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  • Les autorisations surchargées par les plugins

    27 avril 2010, par

    Mediaspip core
    autoriser_auteur_modifier() afin que les visiteurs soient capables de modifier leurs informations sur la page d’auteurs

  • Support audio et vidéo HTML5

    10 avril 2011

    MediaSPIP utilise les balises HTML5 video et audio pour la lecture de documents multimedia en profitant des dernières innovations du W3C supportées par les navigateurs modernes.
    Pour les navigateurs plus anciens, le lecteur flash Flowplayer est utilisé.
    Le lecteur HTML5 utilisé a été spécifiquement créé pour MediaSPIP : il est complètement modifiable graphiquement pour correspondre à un thème choisi.
    Ces technologies permettent de distribuer vidéo et son à la fois sur des ordinateurs conventionnels (...)

  • HTML5 audio and video support

    13 avril 2011, par

    MediaSPIP uses HTML5 video and audio tags to play multimedia files, taking advantage of the latest W3C innovations supported by modern browsers.
    The MediaSPIP player used has been created specifically for MediaSPIP and can be easily adapted to fit in with a specific theme.
    For older browsers the Flowplayer flash fallback is used.
    MediaSPIP allows for media playback on major mobile platforms with the above (...)

Sur d’autres sites (7083)

  • Record video stream in rust

    19 novembre 2024, par El_Loco

    I have bought a stereo camera with global shutter and a frame rate of at most 120 fps. https://www.amazon.com/dp/B0D8T3ZSL4?ref_=pe_386300_442618370_TE_sc_as_ri_0#

    


    My next step is to write a program that can show and record a video with desired fps and resolution.

    


    use opencv::{&#xA;    core, highgui,&#xA;    prelude::*,&#xA;    videoio::{self, VideoCapture},&#xA;    Result,&#xA;};&#xA;&#xA;fn open_camera() -> Result<videocapture> {&#xA;    let capture = videoio::VideoCapture::new(2, videoio::CAP_ANY)?;&#xA;    return Ok(capture);&#xA;}&#xA;fn main() -> Result&lt;()> {&#xA;    let window = "video capture";&#xA;    highgui::named_window(window, highgui::WINDOW_AUTOSIZE)?;&#xA;    let mut cam = open_camera()?;&#xA;    let opened = videoio::VideoCapture::is_opened(&amp;cam)?;&#xA;    if !opened {&#xA;        panic!("Unable to open default camera!");&#xA;    }&#xA;    let width = 3200.0;&#xA;    let height = 1200.0;&#xA;    cam.set(videoio::CAP_PROP_FRAME_WIDTH, width)?;&#xA;    cam.set(videoio::CAP_PROP_FRAME_HEIGHT, height)?;&#xA;&#xA;    // Set the frame rate (FPS)&#xA;    let fps = 60.0;&#xA;        &#xA;    let fourcc = videoio::VideoWriter::fourcc(&#x27;M&#x27;, &#x27;J&#x27;, &#x27;P&#x27;, &#x27;G&#x27;)?;&#xA;    let mut writer = videoio::VideoWriter::new(&#xA;        "video_output.avi",&#xA;        fourcc,&#xA;        fps,&#xA;        core::Size::new(width as i32, height as i32),&#xA;        true,&#xA;    )?;&#xA;&#xA;    if !writer.is_opened()? {&#xA;        println!("Error: Could not open the video writer.");&#xA;    }&#xA;&#xA;    let mut frame = core::Mat::default();&#xA;    let mut ctr = 0;&#xA;    while cam.read(&amp;mut frame)? {&#xA;        if frame.empty() {&#xA;            break;&#xA;        }&#xA;        writer.write(&amp;frame)?;&#xA;        highgui::imshow(window, &amp;frame)?;&#xA;        &#xA;        let key = highgui::wait_key(1)?;&#xA;        if key > 0 {&#xA;            break;&#xA;        }&#xA;        ctr &#x2B;= 1;&#xA;        if ctr == 600 {&#xA;            break;&#xA;        }&#xA;    }&#xA;    cam.release()?;&#xA;    writer.release()?;&#xA;    Ok(())&#xA;}&#xA;</videocapture>

    &#xA;

    When I run this code the frame rate is terrible. Like 1 fps or something. For debugging I tried to run in cheese. There I got 30 fps with full resolution 3200x1200. But I cannot change the fps to 60 fps what I can see.

