
Recherche avancée
Autres articles (56)
-
MediaSPIP version 0.1 Beta
16 avril 2011, parMediaSPIP 0.1 beta est la première version de MediaSPIP décrétée comme "utilisable".
Le fichier zip ici présent contient uniquement les sources de MediaSPIP en version standalone.
Pour avoir une installation fonctionnelle, il est nécessaire d’installer manuellement l’ensemble des dépendances logicielles sur le serveur.
Si vous souhaitez utiliser cette archive pour une installation en mode ferme, il vous faudra également procéder à d’autres modifications (...) -
MediaSPIP 0.1 Beta version
25 avril 2011, parMediaSPIP 0.1 beta is the first version of MediaSPIP proclaimed as "usable".
The zip file provided here only contains the sources of MediaSPIP in its standalone version.
To get a working installation, you must manually install all-software dependencies on the server.
If you want to use this archive for an installation in "farm mode", you will also need to proceed to other manual (...) -
Amélioration de la version de base
13 septembre 2013Jolie sélection multiple
Le plugin Chosen permet d’améliorer l’ergonomie des champs de sélection multiple. Voir les deux images suivantes pour comparer.
Il suffit pour cela d’activer le plugin Chosen (Configuration générale du site > Gestion des plugins), puis de configurer le plugin (Les squelettes > Chosen) en activant l’utilisation de Chosen dans le site public et en spécifiant les éléments de formulaires à améliorer, par exemple select[multiple] pour les listes à sélection multiple (...)
Sur d’autres sites (6067)
-
MobileFFMPeg Not converting mkv to Mp4
7 mai 2020, par JleeI'm currently running the following code on my device in order to convert all mkv files in a directory to an mp4. But for some reason no files are converted. I double checked the dir name and it is correct, is there something wrong with my syntax ?



let path = self.documentsDir()
let url = URL(string: path.addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed)!)
 var rc = MobileFFmpeg.execute("-i jellyfish.mkv -c:v libx264 -preset -slow -crf 22 -c:a copy youroutput.mp4")
 if (rc == RETURN_CODE_SUCCESS) {
 print("Command execution completed successfully.\n");
 } 
 else if (rc == RETURN_CODE_CANCEL) {
 print("Command execution cancelled by user.\n");
 } 
 else {
 print("Command execution failed with rc=%d and output=%@.\n", rc, MobileFFmpegConfig.getLastCommandOutput);
 }




2020-05-07 13:36:02.782150-0400 WebmBrowser[8025:138754] ERROR: /Users/jlee/Library/Developer/CoreSimulator/Devices/8CD81B87-9E27-4F3C-8601-C76945FAD4D8/data/Containers/Data/Application/B7A0D956-3BAB-4203-82EE-5FDBF38B2F13/Documents/jellyfish.mkv: Invalid data found when processing input

Command execution failed with rc=%d and output=%@.



-
Unexpected result from Python re.search for command line output
23 mai 2020, par Fernando OrtegaI'm using
subprocess.Popen
to run an ffmpeg command (in Windows) and then extract the part of the output that has the frame count with a regex expression usingre.search
. Sometimes, not always, I get the wrong result from search even if the printed command output string clearly shows what I expect.


When I use
re.findall
I get 2 results, the "wrong" one and the expected one, but in the output string of the command I still only see one option. I'd like to understand why this is happening.


Here's the code I'm running :



import re
import subprocess

# path to video with 300 frames
cmd = r'ffmpeg -i C:\...\300frames_HUD.avi -map 0:v:0 -c copy -f null -'
p = subprocess.Popen(cmd, shell=True, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
output_info = p.communicate()[0]

regex = r'(frame=\s*)([0-9]+)'
search_result = re.search(regex, output_info)
findall_result = re.findall(regex, output_info)
print "SEARCH"
print '0', search_result.group(0)
print '1', search_result.group(1)
print '2', search_result.group(2)

print "FIND ALL"
print findall_result




Here are the results I get :



SEARCH
0 frame= 293
1 frame= 
2 293
FIND ALL
[('frame= ', '293'), ('frame= ', '300')]




