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The pirate bay depuis la Belgique
1er avril 2013, par
Mis à jour : Avril 2013
Langue : français
Type : Image
Autres articles (73)
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MediaSPIP 0.1 Beta version
25 avril 2011, parMediaSPIP 0.1 beta is the first version of MediaSPIP proclaimed as "usable".
The zip file provided here only contains the sources of MediaSPIP in its standalone version.
To get a working installation, you must manually install all-software dependencies on the server.
If you want to use this archive for an installation in "farm mode", you will also need to proceed to other manual (...) -
MediaSPIP version 0.1 Beta
16 avril 2011, parMediaSPIP 0.1 beta est la première version de MediaSPIP décrétée comme "utilisable".
Le fichier zip ici présent contient uniquement les sources de MediaSPIP en version standalone.
Pour avoir une installation fonctionnelle, il est nécessaire d’installer manuellement l’ensemble des dépendances logicielles sur le serveur.
Si vous souhaitez utiliser cette archive pour une installation en mode ferme, il vous faudra également procéder à d’autres modifications (...) -
Personnaliser en ajoutant son logo, sa bannière ou son image de fond
5 septembre 2013, parCertains thèmes prennent en compte trois éléments de personnalisation : l’ajout d’un logo ; l’ajout d’une bannière l’ajout d’une image de fond ;
Sur d’autres sites (10846)
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Convert video into mp3 format using ffmpeg in nodejs and angular and then save converted audio into the database(mongodb)
6 septembre 2021, par Amir ShahzadThis is nodejs server side file


const express = require('express');
const ffmpeg = require('fluent-ffmpeg');
const fileUpload = require('express-fileupload');
const mongoose = require('mongoose');
const cors = require('cors')
const app = express();
const Video = require('./models/video');
mongoose.connect('mongodb://localhost:27017/YoutubeApp', {
 useNewUrlParser: true,
 useUnifiedTopology: true,
});
const db = mongoose.connection;
db.on('error', console.error.bind(console, 'connection error'));
db.once('open', () => {
 console.log('Data Base Connected Successfully!');
});

app.use(fileUpload({
 useTempFiles: true,
 tempFileDir: 'temp/'
}));
app.use(express.json());
app.use(express.urlencoded({ extended: true }));
app.use(cors({ origin: 'http://localhost:4200' }));


ffmpeg.setFfmpegPath('/usr/bin/ffmpeg');

app.post('/mp4tomp3', (req, res) => {
 convertdata = req.body;
 console.log('path of innput is', req.body);
 function convert(input, output, callback) {
 ffmpeg(input)
 .output(output)
 .on('end', function() { 
 console.log('conversion ended');
 callback(null);
 }).on('error', function(err){
 console.log('error: ', err.code, err.msg);
 callback(err);
 }).run();
 }
 convert(convertdata, './temp/output.mp3', function(err){
 if(!err) {
 console.log('conversion complete');

 
 }
 })

 app.listen(3000, () => {
 console.log('Server Start On Port 3000')
 })



In Convert function i not know how i can get input by the user i'm new in angular Please anyone can solve this out thanks in advance


This is video model file


const mongoose = require("mongoose");
const Schema = mongoose.Schema;

const videoSchema = new Schema({
 mp4: String,
});
module.exports = mongoose.model("Videos", videoSchema);



**This is Typescript code in angular client side that handle user input and select video **


import { ThrowStmt } from '@angular/compiler';
import { Component, OnInit } from '@angular/core';
import { FormBuilder, FormGroup, Validators } from '@angular/forms';
import { VideoConversionService } from 'src/services/video-conversion.service';

@Component({
 selector: 'app-root',
 templateUrl: './app.component.html',
 styleUrls: ['./app.component.css']
})
export class AppComponent implements OnInit {

 submitted =false;
 form! : FormGroup
 data:any

 constructor(private formBuilder: FormBuilder,
 private videoService: VideoConversionService){}

 creatForm(){
 this.form = this.formBuilder.group({
 mp4: ['', Validators.required],
 });
 }
 ngOnInit(): void {
 this.creatForm();

 }


 convertVideo(){
 this.submitted = true
 this.videoService.conversion(this.form.value).subscribe(res => {
 this.data = res;
 })
 }

 }



I do not know how to create logic to do that (convert video into audio using angular framework)


This is app.component.html file where i want to get video from the user using input field


<div class="container">
 <h1>Video Proccessing App</h1>
 <form>
 <input type="file" formcontrolname="mp4" />
 <input type="submit" value="Convert" />
 </form>
</div>





But my code is not working and video is not converting into audio


This is my video service file where i calling nodejs api to perform the task


import { Injectable } from '@angular/core';
import { HttpClient } from '@angular/common/http';
@Injectable({
 providedIn: 'root'
})
export class VideoConversionService {

constructor(private httpClient: HttpClient) { }

conversion(data: any){
 return this.httpClient.post('http://localhost:3000/mp4tomp3', data)
}
}



Please anyone can solve my problem Thanks in advance


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ffmpeg save highly quality video by using rtsp link [closed]
22 août 2023, par Shivam SinghI'm trying to download good quality of video from the camera stream by using ffmpeg


ffmpeg -i rtsp://admin:admin@123@117.216.143.251:556 -r 15 /home/Documents/Yolo/yolo/251.avi



How to download good quality of video by using ffmpeg ?


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How can i save a iphone uploaded video always horizontal by ffmpeg
24 juillet 2013, par Ranjith ReddyI am using FFMPEG for uploading recording video from iphone and generating frames.
case1 : recording video in horizontal (generating video and frames in horizontal).
case2 : recording video in vertical (generating video and frames in vertical).
But in above 2 case i want video and frames in horizontal only.
FFMPEG COMMAND
%x(cd "#{tmp_path}" && ffmpeg -i "video path" -r 1 -f image2 image-%4d.jpeg )