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• Generate special file list

  11 novembre 2020, par michel

  How can I get a list like this in bash :
I have to create a list like this and then concatenate the files for ffmpeg.

  


  ls -l stream
-rw-r - r-- 1 root root 0 Nov 9 20:30 Il.Gatto.Nero.2019.mp4
-rw-r - r-- 1 root root 0 Nov 9 20:30 My.Name.2019.mp4
-rw-r - r-- 1 root root 0 Nov 9 20:30 Terminator.2019.mp4
-rw-r - r-- 1 root root 0 Nov 9 20:30 spot-Il.Gatto.Nero.2019.mp4
-rw-r - r-- 1 root root 0 Nov 9 20:30 spot-My.Name.2019.mp4
-rw-r - r-- 1 root root 0 Nov 9 20:30 spot-Terminator.2019.mp4

i need to create a txt file like this:

file '/stream/spot-Il.Gatto.Nero.2019.mp4'
file '/stream/Il.Gatto.Nero.2019.mp4'
file '/stream/spot-Terminator.2019.mp4'
file '/stream/Terminator.2019.mp4'
file '/stream/spot-My.Name.2019.mp4'
file '/stream/My.Name.2019.mp4'
file ..........



ls -l | awk {'print "file \047/data/"$9 "\047" '} | awk NF
file '/data/'
file '/data/Il.Gatto.Nero.2019.mp4'
file '/data/Il.Mio.Nome.2019.mp4'
file '/data/Terminator.2019.mp4'
file '/data/spot-Il.Gatto.Nero.2019.mp4'
file '/data/spot-Il.Mio.Nome.2019.mp4'
file '/data/spot-Terminator.2019.mp4'


  


  Greetings Mich

  


  in php have write this :

  


  <?php
$db_host = 'localhost';
$db_name = 'genlist';
$db_user = '********';
$db_pass = '********';
$conn = mysqli_connect($db_host, $db_user, $db_pass);

if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
} else {
//echo "Connected successfully";
}
mysqli_select_db($conn,$db_name) or die ("Error select db: " . mysqli_error());

$sql = "SELECT * FROM tb_movie ORDER BY RAND()";
$query = mysqli_query($conn,$sql);

while($result = mysqli_fetch_assoc($query)) {

$data = "file '/data/EagleCinema/CinemaDramaNew/stream/" . $result['spot']  . "'"."\n";
$data .= "file '/data/EagleCinema/CinemaDramaNew/stream/" . $result['movie'] . "'"."\n";

file_put_contents('/var/www/html/random-cinema-drama.txt', $data, FILE_APPEND );

}


?>


  


  php result :

  


  file '/data/EagleCinema/CinemaDramaNew/stream/spot-Demolition.-.Amare.E.Vivere.2015.mp4'
file '/data/EagleCinema/CinemaDramaNew/stream/Demolition.-.Amare.E.Vivere.2015.mp4'
file '/data/EagleCinema/CinemaDramaNew/stream/spot-Una.Giusta.Causa.2018.mp4'
file '/data/EagleCinema/CinemaDramaNew/stream/Una.Giusta.Causa.2018.mp4'
file '/data/EagleCinema/CinemaDramaNew/stream/spot-Io.Prima.Di.Te.2016.mp4'
file '/data/EagleCinema/CinemaDramaNew/stream/Io.Prima.Di.Te.2016.mp4'
file '/data/EagleCinema/CinemaDramaNew/stream/spot-A.Beautiful.Day.2017.mp4'
file '/data/EagleCinema/CinemaDramaNew/stream/A.Beautiful.Day.2017.mp4'
file '/data/EagleCinema/CinemaDramaNew/stream/spot-Un.Improbabile.Amicizia.2019.mp4'
file '/data/EagleCinema/CinemaDramaNew/stream/Un.Improbabile.Amicizia.2019.mp4'
file '/data/EagleCinema/CinemaDramaNew/stream/spot-The.Intervention.2016.mp4'
file '/data/EagleCinema/CinemaDramaNew/stream/The.Intervention.2016.mp4'


  


  ...

  


  i need same result but with bash script no DB, only scan ffrom directory the file and generate the list.

  


• ffmpeg doesn't accept input in script

  21 octobre 2022, par Eberhardt

  this is a beginner's question but i can't figure out the answer after looking into it for several days :

  


  I want ffmpeg to extract the audio portion of a video and save it in an .ogg container. If i run the following command in terminal it works as expected :

  


  ffmpeg -i example.webm -vn -acodec copy example.ogg


  


  For convenience, i want to do this in a script. However, if i pass a variable to ffmpeg it apparently just considers the first word and produces the error "No such file or directory".

  


  I noticed that my terminal escapes spaces by a \ so i included this in my script. This doesn't solve the problem though.

  


  Can someone please explain to me, why ffmpeg doesn't consider the whole variable that is passed to it in a script while working correctly when getting passed the same content in the terminal ?

  


  This is my script that passes the filename with spaces escaped by \ to ffmpeg :

  


  #!/bin/bash

titelschr=$(echo $@ | sed "s/ /\\\ /g")
titelohne=$(echo $titelschr | cut -d. -f 1)
titelogg=$(echo -e ${titelohne}.ogg)  

ffmpeg -i $titelschr -vn -acodec copy $titelogg


  


  Thank you very much in advance !

  


• checkasm : arm : preserve the stack alignment in x264_checkasm_checked_call

  14 novembre 2016, par Janne Grunau

  checkasm : arm : preserve the stack alignment in x264_checkasm_checked_call
  The stack used by x264_checkasm_checked_call_neon was a multiple of 4
  
  when the checked function is called. AAPCS requires a double word (8 byte)
  
  aligned stack public interfaces. Since both calls are public interfaces
  
  the stack is misaligned when the checked is called.
  This can cause issues if code called within this (which includes
  
  the C implementations) relies on the stack alignment.
  

  • [DH] tools/checkasm-arm.S