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• aarch64 : cabac_encode_{decision,bypass,terminal}_asm

  19 novembre 2014, par Janne Grunau

  aarch64 : cabac_encode_decision,bypass,terminal_asm
  benchmarks on a Nexus 9 (nvidia denver) :
  
  101.3 cycles in x264_cabac_encode_decision_c,   67105369 runs, 3495 skips
  
   97.3 cycles in x264_cabac_encode_decision_asm, 67105493 runs, 3371 skips
  
  132.8 cycles in x264_cabac_encode_terminal_c,    1046950 runs, 1626 skips
  
  116.1 cycles in x264_cabac_encode_terminal_asm,  1048424 runs, 152 skips
  
   92.4 cycles in x264_cabac_encode_bypass_c,     16776192 runs, 1024 skips
  
   89.6 cycles in x264_cabac_encode_bypass_asm,   16776453 runs, 763 skips
  Cycle counts are not as stable as one would like. The dynamic code
  
  optimisation seems to produce different results for small chnages in a
  
  binary. Repeated runs with the same binary produce stable results
  
  though (ignoring the first run).
  

  • [DH] Makefile
  • [DH] common/aarch64/asm-offsets.c
  • [DH] common/aarch64/asm-offsets.h
  • [DH] common/aarch64/cabac-a.S
  • [DH] common/cabac.h
  • [DH] tools/checkasm.c

• How to run a command in python with file paths containing spaces ?

  24 juillet 2023, par tomatochan

  I'm developing a program in Python that requires the use of FFMPEG. In one step, I need to create a video from a text file containing the list of images (path and duration) that need to be assembled to make a video. To do this, I use the following code :

  


  cmd = [ffmpeg, "-y", "-f", "concat", "-safe", "0", "-i", tmp, "-c:v", "libx264", "-r", "25", "-pix_fmt", "yuv420p", out]
subprocess.run(cmd)
# os.system(" ".join(cmd)) # returns same error


  


  What returns the error : The syntax of the file, directory or volume name is incorrect.

  


  I know that paths can be problematic when they contain spaces, and as my username has one, I've taken care to quote the paths in such a way that :

  


  ffmpeg = '"C:\Users\John Doe\Documents\ffmpeg\bin\ffmpeg.exe"'
tmp = '"C:\Users\John Doe\Desktop\path\to\file.txt"'
out = '"C:\Users\John Doe\Desktop\path\to\video.mp4"'


  


  When I print(" ".join(cmd)), this is what I get in my terminal :

  


  "C:\Users\John Doe\Documentsffmpeg\binffmpeg.exe" -y -f concat -safe 0 -i "C:\Users\John Doe\Desktop\path\to\file.txt" -c:v libx264 -r 25 -pix_fmt yuv420p "C:\Users\John Doe\Desktop\path\to\video.mp4"


  


  However, the problem persists.
Has anyone ever had this problem and managed to solve it ?

  


  I've also tried the method where you have to escape the spaces (taking care to replace the \ with / and then the with \ ) but nothing works... The error persists.

  


  For your information, here are the contents of one of my .txt files

  


  file C:\Users\John Doe\Desktop\path\to\image_1.png
duration 0.04
file C:\Users\John Doe\Desktop\path\to\image_2.png
duration 0.04
file C:\Users\John Doe\Desktop\path\toimage_3.png
duration 0.04


  


  When I quote the paths in the .txt files

  


  

  • subprocess gives me the error :
PermissionError: [WinError 5] Access denied

  


  • os.system gives me the error :

  


  


  C:\Users\John' is not recognized as an internal or external command, an executable program or a command file.
The syntax of the file, directory or volume name is incorrect.


  


• How to run a ffmpeg command in python with file paths containing spaces ?

  21 juillet 2023, par tomatochan

  I'm developing a program in Python that requires the use of FFMPEG. In one step, I need to create a video from a text file containing the list of images (path and duration) that need to be assembled to make a video. To do this, I use the following code :

  


  cmd = [ffmpeg, "-y", "-f", "concat", "-safe", "0", "-i", tmp, "-c:v", "libx264", "-r", "25", "-pix_fmt", "yuv420p", out]
subprocess.run(cmd)
# os.system(" ".join(cmd)) # returns same error


  


  What returns the error : The syntax of the file, directory or volume name is incorrect.

  


  I know that paths can be problematic when they contain spaces, and as my username has one, I've taken care to quote the paths in such a way that :

  


  ffmpeg = "C:\Users\John Doe\Documents\ffmpeg\bin\ffmpeg.exe"
tmp = "C:\Users\John Doe\Desktop\path\to\file.txt"
out = "C:\Users\John Doe\Desktop\path\to\video.mp4"


  


  When I print(" ".join(cmd)), this is what I get in my terminal :

  


  "C:\Users\John Doe\Documentsffmpeg\binffmpeg.exe" -y -f concat -safe 0 -i "C:\Users\John Doe\Desktop\path\to\file.txt" -c:v libx264 -r 25 -pix_fmt yuv420p "C:\Users\John Doe\Desktop\path\to\video.mp4"


  


  However, the problem persists.
Has anyone ever had this problem and managed to solve it ?

  


  I've also tried the method where you have to escape the spaces (taking care to replace the \ with / and then the with \ ) but nothing works... The error persists.

  


  For your information, here are the contents of one of my .txt files

  


  file C:\Users\John Doe\Desktop\path\to\image_1.png
duration 0.04
file C:\Users\John Doe\Desktop\path\to\image_2.png
duration 0.04
file C:\Users\John Doe\Desktop\path\toimage_3.png
duration 0.04


  


  When I quote the paths in the .txt files

  


  

  • subprocess gives me the error :
PermissionError: [WinError 5] Access denied

  


  • os.system gives me the error :

  


  


  C:\Users\John' is not recognized as an internal or external command, an executable program or a command file.
The syntax of the file, directory or volume name is incorrect.