    &#xA;

    Then I tried to capture a video using ffmpeg :

    &#xA;

    ffmpeg -f v4l2 -framerate 60 -video_size 3200x1200 -i /dev/video2 output.mp4

    &#xA;

    With the following output :

    &#xA;

    [video4linux2,v4l2 @ 0x5a72cbbd1400] The driver changed the time per frame from 1/60 to 1/2&#xA;Input #0, video4linux2,v4l2, from &#x27;/dev/video2&#x27;:&#xA;  Duration: N/A, start: 2744.250608, bitrate: 122880 kb/s&#xA;  Stream #0:0: Video: rawvideo (YUY2 / 0x32595559), yuyv422, 3200x1200, 122880 kb/s, 2 fps, 2 tbr, 1000k tbn&#xA;File &#x27;output.mp4&#x27; already exists. Overwrite? [y/N]&#xA;

    &#xA;

    The frame rate is lowered to 2 fps.

    &#xA;

    Then I tried to run v4l2-ctl --list-formats-ext -d 2 with the following output :

    &#xA;

    ioctl: VIDIOC_ENUM_FMT&#xA;        Type: Video Capture&#xA;&#xA;        [0]: &#x27;MJPG&#x27; (Motion-JPEG, compressed)&#xA;                Size: Discrete 3200x1200&#xA;                        Interval: Discrete 0.017s (60.000 fps)&#xA;                        Interval: Discrete 0.033s (30.000 fps)&#xA;                        Interval: Discrete 0.040s (25.000 fps)&#xA;                        Interval: Discrete 0.050s (20.000 fps)&#xA;                        Interval: Discrete 0.067s (15.000 fps)&#xA;                        Interval: Discrete 0.100s (10.000 fps)&#xA;                Size: Discrete 2560x720&#xA;                        Interval: Discrete 0.017s (60.000 fps)&#xA;                        Interval: Discrete 0.033s (30.000 fps)&#xA;                        Interval: Discrete 0.040s (25.000 fps)&#xA;                        Interval: Discrete 0.050s (20.000 fps)&#xA;                        Interval: Discrete 0.067s (15.000 fps)&#xA;                        Interval: Discrete 0.100s (10.000 fps)&#xA;                Size: Discrete 1600x600&#xA;                        Interval: Discrete 0.008s (120.000 fps)&#xA;                        Interval: Discrete 0.017s (60.000 fps)&#xA;                        Interval: Discrete 0.033s (30.000 fps)&#xA;                        Interval: Discrete 0.040s (25.000 fps)&#xA;                        Interval: Discrete 0.050s (20.000 fps)&#xA;                        Interval: Discrete 0.067s (15.000 fps)&#xA;

    &#xA;

    I then tried to open the camera using qv4land there it seemed to work. Does not seem like I can record a video though.

    &#xA;

    I am using Rust to learn. I want to be able to programmatically be able to record a video somehow and then do computer vision. The easiest would be to do it in Rust. But other solutions are ok.

