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• At least one output file must be specified

  11 mai 2015, par Desipicforu Blogspot

  I am using this command in ffmpeg

     ffmpeg -i test.flv -i /var/www/phpvibe/logo.gif -filter_complex "scale=1200:-1,overlay=0:0" -s 1280x720 -vcodec libx264 -s 640x360 -movflags test.mp4 2>&1

  But i am getting this

   string(42) "At least one output file must be specified"

  updated :-

  php code :-

   $output ='{ffmpeg-cmd} -i {input} -i /var/www/phpvibe/logo.gif -filter_complex "scale=1200:-1,overlay=0:0" -s 1280x720 -vcodec libx264 -s {ffmpeg-vsize} -threads 4 -movflags {output}.mp4 2>&1';

  Complete output :-

    array(33) {
  
    [0]=>
  
   string(83) "ffmpeg version git-2015-05-11-94c20de Copyright (c)  2000-2015 the FFmpeg developers"
  
   [1]=>
  
   string(51) "  built with gcc 4.6 (Ubuntu/Linaro 4.6.3-1ubuntu5)"
  
   [2]=>
  
  string(243) "  configuration: --enable-gpl --enable-libfaac --enable-libmp3lame --enable-libopencore-amrnb --enable-libopencore-amrwb --enable-librtmp --enable-libtheora --enable-libvorbis --enable-libvpx --enable-libx264 --enable-nonfree --enable-version3"
  
  [3]=>
  
    string(40) "  libavutil      54. 23.101 / 54. 23.101"
  
  [4]=>
  
  string(40) "  libavcodec     56. 38.100 / 56. 38.100"
  
  [5]=>
  
  string(40) "  libavformat    56. 32.100 / 56. 32.100"
  
  [6]=>
  
  string(40) "  libavdevice    56.  4.100 / 56.  4.100"
  
  [7]=>
  
  string(40) "  libavfilter     5. 16.101 /  5. 16.101"
  
  [8]=>
  
  string(40) "  libswscale      3.  1.101 /  3.  1.101"
  
  [9]=>
  
  string(40) "  libswresample   1.  1.100 /  1.  1.100"
  
  [10]=>
  
  string(40) "  libpostproc    53.  3.100 / 53.  3.100"
  
  [11]=>
  
  string(47) "Trailing options were found on the commandline."
  
  [12]=>
  
  string(31) "Input #0, flv, from 'test.flv':"
  
  [13]=>
  
   string(11) "  Metadata:"
  
  [14]=>
  
  string(28) "    audiosize       : 150117"
  
   [15]=>
  
   string(26) "    canSeekToEnd    : true"
  
   [16]=>
  
   string(29) "    datasize        : 1015662"
  
   [17]=>
  
   string(26) "    hasAudio        : true"
  
   [18]=>
  
   string(27) "    hasCuePoints    : false"
  
   [19]=>
  
   string(26) "    hasKeyframes    : true"
  
   [20]=>
  
   string(26) "    hasMetadata     : true"
  
   [21]=>
  
   string(26) "    hasVideo        : true"
  
   [22]=>
  
   string(24) "    lasttimestamp   : 42"
  
   [23]=>
  
   string(72) "    metadatacreator : flvtool++ (Facebook, Motion project, dweatherford)"
  
   [24]=>
  
   string(25) "    totalframes     : 229"
  
   [25]=>
  
   string(28) "    videosize       : 856032"
  
   [26]=>
  
   string(59) "  Duration: 00:00:42.27, start: 0.066000, bitrate: 192 kb/s"
  
   [27]=>
  
   string(124) "    Stream #0:0: Video: h264 (High), yuv420p, 176x144 [SAR 12:11 DAR 4:3], 165 kb/s, 30.30 fps, 29.97 tbr, 1k tbn, 59.94 tbc"
  
   [28]=>
  
   string(64) "    Stream #0:1: Audio: aac (LC), 8000 Hz, stereo, fltp, 29 kb/s"
  
   [29]=>
  
   string(48) "Input #1, gif, from '/var/www/phpvibe/logo.gif':"
  
   [30]=>
  
  string(29) "  Duration: N/A, bitrate: N/A"
  
   [31]=>
  
   string(67) "    Stream #1:0: Video: gif, bgra, 90x55, 100 tbr, 100 tbn, 100 tbc"
  
   [32]=>
  
   string(42) "At least one output file must be specified"
  
  }
  
  int(1)

