0002M01.XML

    Specifically, I want to change the file name as follows.

    2019-10-23_13-10-32.MP4
    2019-10-23_13-10-32.XML
    2019-10-23_13-10-49.MP4
    2019-10-23_13-10-49.XML

    I tried to think that using the ext option would give me the expected result, but I didn’t get the expected result.

    First time

    C:\Users\user>exiftool "-FileNamehoge/C0001M01.XML
    Warning: No writable tags set from C:/hoge/C0001M01.XML
    Warning: [minor] Error 3 placing ::NonRealTimeMetaAudioFormatAudioRecPortTrackDst in structure or list - C:/hoge/C0002M01.XML
    Warning: No writable tags set from C:/hoge/C0002M01.XML
       1 directories scanned
       0 image files updated
       2 image files unchanged

    Second time

    C:\Users\user>exiftool "-FileNamehoge/C0001.MP4
    Warning: [minor] Error 3 placing ::NonRealTimeMetaLtcChangeTableLtcChangeStatus in structure or list - C:/hoge/C0001M01.XML
    Warning: No writable tags set from C:/hoge/C0001M01.XML
    Warning: [minor] The ExtractEmbedded option may find more tags in the movie data - C:/hoge/C0002.MP4
    Warning: [minor] Error 3 placing ::NonRealTimeMetaAudioFormatAudioRecPortPort in structure or list - C:/hoge/C0002M01.XML
    Warning: No writable tags set from C:/hoge/C0002M01.XML
       1 directories scanned
       2 image files updated
       2 image files unchanged
  • How to run a command in python with file paths containing spaces ?

    24 juillet 2023, par tomatochan

    I'm developing a program in Python that requires the use of FFMPEG. In one step, I need to create a video from a text file containing the list of images (path and duration) that need to be assembled to make a video. To do this, I use the following code :

    


    cmd = [ffmpeg, "-y", "-f", "concat", "-safe", "0", "-i", tmp, "-c:v", "libx264", "-r", "25", "-pix_fmt", "yuv420p", out]
subprocess.run(cmd)
# os.system(" ".join(cmd)) # returns same error


    


    What returns the error : The syntax of the file, directory or volume name is incorrect.

    


    I know that paths can be problematic when they contain spaces, and as my username has one, I've taken care to quote the paths in such a way that :

    


    ffmpeg = '"C:\Users\John Doe\Documents\ffmpeg\bin\ffmpeg.exe"'
tmp = '"C:\Users\John Doe\Desktop\path\to\file.txt"'
out = '"C:\Users\John Doe\Desktop\path\to\video.mp4"'


    


    When I print(" ".join(cmd)), this is what I get in my terminal :

    


    "C:\Users\John Doe\Documentsffmpeg\binffmpeg.exe" -y -f concat -safe 0 -i "C:\Users\John Doe\Desktop\path\to\file.txt" -c:v libx264 -r 25 -pix_fmt yuv420p "C:\Users\John Doe\Desktop\path\to\video.mp4"


    


    However, the problem persists.
Has anyone ever had this problem and managed to solve it ?

    


    I've also tried the method where you have to escape the spaces (taking care to replace the \ with / and then the with \ ) but nothing works... The error persists.

    


    For your information, here are the contents of one of my .txt files

    


    file C:\Users\John Doe\Desktop\path\to\image_1.png
duration 0.04
file C:\Users\John Doe\Desktop\path\to\image_2.png
duration 0.04
file C:\Users\John Doe\Desktop\path\toimage_3.png
duration 0.04


    


    When I quote the paths in the .txt files

    


      

    • subprocess gives me the error :
PermissionError: [WinError 5] Access denied
    • 


    • os.system gives me the error :
    • 


    


    C:\Users\John' is not recognized as an internal or external command, an executable program or a command file.
The syntax of the file, directory or volume name is incorrect.


    


  • Revision 970eb39bdc : Cleaning up read_skip_coeff() function. Making code easier to read and avoiding

    31 octobre 2013, par Dmitry Kovalev

    Changed Paths :
     Modify /vp9/decoder/vp9_decodemv.c



    Cleaning up read_skip_coeff() function.

    Making code easier to read and avoiding calculation of skip context twice.

    Change-Id : I42c376b1a1811bc842bf6420bf81d2de7a1bf980