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• Streaming jpegs to a video on my server

  2 décembre 2013, par Andrew Simpson

  I found a solution to my problem IF I was using a Linux/UNIX machine. It is FFServer from the tools from FFMPEG.

  I had been using FFMPEG on my client Winform Desktop C# to convert jpegs into an OGG video file for playback.

  I have now been tasked with uploading the jpegs to my server and rendering it as a video.

  Optimum, I would start an FFMPEG process on my client PC and supply its stdin with jpegs in byte array format. I have achieved this (I have looked around) but is there a way to redirect the stdoutput to my server that can be picked up by my code on the server and render in real-time to my web User ?

  I have looked on the ffmpeg web site but I am unsure how to 'fit' it in with my process.

  This is my code so far :

      public byte[] EncodeAndUploadImages(string _args1, string _fn)  
  
      {
  
          byte[] _data = null;
  
          try
  
          {
  
              clientBuild = new Process();
  
              clientBuild.StartInfo.WorkingDirectory = Environment.CurrentDirectory;
  
              clientBuild.StartInfo.Arguments = " -f mjpeg -r 30 -i - -c:v libtheora -q:v 7 -r 30 -f ogg -";
  
              clientBuild.StartInfo.FileName = Environment.CurrentDirectory + @"\ffmpeg.exe";
  
              clientBuild.StartInfo.UseShellExecute = false;
  
              clientBuild.StartInfo.RedirectStandardOutput = true;
  
              clientBuild.StartInfo.RedirectStandardError = true;
  
              clientBuild.StartInfo.RedirectStandardInput = true;
  
              clientBuild.StartInfo.CreateNoWindow = true;
  
              clientBuild.StartInfo.LoadUserProfile = false;
  
              clientBuild.EnableRaisingEvents = true;    
  
              clientBuild.Start();
  
  
  
              using (BinaryWriter bw = new BinaryWriter(clientBuild.StandardInput.BaseStream))
  
              {
  
                 //I am simulating a stream of jpegs coming in////////////////
  
                  for (int i = 1; i < 20; i++)
  
                  {
  
                      using (MemoryStream ms = new MemoryStream())
  
                      {
  
                          System.Diagnostics.Debug.Write(i.ToString("00000"));
  
                          Bitmap bmp = new Bitmap("h:\\streamin\\" + i.ToString("00000") + ".jpg");
  
                          bmp.Save(ms, System.Drawing.Imaging.ImageFormat.Jpeg);
  
                          bw.Write(ms.ToArray());                           
  
                          bmp.Dispose();
  
                          ms.Close();
  
                      }
  
                  }
  
                  bw.Close();
  
              }
  
  
  
              // I need some in my ffmpeg arguments to do something here//////   
  
              mStandardOutput = clientBuild.StandardOutput.BaseStream;
  
              mStandardOutput.BeginRead(mReadBuffer, 0, mReadBuffer.Length, StandardOutputReadCallback, null);
  
              clientBuild.WaitForExit();
  
              _data = mStandardOutputMs.ToArray();
  
              mStandardOutput.Close();
  
          }
  
          catch (Exception _ex)
  
          {
  
  
  
          }
  
          finally
  
          {
  
              clientBuild.Dispose();
  
          }
  
          return _data;
  
      }

  Thanks

• Save taken snapshot

  8 octobre 2014, par User056

  I have done everything how is in this question. everything is alright except one. I can’t save the taken snapshot. If I’ll follow with debug everything is alright.. what’s wrong ?

   public class FFMPEG
  
  {
  
      Process ffmpeg;
  
      public void exec(string input, string parametri, string output)
  
      {
  
          ffmpeg = new Process();
  
  
  
          ffmpeg.StartInfo.Arguments = " -i " + input + (parametri != null ? " " + parametri : "") + " " + output;
  
          ffmpeg.StartInfo.FileName = HttpContext.Current.Server.MapPath("~/ffmpeg.exe");
  
          ffmpeg.StartInfo.UseShellExecute = false;
  
          ffmpeg.StartInfo.RedirectStandardOutput = true;
  
          ffmpeg.StartInfo.RedirectStandardError = true;
  
          ffmpeg.StartInfo.CreateNoWindow = true;
  
  
  
          ffmpeg.Start();
  
          ffmpeg.WaitForExit();
  
          ffmpeg.Close();
  
      }
  
  
  
      public void GetThumbnail(string video, string jpg, string velicina)
  
      {
  
          if (velicina == null) velicina = "640x480";
  
          exec(video, "-ss 00:00:06 " + velicina, jpg);
  
      }
  
  
  
  }
  
  
  
  
  
  FFMPEG f = new FFMPEG();
  
              f.GetThumbnail(Server.MapPath("~/Uploads/" + unique), Server.MapPath("~/Thumbnails/" + unique.Remove(unique.IndexOf(".")) + ".jpg"), "1200x223");

• PHP create video thumbnail from remote url

  23 mars 2017, par user2918057

  I’ve my video storage on google cloud, I need to create the thumbnail for my videos it’s gonna be remote, I tried to use FFmpeg to create and getting the content of the thumbs, but it’s not working, it just returns null for me.

  public function create_video_thumb($video){
  
  
  
          $ffmpeg = '/usr/bin/ffmpeg';
  
  
  
          try{
  
  
  
              $cmd = "ffmpeg -i $video -deinterlace -an -ss 00:00:10 -vframes 1 -f image2 'test.jpg' ";
  
  
  
              $return = array(
  
                  'success'=>true,
  
                  'content' => $cmd
  
              );
  
  
  
          }catch (Exception $e){
  
              $return = $e->getMessage();
  
          }
  
  
  
  
  
          return   $return;
  
      }

  Return :

  {
  
        "sucess":true,
  
        "content":null
  
  }