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• sh : ffmpeg : command not found when run command through php

  9 avril 2015, par Ashok

  I have installed successfully installed FFMpeg on root of my Centos 6 machine (https://trac.ffmpeg.org/wiki/CompilationGuide/Centos).

  My workplace of apache/php is /var/www/html

  Now I’m running below command successfully on /var/www/html directory to capture frame from the video file. It’s capturing a frame.

  [root@localhost html]# ffmpeg -i video.mpg -an -ss 30  -t 00:00:01 -r 1 -y -vcodec mjpeg -f mjpeg -s 160x100 frame8  2>&1

  I want to run this command through php and using shell_exec() or exec() php functions. My php code for running the command is :

  $cmd = "/root/bin/ffmpeg -i /project/app/webroot/videos/video.mpg -ss 00:00:14.435 -f image2 -vframes 1 /project/app/webroot/videothumbnails/example-thumb.jpg";
  
  $locale = 'en_IN.UTF-8';
  
  setlocale(LC_ALL, $locale);
  
  putenv('LC_ALL='.$locale);
  
  echo shell_exec($cmd);

  When I’m trying to run command through above php code, I’m getting below error :

  sh: ffmpeg: command not found

  Please help me to solve out this problem.

• sh : ffmpeg : command not found when run command through php

  21 septembre 2018, par Vivacity InfoTech

  I have installed successfully installed FFMpeg on root of my Centos 6 machine (https://trac.ffmpeg.org/wiki/CompilationGuide/Centos).

  My workplace of apache/php is /var/www/html

  Now I’m running below command successfully on /var/www/html directory to capture frame from the video file. It’s capturing a frame.

  [root@localhost html]# ffmpeg -i video.mpg -an -ss 30  -t 00:00:01 -r 1 -y -vcodec mjpeg -f mjpeg -s 160x100 frame8  2>&1

  I want to run this command through php and using shell_exec() or exec() php functions. My php code for running the command is :

  $cmd = "/root/bin/ffmpeg -i /project/app/webroot/videos/video.mpg -ss 00:00:14.435 -f image2 -vframes 1 /project/app/webroot/videothumbnails/example-thumb.jpg";
  
  $locale = 'en_IN.UTF-8';
  
  setlocale(LC_ALL, $locale);
  
  putenv('LC_ALL='.$locale);
  
  echo shell_exec($cmd);

  When I’m trying to run command through above php code, I’m getting below error :

  sh: ffmpeg: command not found

  Please help me to solve out this problem.

• ffmpeg on ubuntu convert 3gp to iphone 5 format [closed]

  21 mars 2013, par Jistanidiot

  I'm desperately trying to convert a 3GP video into something the iphone 5 will import and play. Verizon says they cannot help me that it is not possible to convert a Droid video to iphone.

  After much trouble I came to the conclusion to try the conversion on my Ubuntu box using ffmpeg. Again after a long struggle, I removed the package and followed the directions at https://ffmpeg.org/trac/ffmpeg/wiki/UbuntuCompilationGuide

  Now with the new complied ffmpeg, I try the following command :

   ffmpeg -i foo.3gp -s 320x240 -r 30000/1001 -b:v 200k -bt 240k -vcodec libx264 -coder 0 -bf 0 -flags2 -wpred-dct8x8 -level 13 -maxrate 768k -bufsize 3M-acodec libfaac -ac 2 -ar 48000 -ab 192k output.mp4

  However I keep getting the error :

   [NULL @ 0xa9874a0] Unable to find a suitable output format for 'libfaac' libfaac: Invalid argument

  I found a random blog post saying you needed to add

  `-target type’

  and then specify target file type (“vcd”, “svcd”, “dvd”, “dv”, “dv50”, “pal-vcd”, “ntsc-svcd”, … ). However after trying all 8 of them listed I still got the same errors.

  I'm at a complete loss. How can I convert the 3gp video into the iphone 5 format ?

  Thanks in advance.