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• Unable find an ffmpeg binary for your Android system

  22 juillet 2024, par Ayush Thakur

  Working on a project where I need to use FFmpeg library in Kotlin to work on some audio files. However I'm unable to initialize the ffmpeg library itself.

  


  this is the error I'm getting

  


  Could not find an ffmpeg binary for your Android system. Did you forget calling: 'new AndroidFFMPEGLocator(this);' ?
2024-07-22 18:48:33.910 11800-11800 PipeDecoder             com.example.sangeet                  E  Tried to unpack a statically compiled ffmpeg binary for your architecture to: /data/user/0/com.example.sangeet/cache/ffmpeg
2024-07-22 18:48:33.923 11800-11800 AndroidRuntime          com.example.sangeet                  E  FATAL EXCEPTION: main (Ask Gemini)
                                                                                                    Process: com.example.sangeet, PID: 11800
                                                                                                    java.lang.Error: Decoding via a pipe will not work: Could not find an ffmpeg binary for your system


  


  @HiltAndroidApp
class Sangeet: Application(){
    override fun onCreate() {
        super.onCreate()
        provideFirebaseApp(this)
        FFmpegKitConfig.setLogLevel(Level.AV_LOG_INFO)
        FFmpegKitConfig.enableLogCallback { Log.d("ffmpeg",it.message) }
        initializeFFmpegKit()
    }
    private fun initializeFFmpegKit() {
        // This method should be sufficient to ensure FFmpegKit is ready to use
        val ffmpegSession = FFmpegKit.execute("ffmpeg -version")
        if (ReturnCode.isSuccess(ffmpegSession.returnCode)) {
            Log.d("FFmpeg", "FFmpeg is ready to use.")
        } else {
            Log.e("FFmpeg", "Failed to initialize FFmpeg: ${ffmpegSession.failStackTrace}")
            initializeFFmpegBinary()
        }
    }
    private fun initializeFFmpegBinary() {
        val ffmpegBinaryPath = filesDir.absolutePath + "/ffmpeg"
        val binaryFile = File(ffmpegBinaryPath)
        if (!binaryFile.exists()) {
            Log.e("FFmpeg", "FFmpeg binary not found at $ffmpegBinaryPath")
            // Copy or download the FFmpeg binary to this path
        } else {
            Log.d("FFmpeg", "FFmpeg binary found at $ffmpegBinaryPath")
        }
    }
}


  


  Tried using AndroidFFMPEGLocator(this) ; as suggested by the compiler in my code but unknown reference error is coming for the above line of code.

  


  Also tried using FFmpegKit.init(this) function but init is also not being recognised by the compiler

  


• Convert GIF to MP4 with ffmpeg with palette color

  28 mars 2019, par NAG

  Palettegen is ok :

  ffmpeg()
  
  .input('temp/' + input.hash)
  
  .outputOptions(["-vf fps=15,scale=320:-1:flags=lanczos,palettegen"])
  
  .output('temp/palette.png')

  the conversion using the palette return a error :

  Error : Cannot find a matching stream for unlabeled input pad 1 on filter Parsed_paletteuse_0

  ffmpeg()
  
  .input('color=' + input.bg)
  
  .inputFormat('lavfi')
  
  .input('temp/' + input.hash)
  
  .inputFormat('gif')
  
  .input('temp/palette.png')
  
  .outputOptions('-lavfi paletteuse')
  
  .complexFilter(["[0][1]scale2ref[bg][gif]", "[bg]setsar=1[bg]", "[bg][gif]overlay=shortest=1[o]", "[o]scale=trunc(iw/2)*2:trunc(ih/2)*2"])
  
  .outputOptions(['-pix_fmt yuv420p', '-movflags frag_keyframe+empty_moov', '-movflags +faststart', '-crf 5'])
  
  .toFormat('mp4')
  
  .output('temp/final-' + input.hash)

  ffmpeg final command :

  ffmpeg -f lavfi -i color=ffffff -f gif -i temp/cf81f99083462f693406e8fd03ca7009 -i temp/palette.png -y -filter_complex [0][1]scale2ref[bg][gif];[bg]setsar=1[bg];[bg][gif]overlay=shortest=1[o];[o]scale=trunc(iw/2)*2:trunc(ih/2)*2 -lavfi paletteuse -pix_fmt yuv420p -movflags frag_keyframe+empty_moov -movflags +faststart -crf 5 -f mp4 temp/final-cf81f99083462f693406e8fd03ca7009

• How to join two video files using Python ?

  1er juillet 2013, par rash

  Here I tried to cut first and second 30sec long video file from "path/connect.webm" to the strings out and out1. It works. But what I need to do is to concatenate these two strings and write that to a file "path/final.webm". So that I get a 60sec long video file "final.webm" at the end. But now i get first 30sec long video only as the output. Please help me. Thanks a lot in advance.

  Code in python :

  import subprocess,os
  
  
  
  fname = "/home/xincoz/test/final.webm"
  
  
  
  fp = open(fname,'wb')
  
  
  
  ffmpeg_command = ["ffmpeg", "-i", "/home/xincoz/test/connect.webm", "-acodec", "copy",   "-ss", "00:00:00", "-t", "00:00:30","-f", "webm", "pipe:1"]
  
  
  
  p = subprocess.Popen(ffmpeg_command,stdout=subprocess.PIPE)
  
  
  
  out, err = p.communicate()
  
  
  
  ffmpeg_command1 = ["ffmpeg", "-i", "/home/xincoz/test/connect.webm", "-acodec", "copy",   "-ss", "00:00:31", "-t", "00:00:30","-f", "webm", "pipe:1"]
  
  
  
  p1 = subprocess.Popen(ffmpeg_command1,stdout=subprocess.PIPE)
  
  
  
  out1, err1 = p1.communicate()
  
  
  
  string = out + out1
  
  
  
  print len(out)
  
  
  
  print len(out1)
  
  
  
  print len(string)
  
  
  
  fp.write(string)
  
  
  
  fp.close()

  Please help me.