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• Powershell script for youtube-dl

  29 mai 2022, par Ricardo

  I'm trying to write a script to simplify input of variables to youtube-dl.

  


  Here is my ffmpeg command (replace items in brackets) :

  


  ./ffmpeg -ss ['starting time', ex: 05:49] -i $(./youtube-dl -f 22 --get-url ['video youtube url']) -t ['clip duration in seconds'] -c:v copy -c:a copy ['file result name'].mp4


  


  Here is my PowerShell command :

  


  cls

$url = Read-Host -Prompt "Enter the Youtube Video URL"

$start = Read-Host -Prompt "Enter the video start time (H:MM:SS)"

$end = Read-Host -Prompt "Enter the clip duration in seconds"

$name = Read-Host -Prompt "Enter the video name"

./ffmpeg -ss $start -i $(./youtube-dl -f 22 --get-url $url) -t $end -c:v copy -c:a copy $name.mp4



  


  And this is the result I receive from Powershell :

  


  

  


• look for a mp4 file inside a directory and send it to different directory after converting to mp3 in php ?

  13 mai 2019, par flash

  I have a directory called incoming_folder in which there is a mp4 file.

  What I want to achieve through php code is to scan a incoming_folder directory, look for an mp4 file and send it to outgoing_folder after converting it into mp3.

  Technically outgoing_folder should have mp3 version of mp4 from incoming_folder

  Here is the pictorial representation of what I want :

  

  Tried with the following code although its scanning the incoming_folder directory but no conversion is happening through ffmpeg.

  <?php
  
  $dir    = 'in_folder';  /* Place where mp4 file is present */
  
  $files1 = scandir($dir);
  
  print_r($files1);    /* It lists all the files in a directory including mp4 file*/
  
  
  
  $destination = 'out_folder';  /* Place where mp3 file need to be send after conversion from mp4 */
  
  
  
      <?php
  
      foreach($files1 as $f)
  
      {
  
        $parts = pathinfo($f);
  
  
  
        switch($parts['extension'])
  
        {
  
          case 'mp4' :
  
            system('ffmpeg -i '.$f.' -map 0:2 -ac 1 '.$destination.DS. $parts['filename'].'.mp3', $result);
  
  
  
            if ($result) {
  
              // Do something with result if you want
  
              // log for example
  
            }
  
            break;
  
  
  
          case 'mp3' :
  
            // copy($f, $destination. DS . $parts['filename']. '.' . $parts['extension']);
  
            copy($f, $destination.DS.$parts['filename'].'.mp3');
  
            break;  
  
        }
  
      }
  
      ?>

  Problem Statement :

  I am wondering what changes I should make in the php code so that conversion of file happens from incoming_folder and it should go to outgoing_folder.

• Why is PowerShell Eating my Dash

  11 novembre 2017, par gvkv

  In a directory vidtemp with files : G*53.mp4 (a series of GoPro videos) using PowerShell 5.0 :

  PS C:\Users\gvkv\vidtemp $sources = Get-ChildItem -Filter *53*
  
  PS C:\Users\gvkv\vidtemp $vin = [String]::Join(" ", $($sources | %{"-i $($_.Name)"}))
  
  PS C:\Users\gvkv\vidtemp $vin
  
  -i GOPR0053.MP4 -i GP010053.MP4 -i GP020053.MP4 -i GP030053.MP4 -i GP040053.MP4 -i GP050053.MP4
  
  
  
  PS C:\Users\gvkv\Videos\hockeytemp\tt\trw> $concat = [String]::Join(" ", `
  
  >> $(0..$($sources.count-1) | `
  
  >> %{"[$($_):v:0] [$($_):a:0]"}) + "concat=n=$($sources.count):v=1:a=1 [v] [a]" `
  
  >> )
  
  PS C:\Users\gvkv\vidtemp $concat
  
  PS C:\Users\gvkv\vidtemp [0:v:0] [0:a:0] [1:v:0] [1:a:0] [2:v:0] [2:a:0] [3:v:0] [3:a:0] [4:v:0] [4:a:0] [5:v:0] [5:a:0] concat=n=6:v=1:a=1 [v] [a]
  
  PS C:\Users\gvkv\vidtemp ffmpeg $vin `
  
  >> -filter_complex $concat -map '[v]' -map '[a]' `
  
  >> -c:v -crf 21 -preset slow 
  
  >> out.53.mp4
  
  ...
  
  Unrecognized option 'i GOPR0053.MP4 -i GP010053.MP4 -i GP020053.MP4 -i GP030053.MP4 -i GP040053.MP4 -i GP050053.MP4'. 
  
  ndError splitting the argument list: Option not found

  Note there’s no "-" on the first i. What’s happening and what do I do about it ?