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  • ffmpeg php video basic uses and types

    15 mai 2014, par HackerManiac

    Can anyone give a code on how do i covert a video using ffmpeg.

    As thought currently i have only uploading system.

    vu.php(only a part is shown)

    define('UPLOAD','../../videos/');
    
    $fileName = time().$file['name']; 
    
    $target = UPLOAD.$fileName;
    

    
  if(move_uploaded_file($file['tmp_name'],$target)){                
    
      exec("ffmpeg -i ".UPLOAD." ".UPLOAD.$filename.".flv"); 
    
  }

    This pice of code block just uploads the video on video folder but does not converts it to .flv.
    I am not sure how to use ffmpeg.

    My diretory looks like this

    www[localhost]->videos[videos folder]
    
www[localhost]->pictures[pictures folder]
    
www[localhost]->resources[folder]->php[folder]->vu.php

    I also want to return a .jpg image of any frame of video through json by converting via ffmpeg and uploading it to pictures folder.

    return json_encode(array("thumbnail"=>$image_src));

    UPDATE 1

    The above stuff was solved but now i have a question regarding video conversion.
    Suppose i have a file.avi and i want to convert it in 3 sizes of .flv format -> Low(320p) ,Medium (720p)and HD(1080p)

    what commands will i have to send to shell_exec(); and will that be fast enough ?
    CUrrently what i have is

    $vidSize = "640x480";
    
$ffmpeg -i $videoFile -ar 22050 -ab 32 -f flv -s $vidSize $vidFile

    And i am not sure what -ar and -ab means and what value will be good for all those 3 sized videos ?

  • ffmpeg php video basic uses and types [theoritical]

    15 mai 2014, par HackerManiac

    Can anyone give a code on how do i covert a video using ffmpeg.

    As thought currently i have only uploading system.

    vu.php(only a part is shown)

    define('UPLOAD','../../videos/');
    
    $fileName = time().$file['name']; 
    
    $target = UPLOAD.$fileName;
    

    
  if(move_uploaded_file($file['tmp_name'],$target)){                
    
      exec("ffmpeg -i ".UPLOAD." ".UPLOAD.$filename.".flv"); 
    
  }

    This pice of code block just uploads the video on video folder but does not converts it to .flv.
    I am not sure how to use ffmpeg.

    My diretory looks like this

    www[localhost]->videos[videos folder]
    
www[localhost]->pictures[pictures folder]
    
www[localhost]->resources[folder]->php[folder]->vu.php

    I also want to return a .jpg image of any frame of video through json by converting via ffmpeg and uploading it to pictures folder.

    return json_encode(array("thumbnail"=>$image_src));

    UPDATE 1

    The above stuff was solved but now i have a question regarding video conversion.
    Suppose i have a file.avi and i want to convert it in 3 sizes of .flv format -> Low(320p) ,Medium (720p)and HD(1080p)

    what commands will i have to send to shell_exec(); and will that be fast enough ?
    CUrrently what i have is

    $vidSize = "640x480";
    
$ffmpeg -i $videoFile -ar 22050 -ab 32 -f flv -s $vidSize $vidFile

    And i am not sure what -ar and -ab means and what value will be good for all those 3 sized videos ?

  • ffmpeg dont work in php shell_exec("ffmpeg -i $movie $pic &")

    26 septembre 2016, par josef

    I’m running the following script without any problems :

    <?php
    
echo $video  = dirname(__FILE__)."\\MOVIES\\1.mp4";
    
echo "<br />";
    
echo $pic  = dirname(__FILE__)."\\PICTURES\\1.jpg";
    
echo shell_exec("ffmpeg -i  $video  $pic &amp;");

    But when I run this one i get nothing :

    echo shell_exec("ffmpeg -i  C:\xampp\htdocs\Video-share-script\MOVIES\1.mp4  C:\xampp\htdocs\Video-share-script\PICTURES\1.jpg &amp;");

    the value of $video is C :\xampp\htdocs\Video-share-script\MOVIES\1.mp4
    and $pic is C :\xampp\htdocs\Video-share-script\PICTURES\1.jpg
    thank you

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