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• Anomalie #3408 (En cours) : Ergo : incoherence entre l’accès au formulaire instituer et si on a vr...

  9 février 2021, par b b

  J’aillais envoyer le patch suivant, mais...

  < b_b‎ >  je voulais tester avant d’envoyer maieul 
  < b_b‎ >  mais je ne comprends pas le bug
  < b_b‎ >  je dois faire quoi pour le reproduire ?
  < b_b‎ >  en tant que rédacteur j’ai :
  < b_b‎ >  en cours de rédac + proposé + à la poubelle
  < b_b‎ >  j’envoie rien tant que je ne peux pas reproduire le bug
  

  * d702e8779a - (HEAD -> issue_3408) tester aussi qu’on peut publier dans la rubrique courante au chargement du formulaire (b_b il y a 5 minutes)
  | 
  | diff —git a/prive/formulaires/instituer_objet.php b/prive/formulaires/instituer_objet.php
  | index b5ae508405..cfa5f710e4 100644
  | --- a/prive/formulaires/instituer_objet.php
  | +++ b/prive/formulaires/instituer_objet.php
  | @@ -93,6 +93,11 @@ function formulaires_instituer_objet_charger_dist($objet, $id_objet, $retour = ’
  |              
  |          
  |      
  | +
  | +    if (isset($v[’id_rubrique’]) and !autoriser(’publierdans’, ’rubrique’, $v[’id_rubrique’])) 
  | +        $publiable = false ;
  | +    
  | +
  |      $statuts = lister_statuts_proposes($desc, $editable ? $publiable : true) ;
  |      if (count($statuts) == 1 and isset($statuts[$v[’statut’]])) 
  |          $editable = false ;
  

• Stream my webcam on RTMP through FFMPEG

  3 mars 2014, par M.Yazdian

  I want to stream my webcam on RTMP through FFMPEG.

  I use FFMPEG in ProcessStartInfo, when I start this process FFMPEG run in new window and my web cam Images stream in RTMP correctly.

  But I have problems in this case :

  1- When I start to process, FFMPEG runs in the new window (cmd), I don’t need this window.

  I like FFMPEG work in background.

  2- When the FFMPEG in working I can't access to my forms.

  My vb.net forms are locked until FFMPEG process is done.

  3- I have 3 webcam in my computer and I like to stream these 3 webcams on the RTMP such as webcam1 , webcam2 , webcam3, But when I start stream from webcam1, I can't access to start other webcams to stream.

  Dim camName = DirectCast(sender, Button)
  
  Dim psi As ProcessStartInfo = New ProcessStartInfo("c:\ImageMagick\ffmpeg.exe")
  
  Dim proc As Process = Process.Start(psi)
  
  psi.UseShellExecute = False
  
  psi.CreateNoWindow = False
  
  psi.Arguments = " -f dshow -i video=""" & camName.Name & """ -threads 1 -preset ultrafast -vcodec libx264 -b:v 640k -acodec copy -f flv rtmp://192.168.1.2/live/sample2 "
  
  proc = Process.Start(psi)
  
  proc.WaitForExit()

  Please advise me to solve these issues

  Thanks in advance

• Process is not exiting ffmpeg.exe only for the command which detects the silences from a video

  20 juillet 2015, par Jitender Kumar

  The job of the method ExecuteCommandSync is to detect the silences from a video and return the output as string but when I run this code it never bring the value of proc.HasExited as true. If I forcefully drag the debugger to the line

  result =proc.StandardOutput.ReadToEnd()

  then it never exit the ffmpeg.exe so as a result control never returns back.

  Although the same method is working fine for a different command like creating an audio file from a video. In this case proc.HasExited also returns false but it also generates the audio file successfully.

  public static string ExecuteCommandSync(string fileName, int timeoutMilliseconds)
  
      {
  
          string result = String.Empty;
  
          string workingDirectory = Directory.GetCurrentDirectory();
  
          try
  
          {
  
              string command = string.Format("ffmpeg -i {0} -af silencedetect=noise=-20dB:d=0.2 -f null -", "\"" + fileName + "\"");                
  
              System.Diagnostics.ProcessStartInfo procStartInfo =
  
                  new System.Diagnostics.ProcessStartInfo("cmd", "/c " + command);
  
  
  
              procStartInfo.WorkingDirectory = workingDirectory;                
  
              procStartInfo.RedirectStandardOutput = true;
  
              procStartInfo.RedirectStandardError = true;
  
              procStartInfo.UseShellExecute = false;                
  
              procStartInfo.CreateNoWindow = false;                
  
              System.Diagnostics.Process proc = new System.Diagnostics.Process();
  
              proc.StartInfo = procStartInfo;
  
              proc.Start();                
  
              proc.WaitForExit(timeoutMilliseconds);
  
              // Get the output into a string 
  
              if (proc.HasExited)
  
              {
  
                  if (!proc.StandardOutput.EndOfStream)
  
                  {
  
                      result = proc.StandardOutput.ReadToEnd();
  
                  }
  
                  else if (!proc.StandardError.EndOfStream)
  
                  {
  
                      result = "Error:: " + proc.StandardError.ReadToEnd();
  
                  }
  
              }
  
          }
  
          catch (Exception)
  
          {
  
              throw;
  
          }
  
          return result;
  
      }

  So please advice.