• C# app - running FFMpeg from the command line is not working

  11 avril 2017, par Dan Kahn

  I’m trying to run FFMpeg from the Command Line in C#. Previously I was running it from "CMD.exe" and it was working, but that requires a local installation of ffmpeg with configuring my System environmental variables. So I wanted to run it directly from "ffmpeg.exe". I’m using the following code (all the paths are correct), and nothing happens :

  string programToRun = "C:\\Users\\dkahn\\Documents\\PlaybackTool\\PlaybackTool\\Desktop\\Source\\Player\\Player\\ffmpeg\\ffmpeg.exe";
  
  
  
  string directoryName = "C:\\Users\\dkahn\\Documents\\PlaybackTool\\PlaybackTool\\Desktop\\Source\\Player\\test\\test1-1.mp4";
  
  
  
  string command = "@ffmpeg -i test1-1.mp4 -r 1  -s 180x101 test1-1\\output_%04d.png";
  
  
  
  Process cmd = new Process();
  
  cmd.StartInfo.FileName = programToRun;
  
  cmd.StartInfo.RedirectStandardInput = true;
  
  cmd.StartInfo.RedirectStandardOutput = true;
  
  cmd.StartInfo.CreateNoWindow = true;
  
  cmd.StartInfo.UseShellExecute = false;
  
  cmd.StartInfo.WorkingDirectory = directoryName;
  
  cmd.Start();
  
   cmd.StandardInput.WriteLine(command);
  
  cmd.StandardInput.Flush();
  
  cmd.StandardInput.Close();
  
  cmd.WaitForExit();

  Does anybody have any insight ?

• ffmpeg+php Add Music to video

  19 septembre 2013, par user2792392

  Dear Sir i create this code for simple video convert from one to another.
  i want to add more feature like
  ffmpeg+php Add Music to video

  how to do it ??
  convert request to begin encoding the video, and status request that retrieves
  * the current encoding status so the progress bar can be updated.
  *
  * The $outfile variable should be changed to an input value, but is set this way
  * for now for testing purposes.
  *
  * @ver 0.1
  */
  require 'config.php' ;
  require 'functions.php' ;

  //<<-- CHECK FOR ERRORS -->>//
  
  $type       = _chkVal('type', '');
  
  $fkey       = _chkVal('fkey', '');
  
  $infile     = _chkVal('filename', '');
  
  $outfile    = 'testing.mp4';
  
  $params     = _chkVal('params', '');
  
  
  
  // Check Request Type
  
  $validTypes = array('convert', 'status');
  
  
  
  if( !in_array($type, $validTypes) )
  
      json_response(array('fkey' => $fkey, 'msg' => 'Invalid process type!'), true);
  
  
  
  // $fkey will always be 8 characters.
  
  // It's created with PHP's hash() function using 'crc32' algorithm in index.php
  
  if( strlen($fkey) != 8 )
  
      json_response(array_merge(array('fkey' => '', 'msg' => 'Invalid fkey given!')), true);
  
  
  
  // Filename should be at least 5 (1 character + 4 character extension. EX : i.mp4)
  
  if( $type == 'convert' && ( strlen($infile) < 5) )
  
      json_response(array('fkey' => $fkey, 'msg' => 'Invalid input filename given!'), true);
  
  
  
  // Filename should be at least 5 (1 character + 4 character extension. EX : i.mp4)
  
  if( $type == 'convert' && ( strlen($outfile) < 5) )
  
      json_response(array('fkey' => $fkey, 'msg' => 'Invalid output filename given!'), true);
  
  
  
  if( $type == 'convert' && (strlen($params) < 1) )
  
      json_response(array('fkey' => $fkey, 'msg' => 'Invalid parameters given!'), true);
  
  
  
  //<<-- END OF ERROR CHECK -->>//
  
  
  
  
  
  $ffmpegConvert = new ffmpegConvert($fkey);
  
  
  
  
  
  //<<-- PROCESS REQUEST -->>//
  
  
  
  // Start the video conversion
  
  if( $type == 'convert' )
  
  {
  
      $ffmpegConvert->exec( $infile, $outfile, $params, $fkey );
  
      // Add 2 second delay to give the server time to start writing the status log,
  
      // otherwise $ffmpegConvert->jsonStatus() will trigger an error...
  
      sleep(2);
  
      $ffmpegConvert->jsonStatus();
  
  }
  
  
  
  // Check on video conversion progress
  
  if( $_POST['type'] == 'status' )
  
  {
  
      $ffmpegConvert->jsonStatus();
  
  }
  
  
  
  //<<-- END OF PROCESS REQUEST -->>//
  
  
  
  // Shouldn't get to this, but if so, let's send a message for debugging reasons....
  
  json_response(array('msg' => 'Unhandled request type!'), true);