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• dxva : verbose-log decoder GUID list

  22 juin 2017, par wm4

  dxva : verbose-log decoder GUID list
  Helpful for debugging.
  Merges Libav commit 068eaa534e7ddb2155e2830818d5c3f1069c68d8.
  Signed-off-by : Luca Barbato <lu_zero@gentoo.org>
  

  • [DH] libavcodec/dxva2.c

• FFMPEG Concatenate X video at time from a list.txt

  25 octobre 2019, par Lorenzo Castagnone

  I’m trying to concatenate 3 videos at time from a list.txt, i can concatenate all the videos in the list in a single long video, but i wish to concatenate x videos from the list in a single output, then concatenate the next x videos from the same list in another single output and so on.

  The script i’m developing it’s written in python, it fetches some videos from a server and save them locally in a folder and write my concat.txt, then ffmpeg read the concat.txt and create a single output.mp4

  #this merge all video in concat file in a single output
  
  os.system("ffmpeg -f concat -i downloaded/concat.txt -safe 1 -r 30 -fflags +genpts -c:a copy downloaded/output.mp4")

  I’m looking for a way to make ffmpeg read the first x row from the concat.txt , concatenate them in output1.mp4, then read the next x row from cancat.txt , concatenate them in output2.mp4 and so on.

  Thank you for your time to help me, i really appreciate that !

  ---EDIT
  Thank to @Tejas for the reply, i solved how to split the concat.txt file, now i’m trying to apply a filter to every clip

  import os
  
  x = 3 #Number of files you want to concatenate
  
  
  
  #Making directories so that the working directory stays organized
  
  txtFileName = "./splits/output{}.txt"
  
  outputFile = "./clip/output{}.mp4"
  
  postFile = "./media/post{}.mp4"
  
  os.makedirs(os.path.dirname(txtFileName), exist_ok=True)
  
  os.makedirs(os.path.dirname(outputFile), exist_ok=True)
  
  os.makedirs(os.path.dirname(postFile), exist_ok=True)
  
  
  
  
  
  #While splitting the files store their path to a list
  
  listofSplitFiles = []
  
  with open('./downloaded/concat.txt','r') as concat:
  
      lines = concat.readlines()
  
      for i in range(0,lines.__len__()//x):
  
          with open(txtFileName.format(i+1),'w') as split:
  
              listofSplitFiles.append(txtFileName.format(i+1))
  
              for j in range(0,x):
  
                  if( (i*x)+j < lines.__len__() ):
  
                      split.write(lines[(i*x)+j])
  
  
  
  #Call ffmpeg on the list
  
  for i in listofSplitFiles:
  
      outputBaseName = os.path.basename(i)
  
      outputFileName = os.path.splitext(outputBaseName)[0]
  
      postFileName = os.path.splitext(outputBaseName)[0]
  
      os.system("ffmpeg -f concat -i {} -safe 1 -r 30 -fflags +genpts -c:a copy ./clip/{}.mp4".format(i,outputFileName))
  
      os.system('''ffmpeg -loglevel error -r 30 -i sfondo/bkg.png -i ./clip/output{}.mp4 -b:v 1M -filter_complex ''' + '''"[1:v]scale=''' + "750" + ''':''' + "1080" + ''' [ovrl], [0:v][ovrl]overlay=(main_w-overlay_w)/2:((main_h-overlay_h)/2)"''' + ''' ./media/{}.mp4''' .format(outputFileName,postFileName)) 

  Unfortunately i have this error ./clip/{}.mp4: No such file or directory

• Concat video from list.txt using ffmpeg library с++

  24 novembre 2019, par Orest

  I am new in ffmpeg. I use ffmpeg library in c++. I try concat video from list.txt. I find this https://github.com/FFmpeg/FFmpeg/tree/master/libavformat but I don’t know how to use it