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• How to run a command in python with file paths containing spaces?

  24 July 2023, by tomatochan

  I'm developing a program in Python that requires the use of FFMPEG. In one step, I need to create a video from a text file containing the list of images (path and duration) that need to be assembled to make a video. To do this, I use the following code:

  


  cmd = [ffmpeg, "-y", "-f", "concat", "-safe", "0", "-i", tmp, "-c:v", "libx264", "-r", "25", "-pix_fmt", "yuv420p", out]
subprocess.run(cmd)
# os.system(" ".join(cmd)) # returns same error


  


  What returns the error: The syntax of the file, directory or volume name is incorrect.

  


  I know that paths can be problematic when they contain spaces, and as my username has one, I've taken care to quote the paths in such a way that :

  


  ffmpeg = '"C:\Users\John Doe\Documents\ffmpeg\bin\ffmpeg.exe"'
tmp = '"C:\Users\John Doe\Desktop\path\to\file.txt"'
out = '"C:\Users\John Doe\Desktop\path\to\video.mp4"'


  


  When I print(" ".join(cmd)), this is what I get in my terminal:

  


  "C:\Users\John Doe\Documentsffmpeg\binffmpeg.exe" -y -f concat -safe 0 -i "C:\Users\John Doe\Desktop\path\to\file.txt" -c:v libx264 -r 25 -pix_fmt yuv420p "C:\Users\John Doe\Desktop\path\to\video.mp4"


  


  However, the problem persists.
Has anyone ever had this problem and managed to solve it?

  


  I've also tried the method where you have to escape the spaces (taking care to replace the \ with / and then the with \ ) but nothing works... The error persists.

  


  For your information, here are the contents of one of my .txt files

  


  file C:\Users\John Doe\Desktop\path\to\image_1.png
duration 0.04
file C:\Users\John Doe\Desktop\path\to\image_2.png
duration 0.04
file C:\Users\John Doe\Desktop\path\toimage_3.png
duration 0.04


  


  When I quote the paths in the .txt files

  


  

  • subprocess gives me the error:
PermissionError: [WinError 5] Access denied

  


  • os.system gives me the error:

  


  


  C:\Users\John' is not recognized as an internal or external command, an executable program or a command file.
The syntax of the file, directory or volume name is incorrect.


  


• Requesting header information of a file

  11 January 2012, by 0v3rrid3

  is there anyway I can request only the header information of any media. For example I just want to request header information of any video file so as to find its video length. I tried using ffmpeg -i {video_url} and did the work but I noticed that it actually downloads the given media in local storage and returns back the header information which obviously increases roundtrip time.

  So I would really appreciate if there is any idea for finding the length of media in a fly. BTW I have a ruby on rails application where I need to implement this.

• ffmpeg watermark

  8 May 2018, by tomi

  I am using a static compiled lib of FFMPEG gotten from BAMBUSER for android.
  The problem I am facing now is that FFMPEG version gotten from BAMBUSER does not support watermarking.

  ffmpeg -sameq -i mirror_watermark.mp4 -vf "movie=mirror_watermark.png [logo]; [in][logo] overlay=main_w-overlay_w:main_h-overlay_h [out]" output.mp4
  
  No such filter: 'movie'
  
  
  
  ./configure --list-filters | grep movie
  
  returns nothing

  So I guess I have to use a newer version of FFMPEG but I do not know how to get started since with the BAMBUSER everything was already set I just added certain encoders and decoders to their script.