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• What is the bitrate of my audio file based on ffmpeg output ?

  21 avril 2015, par blueether

  Is it the 40kb/s under Format, or is it the 16kb/s under Stream ? What is the relationship between the Format and the Stream ?
  The below output is for a file generated using Core Audio on an iphone, with an Audio Unit. The output format was specified by an AudioStreamBasicDescription descriptor

  Updated :
  Output from ffprobe -v error -show_format -show_streams 123_1429602551009.051025.m4a :

  [STREAM]
  
  index=0
  
  codec_name=aac
  
  codec_long_name=AAC (Advanced Audio Coding)
  
  profile=LC
  
  codec_type=audio
  
  codec_time_base=1/8000
  
  codec_tag_string=mp4a
  
  codec_tag=0x6134706d
  
  sample_fmt=fltp
  
  sample_rate=8000
  
  channels=1
  
  channel_layout=mono
  
  bits_per_sample=0
  
  id=N/A
  
  r_frame_rate=0/0
  
  avg_frame_rate=0/0
  
  time_base=1/8000
  
  start_pts=0
  
  start_time=0.000000
  
  duration_ts=43008
  
  duration=5.376000
  
  bit_rate=16501
  
  max_bit_rate=N/A
  
  bits_per_raw_sample=N/A
  
  nb_frames=42
  
  nb_read_frames=N/A
  
  nb_read_packets=N/A
  
  DISPOSITION:default=1
  
  DISPOSITION:dub=0
  
  DISPOSITION:original=0
  
  DISPOSITION:comment=0
  
  DISPOSITION:lyrics=0
  
  DISPOSITION:karaoke=0
  
  DISPOSITION:forced=0
  
  DISPOSITION:hearing_impaired=0
  
  DISPOSITION:visual_impaired=0
  
  DISPOSITION:clean_effects=0
  
  DISPOSITION:attached_pic=0
  
  TAG:creation_time=1970-04-16 22:36:01
  
  TAG:language=eng
  
  [/STREAM]
  
  [FORMAT]
  
  filename=123_1429602551009.051025.m4a
  
  nb_streams=1
  
  nb_programs=0
  
  format_name=mov,mp4,m4a,3gp,3g2,mj2
  
  format_long_name=QuickTime / MOV
  
  start_time=0.000000
  
  duration=5.376000
  
  size=27473
  
  bit_rate=40882
  
  probe_score=100
  
  TAG:major_brand=M4A
  
  TAG:minor_version=0
  
  TAG:compatible_brands=M4A mp42isom
  
  TAG:creation_time=1970-04-16 22:36:01
  
  TAG:iTunSMPB= 00000000 00000840 00000361 0000000000009C5F 00000000 00000000 00000000 00000000 00000000 00000000 00000000 00000000
  
  [/FORMAT]

• Playing RTP stream on Android 4.1.2 (Jelly Bean) [closed]

  27 décembre 2024, par Homie_Tomie

  I'll try to keep it quick. Using FFMPEG I started a stream on my PC. Here is the code :

  


  import subprocess

def start_stream():
    command = [
        'ffmpeg',
        '-f', 'gdigrab',  # Desktop capture (Windows)
        '-framerate', '15',  # Low framerate for higher performance
        '-i', 'desktop',  # Capture desktop
        '-c:v', 'libx264',  # Video codec (H.264)
        '-preset', 'ultrafast',  # Ultra-fast encoding preset for minimal latency
        '-tune', 'zerolatency',  # Zero latency for real-time streaming
        '-x264opts', 'keyint=15:min-keyint=15:no-scenecut',  # Frequent keyframes
        '-b:v', '500k',  # Low bitrate to minimize data usage and reduce latency
        '-s', '800x480',  # Resolution fits phone screen and helps performance
        '-max_delay', '0',  # No buffering, instant frame output
        '-flush_packets', '1',  # Flush packets immediately after encoding
        '-f', 'rtp',  # Use mpegts as the container for RTP stream
        'rtp://192.168.72.26:1234',  # Stream over UDP to localhost on port 1234
        '-sdp_file', 'stream.sdp'  # Create SDP file
    ]
    
    try:
        print("Starting stream...")
        subprocess.run(command, check=True)
    except subprocess.CalledProcessError as e:
        print(f"Error occurred: {e}")
    except KeyboardInterrupt:
        print("\nStream interrupted")

if __name__ == "__main__":
    print("Starting screen capture...")
    start_stream()


  


  Now, when I start the stream I can connect to it in VLC when I open up the stream.sdp file. Using the same method I can open up the stream on my iPhone, but when I try to open it on my old Android phone the stream connects but the screen is black. However, when I turn the screen I can see the first frame that was sent to the phone. Why does the stream not work ?

  


  I will be thankful for any and all advice :)

  


• poster adjustment after getting it from video

  30 juin 2016, par Jass

  I am capturing poster from this video https://www.youtube.com/watch?v=wg-kEWsL6Xc using following code. Video can be any, I am just giving example.

  shell_exec('ffmpeg -y  -itsoffset -4  -i "'.base_path().'/assets/videos/'.$file_name.'.mp4" -vcodec mjpeg -vframes 1 -an -f rawvideo -filter:v scale=1170:ih*1170/iw "'.base_path().'/assets/videos/thumbnail/'.$file_name.'.jpg"')

  Width = 1170px,

  Height= 300px (as it is background image so it does not matter)

  But I am facing adjustment problem. Following are my current views

  First : Head is cutting, here I am using css property background : url(’completepath’) center no-repeat ;
  

  Second : Showing black portion on top of head. This is the original image that I am getting from ffmpeg code.

  

  My Question : But I need image like in you tube, you can notice that in all videos we can see top portion of humans without being cutting even black portion is well adjusted.

  Currently I am downloading and testing with youtube videos but in actual job seekers will make their own videos using android/iphone or any camera and will upload on our site.

  so how i can overcome this issue means show image with proper human face and body ?

  thanks in advance.