And here is the printed
output_info
, the ffmpeg command output I'm searching on :


ffmpeg version git-2020-03-15-c467328 Copyright (c) 2000-2020 the FFmpeg developers
 built with gcc 9.2.1 (GCC) 20200122
 configuration: --enable-gpl --enable-version3 --enable-sdl2 --enable-fontconfig --enable-gnutls --enable-iconv --enable-libass --enable-libdav1d --enable-libbluray --enable-libfreetype --enable-libmp3lame --enable-libopencore-amrnb --enable-libopencore-amrwb --enable-libopenjpeg --enable-libopus --enable-libshine --enable-libsnappy --enable-libsoxr --enable-libtheora --enable-libtwolame --enable-libvpx --enable-libwavpack --enable-libwebp --enable-libx264 --enable-libx265 --enable-libxml2 --enable-libzimg --enable-lzma --enable-zlib --enable-gmp --enable-libvidstab --enable-libvorbis --enable-libvo-amrwbenc --enable-libmysofa --enable-libspeex --enable-libxvid --enable-libaom --enable-libmfx --enable-ffnvcodec --enable-cuda-llvm --enable-cuvid --enable-d3d11va --enable-nvenc --enable-nvdec --enable-dxva2 --enable-avisynth --enable-libopenmpt --enable-amf
 libavutil 56. 42.100 / 56. 42.100
 libavcodec 58. 75.100 / 58. 75.100
 libavformat 58. 41.100 / 58. 41.100
 libavdevice 58. 9.103 / 58. 9.103
 libavfilter 7. 77.100 / 7. 77.100
 libswscale 5. 6.101 / 5. 6.101
 libswresample 3. 6.100 / 3. 6.100
 libpostproc 55. 6.100 / 55. 6.100
Input #0, avi, from 'C:\...\300frames_HUD.avi':
 Duration: 00:00:10.00, start: 0.000000, bitrate: 373255 kb/s
 Stream #0:0: Video: rawvideo, bgr24, 960x540, 374496 kb/s, 30 fps, 30 tbr, 30 tbn, 30 tbc
 Metadata:
 title : V
Output #0, null, to 'pipe:':
 Metadata:
 encoder : Lavf58.41.100
 Stream #0:0: Video: rawvideo, bgr24, 960x540, q=2-31, 374496 kb/s, 30 fps, 30 tbr, 30 tbn, 30 tbc
 Metadata:
 title : V
Stream mapping:
 Stream #0:0 -> #0:0 (copy)
Press [q] to stop, [?] for help
frame= 300 fps=0.0 q=-1.0 Lsize=N/A time=00:00:10.00 bitrate=N/A speed=19.4x 
video:455625kB audio:0kB subtitle:0kB other streams:0kB global headers:0kB muxing overhead: unknown




I'm essentially looking for the 300 number in
frame= 300
.
I can reproduce this easily when I execute it inside my IDE (pycharm) twice in a row quickly.

-
error when add arabic text to video ffmpeg c#
28 décembre 2020, par Fath Bakrii want to add Arabic annotation or text to video, i use ffmpeg version 4.3.1 in win 32 bit, here my code in c# :


private string AddVideo_Annotation(string text,int X,int Y)
 {
 try
 {

 string FFmpegPath = Utils.GetEXE_FFmpegPath();
 string path = Utils.GetProgramPath();
 //store outcome of process
 var errors = new StringBuilder();
 var output = new StringBuilder();
 var hadErrors = false;

 Process pdfprocess = new Process();

 
 //pdfprocess.StartInfo.LoadUserProfile = true;
 pdfprocess.StartInfo.RedirectStandardOutput = true;
 pdfprocess.StartInfo.RedirectStandardError = true;
 pdfprocess.StartInfo.UseShellExecute = false;
 
 pdfprocess.StartInfo.FileName = FFmpegPath;
 //text_shaping=1
 pdfprocess.StartInfo.Arguments = "-i \""+filePath+ "\" -vf -enable-libfribidi drawtext=\"text_shaping=1:text=\'" + text+ "\':x=" + X+":y="+Y+ ":fontsize=24:fontcolor=Red\" -c:a copy \"" + path + "\\out.mp4\"";
 
 //pdfprocess.StartInfo.WorkingDirectory = @"C:\Program Files\LibreOffice\program\";
 pdfprocess.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;

 pdfprocess.EnableRaisingEvents = true;

 // capture normal output
 pdfprocess.OutputDataReceived += (s, d) => {
 output.Append(d.Data);
 };

 // Capture error output
 pdfprocess.ErrorDataReceived += (s, d) => {
 if (!hadErrors)
 {
 hadErrors = !String.IsNullOrEmpty(d.Data);
 }
 errors.Append(d.Data);
 };
 pdfprocess.Start();
 pdfprocess.BeginErrorReadLine();
 pdfprocess.BeginOutputReadLine();
 try
 {
 while (pdfprocess.MainWindowHandle == IntPtr.Zero)
 {
 // Discard cached information about the process
 // because MainWindowHandle might be cached.
 pdfprocess.Refresh();
 
