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Publier une image simplement
13 avril 2011, par ,
Mis à jour : Février 2012
Langue : français
Type : Video
Autres articles (85)
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Websites made with MediaSPIP
2 mai 2011, parThis page lists some websites based on MediaSPIP.
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Creating farms of unique websites
13 avril 2011, parMediaSPIP platforms can be installed as a farm, with a single "core" hosted on a dedicated server and used by multiple websites.
This allows (among other things) : implementation costs to be shared between several different projects / individuals rapid deployment of multiple unique sites creation of groups of like-minded sites, making it possible to browse media in a more controlled and selective environment than the major "open" (...) -
Le profil des utilisateurs
12 avril 2011, parChaque utilisateur dispose d’une page de profil lui permettant de modifier ses informations personnelle. Dans le menu de haut de page par défaut, un élément de menu est automatiquement créé à l’initialisation de MediaSPIP, visible uniquement si le visiteur est identifié sur le site.
L’utilisateur a accès à la modification de profil depuis sa page auteur, un lien dans la navigation "Modifier votre profil" est (...)
Sur d’autres sites (11836)
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ffmpeg multiple input video in grid and simultaneous audio
13 février 2023, par Hnusny Plebi would like to copy a video into n videos in one grid :
best example : https://www.youtube.com/watch?v=lYKDTLGH-TQ&ab_channel=TheRabbit_123


This is my code, its working, but problem is, the audio seems to be like its played by one version.. I want the "echo" thats created by a lot of files like on the video above.


def create_4_in_one(number):
shutil.copy("start.mp4", f"video.mp4")
for i in range(number):
 shutil.copy("video.mp4", f"temp_videa/{i}.mp4")
 subprocess.call(f'ffmpeg -y -i video.mp4 -vf "scale=iw/2:ih/2" -c:a copy video_half.mp4',
 shell=True)
 subprocess.call(f'ffmpeg -y -i video_half.mp4 -i video_half.mp4 -i video_half.mp4 -i video_half.mp4 -filter_complex "[0:v][1:v]hstack[t];[2:v][3:v]hstack[b];[t][b]vstack[v]; [0:a][1:a][2:a][3:a]amerge=inputs=4[a]" -map "[v]" -map "[a]" -map 0:a -map 1:a -map 2:a -map 3:a -c:a aac -b:a 128k -ac 2 -shortest output.mp4',
 shell=True)
 os.remove("video.mp4")
 os.remove("video_half.mp4")
 os.rename('output.mp4', 'video.mp4')

os.remove("video.mp4")



Thanks in advance.


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Elegant early exit from a spawned ffmpeg process in C
21 octobre 2016, par jackson80I have a program where I build an ffmpeg command string to capture videos with options input through a gtk3 gui. Once I have all my options selected, I spawn a process with the ffmpeg command string. And I add a child watch to tell me when the process has completed.
// Spawn child process
ret = g_spawn_async (NULL, argin, NULL, G_SPAWN_DO_NOT_REAP_CHILD, NULL, NULL, &pid1, NULL);
if ( !ret )
{
g_error ("SPAWN FAILED");
return;
}
/* Add watch function to catch termination of the process. This function
* will clean any remnants of process */
g_child_watch_add (pid1, (GChildWatchFunc)cb_child_watch, widget );Executing ffmpeg from a terminal using a command line, the program will give an option to input a "q" at the terminal to end the ffmpeg process early.
Is there any way to send a "q" to that spawned process to elegantly end the ffmpeg ? I’m fairly sure I could kill the process using the process id, but I would rather stop it using a mechanism that allows ffmpeg to gracefully exit..
This is running Centos 7, kernel 4.7.5, ffmpeg version 3.0.2.
Since I can still access the terminal where the ffmpeg output is displayed, I’ve tried typing a "q", but it has no effect on the process. -
AttributeError : 'FFmpegAudio' object has no attribute '_process' while trying to play audio from URL
13 août 2022, par jmcamacho7I can't find any solution online and I don't know what's wrong.


My code is : (Not pasting the URL getting since that works fine)


from urllib import parse, request
import re
import pafy
from discord import FFmpegPCMAudio, PCMVolumeTransformer

FFMPEG_OPTIONS = {
 'before_options': '-reconnect 1 -reconnect_streamed 1 -reconnect_delay_max 5', 'options': '-vn'
}

@bot.command(pass_context=True)
async def play(ctx, * , search):
 query_string = parse.urlencode({'search_query': search})
 html_content = request.urlopen('http://www.youtube.com/results?' + query_string)
 search_results=re.findall('watch\?v=(.{11})',html_content.read().decode('utf-8'))
 print(search_results[0])
 
 if(ctx.author.voice):
 channel = ctx.message.author.voice.channel
 await ctx.send("https://www.youtube.com/watch?v="+search_results[0]) 
 url = "https://www.youtube.com/watch?v="+search_results[0]
 conn = await channel.connect()
 conn.play(discord.FFmpegAudio(url, **FFMPEG_OPTIONS))
 else:
 await ctx.send("Necesitas estar en un canal de audio para usar este comando")



It just gives me this error everytime I try it :


Traceback (most recent call last):
 File "/home/runner/HakuBot/venv/lib/python3.8/site-packages/discord/player.py", line 103, in __del__
 self.cleanup()
 File "/home/runner/HakuBot/venv/lib/python3.8/site-packages/discord/player.py", line 154, in cleanup
 proc = self._process
AttributeError: 'FFmpegAudio' object has no attribute '_process'



Anyway to solve this ?