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    21 juin 2013, par

    MediaSPIP 0.2 is the first MediaSPIP stable release.
    Its official release date is June 21, 2013 and is announced here.
    The zip file provided here only contains the sources of MediaSPIP in its standalone version.
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    Pour réaliser cette tâche on se base sur deux plugins SPIP : Saveauto qui permet une sauvegarde régulière de la base de donnée sous la forme d’un dump mysql (utilisable dans phpmyadmin) mes_fichiers_2 qui permet de réaliser une archive au format zip des données importantes du site (les documents, les éléments (...)

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Sur d’autres sites (5993)

  • How to Bulk Speed UP and Crop Videos FFMPEG

    6 septembre 2023, par Usemo Shank

    I have videos in (input) folder that is located on the root of the script, I also have output folder on the root, The input folder has several videos that i want to speed up in bulk by 1.1 percent, I also want to cropt the videos by 90 percent (Meaning 90 Percent of original video is visible).

    


    I have a code that does not function well. Here is the code I have

    


     import os
import subprocess

# Define input and output directories
input_folder = "input"
output_folder = "output"

# Create the output directory if it doesn't exist
if not os.path.exists(output_folder):
    os.makedirs(output_folder)

# List all video files in the input directory
input_files = [f for f in os.listdir(input_folder) if f.endswith(('.mp4', '.avi', '.mkv'))]

# Speed up and crop each video
for input_file in input_files:
    input_path = os.path.join(input_folder, input_file)
    output_file = os.path.splitext(input_file)[0] + "_speed_crop.mp4"
    output_path = os.path.join(output_folder, output_file)

    # FFmpeg command to speed up video by 1.1x and crop to 90%
    ffmpeg_command = [
        "ffmpeg",
        "-i", input_path,
        "-vf", "setpts=1.1*PTS,crop=in_w*0.9:in_h*0.9",
        "-c:v", "libx264",
        "-crf", "20",
        "-c:a", "aac",
        "-strict", "experimental",
        output_path
    ]

    # Run FFmpeg command
    subprocess.run(ffmpeg_command)

print("Conversion complete.")


    


  • find the timestamp of a sound sample of an mp3 with linux or python

    23 juin 2020, par cardamom

    I am slowly working on a project which where it would be very useful if the computer could find where in an mp3 file a certain sample occurs. I would restrict this problem to meaning a fairly exact snippet of the audio, not just for example the chorus in a song on a different recording by the same band where it would become more some kind of machine learning problem. Am thinking if it has no noise added and comes from the same file, it should somehow be possible to locate the time at which it occurs without machine learning, just like grep can find the lines in a textfile where a word occurs.

    


    In case you don't have an mp3 lying around, can set up the problem with some music available on the net which is in the public domain, so nobody complains :

    


    curl https://web.archive.org/web/20041019004300/http://www.navyband.navy.mil/anthems/ANTHEMS/United%20Kingdom.mp3 --output godsavethequeen.mp3


    


    It's a minute long :

    


    exiftool godsavethequeen.mp3 | grep Duration
Duration                        : 0:01:03 (approx)


    


    Now cut out a bit between 30 and 33 seconds (the bit which goes la la la la..) :

    


    ffmpeg -ss 30 -to 33 -i godsavethequeen.mp3 gstq_sample.mp3


    


    both files in the folder :

    


    $ ls -la
-rw-r--r-- 1 cardamom cardamom   48736 Jun 23 00:08 gstq_sample.mp3
-rw-r--r-- 1 cardamom cardamom 1007055 Jun 22 23:57 godsavethequeen.mp3


    


    This is what am after :

    


    $ findsoundsample gstq_sample.mp3 godsavethequeen.mp3
start 30 end 33


    


    Am happy if it is a bash script or a python solution, even using some kind of python library. Sometimes if you use the wrong tool, the solution might work but look horrible, so whichever tool is more suitable. This is a one minute mp3, have not thought yet about performance just about getting it done at all, but would like some scalability, eg find ten seconds somewhere in half an hour.

    


  • How to convert from .h264 to .ts using FFmpeg wrapper for C#/.NET ?

    9 décembre 2020, par juan_marti

    Context

    


    I'm using FFMpegCore in my .NET Core API project that receives a .h264 file (sent in a binary format that is received and converted into a byte array) to be converted to a .ts.

    


    I want to convert a .h264 stream into a .ts output stream using FFmpeg.

    


    Current Approach

    


    (...)

byte[] body;
using ( var ms = new MemoryStream() )
{
    await request.Body.CopyToAsync( ms ); // read sent .h264 data
    body = ms.ToArray();
}

var outputStream = new MemoryStream();

// FFMpegCore
await FFMpegArguments
                .FromPipeInput( new StreamPipeSource( new MemoryStream( body ) ) )
                .OutputToPipe( new StreamPipeSink( outputStream ), options => options
                .ForceFormat( VideoType.MpegTs ) )
                .ProcessAsynchronously();

// view converted ts file
await File.WriteAllBytesAsync( "output.ts", outputStream.ToArray() );

(...)


    


    Problem

    


    I'm not getting a working .ts file. What I'm a doing wrong ? Could you please give some hint or help me with this ? Even if you have other FFmpeg wrappers that you consider more suitable for this problem.

    


    Notes :

    


      

    • I don't have the physical location of the files since this will receive the content of the files over HTTP. So, I will only have the byte array meaning that I need to use the input stream to convert to another format.
    • 


    • FFmpeg command used to test the conversion from .h264 to .ts (using files) : ffmpeg -i file.h264 -an -vcodec copy -f mpegts output.ts
    •