 Thread.Sleep(200);

 }
 }
 catch { }
 Thread.Sleep(2000);
 pdfprocess.WaitForExit();
 while ((Process.GetProcessesByName("ffmpeg").Length > 0))
 {
 Thread.Sleep(200);
 }


 string stderr = errors.ToString();

 if (pdfprocess.ExitCode != 0)
 {
 //MessageBox.Show("error:" + stderr);

 throw new Exception("FFmpeg.exe has exit wit code " + pdfprocess.ExitCode+"\n"+ stderr);
 }
 return path + "\\out"+new FileInfo( filePath).Extension;
 }
 catch(Exception ex)
 {
 TXT_AnnotationText.Text = ex.Message + "\n" + ex.StackTrace.ToString();
 MessageBox.Show(ex.Message + "\n" + ex.StackTrace.ToString());
 throw ex;
 }
 }




i get this error message :


FFmpeg.exe has exit wit code 1
ffmpeg version 4.3.1 Copyright (c) 2000-2020 the FFmpeg developers built with gcc 10.2.1 (GCC) 20200726 configuration : —enable-gpl —enable-version3 —enable-sdl2 —enable-fontconfig —enable-gnutls —enable-iconv —enable-libass —enable-libdav1d —enable-libbluray —enable-libfreetype —enable-libmp3lame —enable-libopencore-amrnb —enable-libopencore-amrwb —enable-libopenjpeg —enable-libopus —enable-libshine —enable-libsnappy —enable-libsoxr —enable-libsrt —enable-libtheora —enable-libtwolame —enable-libvpx —enable-libwavpack —enable-libwebp —enable-libx264 —enable-libx265 —enable-libxml2 —enable-libzimg —enable-lzma —enable-zlib —enable-gmp —enable-libvidstab —enable-libvmaf —enable-libvorbis —enable-libvo-amrwbenc —enable-libmysofa —enable-libspeex —enable-libxvid —enable-libaom —enable-libgsm —disable-w32threads —enable-libmfx —enable-ffnvcodec —enable-cuda-llvm —enable-cuvid —enable-d3d11va —enable-nvenc —enable-nvdec —enable-dxva2 —enable-avisynth —enable-libopenmpt —enable-amf libavutil 56. 51.100 / 56. 51.100 libavcodec 58. 91.100 / 58. 91.100 libavformat 58. 45.100 / 58. 45.100 libavdevice 58. 10.100 / 58. 10.100 libavfilter 7. 85.100 / 7. 85.100 libswscale 5. 7.100 / 5. 7.100 libswresample 3. 7.100 / 3. 7.100 libpostproc 55. 7.100 / 55. 7.100Input #0, mov,mp4,m4a,3gp,3g2,mj2, from 'D :\a.mp4' : Metadata : major_brand : mp42 minor_version : 0 compatible_brands : isommp42 creation_time : 2020-12-02T01:57:02.000000Z Duration : 00:01:37.70, start : 0.000000, bitrate : 125 kb/s Stream #0:0(eng) : Video : h264 (Main) (avc1 / 0x31637661), yuv420p(tv), 1280x662 [SAR 1:1 DAR 640:331], 124 kb/s, 30 fps, 30 tbr, 30k tbn, 60 tbc (default) Metadata : creation_time : 2020-12-02T01:57:03.000000Z handler_name : Mainconcept MP4 Video Media Handler encoder : AVC Coding[NULL @ 05d306c0] Unable to find a suitable output format for 'drawtext=text_shaping=1:text='ظٹظ„ظٹظٹظ„ ظٹظ„ظٹط¨ظ„':x=200:y=200:fontsize=24:fontcolor=Red'drawtext=text_shaping=1:text='ظٹظ„ظٹظٹظ„ ظٹظ„ظٹط¨ظ„':x=200:y=200:fontsize=24:fontcolor=Red : Invalid argument
at EasyWhatsappSender.UserControls.UControl_VideoAudioPreview_Annotation.AddVideo_Annotation(String text, Int32 X, Int32 Y) in C :\Users\FathBakri\Documents\Visual Studio 2017\Projects\MediaViewer\UserControls\UControl_VideoAudioPreview_Annotation.cs:line 239


the error happen when i use text_shaping=1 , if i omit it and use Arabic text it display in symbols and not correct
how to fix it. Thanks for help