    &#xA;

    Edit&#xA;I have found some more this morning :

    &#xA;

    v4l2-ctl -d 2 --list-formats-ext&#xA;ioctl: VIDIOC_ENUM_FMT&#xA;    Type: Video Capture&#xA;&#xA;    [0]: &#x27;MJPG&#x27; (Motion-JPEG, compressed)&#xA;        Size: Discrete 3200x1200&#xA;            Interval: Discrete 0.017s (60.000 fps)&#xA;            Interval: Discrete 0.033s (30.000 fps)&#xA;            Interval: Discrete 0.040s (25.000 fps)&#xA;            Interval: Discrete 0.050s (20.000 fps)&#xA;            Interval: Discrete 0.067s (15.000 fps)&#xA;            Interval: Discrete 0.100s (10.000 fps)&#xA;&#xA;    [1]: &#x27;YUYV&#x27; (YUYV 4:2:2)&#xA;        Size: Discrete 3200x1200&#xA;            Interval: Discrete 0.500s (2.000 fps)&#xA;        Size: Discrete 2560x720&#xA;            Interval: Discrete 0.500s (2.000 fps)&#xA;        Size: Discrete 1600x600&#xA;            Interval: Discrete 0.100s (10.000 fps)&#xA;

    &#xA;

    I also found here that order of flags was important for ffmpeg. Running this I can actually record a video with 60 fps :

    &#xA;

    ffmpeg -framerate 60 -f v4l2 -video_size 3200x1200 -input_format mjpeg  -i /dev/video2 output.avi

    &#xA;

    A drawback is that the images does not look very sharp. You can clearly see the pixels. (I am new to video formats etc as well. Before it has just worked.)

    &#xA;

    If I change from avito mkvit is slow again.

    &#xA;

    In the link above I also saw a suggestion to first do :

    &#xA;

    ffmpeg -framerate 60 -f v4l2 -video_size 3200x1200 -input_format mjpeg  -i /dev/video2 -c copy mjpeg.mkv

    &#xA;

    and then :

    &#xA;

    ffmpeg -i mjpeg.mkv -c:v libx264 -crf 23 -preset medium -pix_fmt yuv420p out.mkv

    &#xA;

    which worked. But I am not sure those flags are ideal for the camera I have. I think it is a good start to make it run as expected using command line and ffmpeg. So I know what format to use and that it actually works as intended before doing it programmatically.

    &#xA;

  • Can I convert a django video upload from a form using ffmpeg before storing the video ?

    5 mai 2014, par GetItDone

    I’ve been stuck for weeks trying to use ffmpeg to convert user uploaded videos to flv. I use heroku to host my website, and store my static and media files on amazon S3 with s3boto. The initial video file will upload fine, however when I retrieve the video and run a celery task (in the same view where the initial video file is uploaded), the new file won’t store on S3. I’ve been trying to get this to work for over a month, with no luck, and really no good resources available for learning how to do this, so I figure maybe if I can get the ffmpeg task to run before storing the video I may be able to get it to work. Unfortunately I’m still not a very advanced at python (or django), so I don’t even know if/how this is possible. Anyone have any ideas ? I am willing to use any solution at this point no matter how ugly, as long as it successfully takes video uploads and converts to flv using ffmpeg, with the resulting file being stored on S3. It doesn’t seem that my situation is very common, because no matter where I look, I cannot find a solution that explains what I should be trying to do. Therefore I will be very appreciative of any guidance. Thanks. My relevant code follows :

    #models.py
    def content_file_name(instance, filename):
       ext = filename.split('.')[-1]
       new_file_name = "remove%s.%s" % (uuid.uuid4(), ext)
       return '/'.join(['videos', instance.teacher.username, new_file_name])

    class BroadcastUpload(models.Model):
       title = models.CharField(max_length=50, verbose_name=_('Title'))
       description = models.TextField(max_length=100, verbose_name=_('Description'))
       teacher = models.ForeignKey(User, null=True, blank=True, related_name='teacher')
       created_date = models.DateTimeField(auto_now_add=True)
       video_upload = models.FileField(upload_to=content_file_name)
       flvfilename = models.CharField(max_length=100, null=True, blank=True)
       videothumbnail = models.CharField(max_length=100, null=True, blank=True)

