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  • Les formats acceptés

    28 janvier 2010, par

    Les commandes suivantes permettent d’avoir des informations sur les formats et codecs gérés par l’installation local de ffmpeg :
    ffmpeg -codecs ffmpeg -formats
    Les format videos acceptés en entrée
    Cette liste est non exhaustive, elle met en exergue les principaux formats utilisés : h264 : H.264 / AVC / MPEG-4 AVC / MPEG-4 part 10 m4v : raw MPEG-4 video format flv : Flash Video (FLV) / Sorenson Spark / Sorenson H.263 Theora wmv :
    Les formats vidéos de sortie possibles
    Dans un premier temps on (...)

Sur d’autres sites (13869)

  • node ffmpeg programmatically built list(?) of commands

    16 mai 2022, par Martin

    I am working on a ffmpeg wasm project and I have it working with this code :

    


            await ffmpeg.run(
            '-loop', '1',
            '-framerate', '2',
            "-i", inputFileNames[0], 
            "-i", inputFileNames[1],
            "-i", inputFileNames[2],
            "-c:a", "libmp3lame", 
            "-b:a", "320k", 
            "-filter_complex", "concat=n=2:v=0:a=1",
            "-vcodec", "libx264", 
            "-bufsize", "3M", 
            "-filter:v", "scale=w=1920:h=1930,pad=ceil(iw/2)*2:ceil(ih/2)*2", 
            "-crf", "18", 
            "-pix_fmt", "yuv420p", 
            "-shortest", "", 
            "-tune", "stillimage", 
            "-t", "13", 
            outputFileName
        );


    


    https://github.com/MartinBarker/ffmpeg-wasm-node

    


    As you can see, the await ffmpeg.run() command takes a list of args / vars to run.
I have it statically set to take three file inputs right now (-i) but I need to have these inputs set dynamically for however many strings are inside the inputFileNames[] list.

    


    I've tried giving await ffmpeg.run(myListArgs) a var containing a list of the same args but that does not work but this causes an error as it only runs the last var outputFIlename so this below does not work :

    


            let ffmpegArgs=('-loop', '1',
        '-framerate', '2',
        "-i", inputFileNames[0], 
        "-i", inputFileNames[1],
        "-i", inputFileNames[2],
        "-c:a", "libmp3lame", 
        "-b:a", "320k", 
        "-filter_complex", "concat=n=2:v=0:a=1",
        "-vcodec", "libx264", 
        "-bufsize", "3M", 
        "-filter:v", "scale=w=1920:h=1930,pad=ceil(iw/2)*2:ceil(ih/2)*2", 
        "-crf", "18", 
        "-pix_fmt", "yuv420p", 
        "-shortest", "", 
        "-tune", "stillimage", 
        "-t", "13", 
        outputFileName)

        await ffmpeg.run(
            ffmpegArgs
        );


    


    I've tried to include multiple inputs in one line like so but it results in an error :

    


    
        await ffmpeg.run(
            '-loop', '1',
            '-framerate', '2',
            `-i ${inputFileNames[0]} -i ${inputFileNames[1]} -i ${inputFileNames[2]}`,
            "-c:a", "libmp3lame", 
            "-b:a", "320k", 
            "-filter_complex", "concat=n=2:v=0:a=1",
            "-vcodec", "libx264", 
            "-bufsize", "3M", 
            "-filter:v", "scale=w=1920:h=1930,pad=ceil(iw/2)*2:ceil(ih/2)*2", 
            "-crf", "18", 
            "-pix_fmt", "yuv420p", 
            "-shortest", "", 
            "-tune", "stillimage", 
            "-t", "13", 
            outputFileName
        );

[fferr] Unrecognized option 'i input-file-0 -i input-file-1 -i input-file-2'.
[fferr] Error splitting the argument list: Option not found
[ffout] FFMPEG_END


    


    I've tried having only the inputs as a list, and using the ... to expand it inside the function call but that causes an error as well as the commas are included in the command (which they shouldnt be)

    


            let ffmpegInputs=[
            "-i", inputFileNames[0], 
            "-i", inputFileNames[1],
            "-i", inputFileNames[2]
        ]
        await ffmpeg.run(
            '-loop', '1',
            '-framerate', '2',
            [...ffmpegInputs],
            "-c:a", "libmp3lame", 
            "-b:a", "320k", 
            "-filter_complex", "concat=n=2:v=0:a=1",
            "-vcodec", "libx264", 
            "-bufsize", "3M", 
            "-filter:v", "scale=w=1920:h=1930,pad=ceil(iw/2)*2:ceil(ih/2)*2", 
            "-crf", "18", 
            "-pix_fmt", "yuv420p", 
            "-shortest", "", 
            "-tune", "stillimage", 
            "-t", "13", 
            outputFileName
        );

[info] run ffmpeg command: -loop 1 -framerate 2 -i,input-file-0,-i,input-file-1,-i,input-file-2 -c:a libmp3lame -b:a 320k -filter_complex concat=n=2:v=0:a=1 -vcodec libx264 -bufsize 3M -filter:v scale=w=1920:h=1930,pad=ceil(iw/2)*2:ceil(ih/2)*2 -crf 18 -pix_fmt yuv420p -shortest  -tune stillimage -t 13 cool-output-video.mp4
TypeError: a.charCodeAt is not a function


    


    How can I create my ffmpeg args dynamically to work for any number of inputs ?

    


  • ffmpy concatenate multiple files with a file list

    10 novembre 2018, par r4ptor

    I’m currently trying to merge multiple video files with a python script using ffmpeg and ffmpy.
    The names of the files are being written into a file list, as suggested by the ffmpeg concatenate wiki.

    In my example I’m only using two files, but in practice, there will be several hundert files, that’s why I’m choosing the file list approach.

    My current code looks like this :

    import os
    import ffmpy


    base_dir = "/path/to/the/files"

    # where to seek the files
    file_list = open("video_list.txt", "x")

    # scan for the video files
    for root, dirs, files in os.walk(base_dir):
       for video_file in files:
           if video_file.endswith(".avi"):
               file_list.write("file './%s'\n" % video_file)

    # merge the video files
    ff = ffmpy.FFmpeg(
       global_options={"-f",
                       "concat ",
                       "-safe",
                       "0"},
       inputs={file_list: None},
       outputs={"-c",
                "copy",
                "output.avi"},
    )
    ff.run()

    So the code I want to run with ffmpy is

    ffmpeg -f concat -safe 0 -i video_list.txt -c copy output.avi

    But unfortunately my script isn’t working and the resulting error is

    Traceback (most recent call last):
     File "concat.py", line 20, in <module>
       "output.avi", }
     File "/usr/lib/python3.7/site-packages/ffmpy.py", line 54, in __init__
       self._cmd += _merge_args_opts(outputs)
     File "/usr/lib/python3.7/site-packages/ffmpy.py", line 187, in _merge_args_opts
       for arg, opt in args_opts_dict.items():
    AttributeError: 'set' object has no attribute 'items'
    </module>

    Any hints why the command isn’t working the way it should ? Am I missing something regarding the command formatting for ffmpy ?

    Thank you.

  • show subtitles list, get id and name of each subtitles track

    21 septembre 2020, par user25

    I would like to get some list of all available subtitles tracks like :

    &#xA;&#xA;

    #1 - id, name&#xA;#2 - id, name&#xA;#3 - id, name&#xA;...&#xA;

    &#xA;&#xA;

    So list would tell how much subtitles tracks I have, show id and name of each track

    &#xA;&#xA;

    Is there any FFmpeg option to show such list ?

    &#xA;