    #tasks.py
    @task(name='celeryfiles.tasks.convert_flv')
    def convert_flv(video_id):
       video = BroadcastUpload.objects.get(pk=video_id)
       print "ID: %s" % video.id
       id = video.id
       print "VIDEO NAME: %s" % video.video_upload.name
       teacher = video.teacher
       print "TEACHER: %s" % teacher
       filename = video.video_upload
       sourcefile = "%s%s" % (settings.MEDIA_URL, filename)
       vidfilename = "%s_%s.flv" % (teacher, video.id)
       targetfile = "%svideos/flv/%s" % (settings.MEDIA_URL, vidfilename)
       ffmpeg = "ffmpeg -i %s %s" % (sourcefile, vidfilename)
       try:
           ffmpegresult = subprocess.call(ffmpeg)
           #also tried separately with following line:
           #ffmpegresult = commands.getoutput(ffmpeg)
           print "---------------FFMPEG---------------"
           print "FFMPEGRESULT: %s" % ffmpegresult
       except Exception as e:
           ffmpegresult = None
           print("Failed to convert video file %s to %s" % (sourcefile, targetfile))
           print(traceback.format_exc())
       video.flvfilename = vidfilename
       video.save()

    @task(name='celeryfiles.tasks.ffmpeg_image')        
    def ffmpeg_image(video_id):
       video = BroadcastUpload.objects.get(pk=video_id)
       print "ID: %s" %video.id
       id = video.id
       print "VIDEO NAME: %s" % video.video_upload.name
       teacher = video.teacher
       print "TEACHER: %s" % teacher
       filename = video.video_upload
       sourcefile = "%s%s" % (settings.MEDIA_URL, filename)
       imagefilename = "%s_%s.png" % (teacher, video.id)
       thumbnailfilename = "%svideos/flv/%s" % (settings.MEDIA_URL, thumbnailfilename)
       grabimage = "ffmpeg -y -i %s -vframes 1 -ss 00:00:02 -an -vcodec png -f rawvideo -s 320x240 %s" % (sourcefile, thumbnailfilename)
       try:        
            videothumbnail = subprocess.call(grabimage)
            #also tried separately following line:
            #videothumbnail = commands.getoutput(grabimage)
            print "---------------IMAGE---------------"
            print "VIDEOTHUMBNAIL: %s" % videothumbnail
       except Exception as e:
            videothumbnail = None
            print("Failed to convert video file %s to %s" % (sourcefile, thumbnailfilename))
            print(traceback.format_exc())
       video.videothumbnail = imagefilename
       video.save()

    #views.py
    def upload_broadcast(request):
       if request.method == 'POST':
           form = BroadcastUploadForm(request.POST, request.FILES)
           if form.is_valid():
               upload=form.save()
               video_id = upload.id
               image_grab = ffmpeg_image.delay(video_id)
               video_conversion = convert_flv.delay(video_id)
               return HttpResponseRedirect('/current_classes/')
       else:
           form = BroadcastUploadForm(initial={'teacher': request.user,})
       return render_to_response('videos/create_video.html', {'form': form,}, context_instance=RequestContext(request))

    #settings.py
    DEFAULT_FILE_STORAGE = 'myapp.s3utils.MediaRootS3BotoStorage'
    DEFAULT_S3_PATH = "media"
    STATICFILES_STORAGE = 'myapp.s3utils.StaticRootS3BotoStorage'
    STATIC_S3_PATH = "static"
    AWS_STORAGE_BUCKET_NAME = 'my_bucket'
    CLOUDFRONT_DOMAIN = 'domain.cloudfront.net'
    AWS_ACCESS_KEY_ID = 'MY_KEY_ID'
    AWS_SECRET_ACCESS_KEY = 'MY_SECRET_KEY'
    MEDIA_ROOT = '/%s/' % DEFAULT_S3_PATH
    MEDIA_URL = 'http://%s/%s/' % (CLOUDFRONT_DOMAIN, DEFAULT_S3_PATH)
    ...

    #s3utils.py
    from storages.backends.s3boto import S3BotoStorage
    from django.utils.functional import SimpleLazyObject

    StaticRootS3BotoStorage = lambda: S3BotoStorage(location='static')
    MediaRootS3BotoStorage  = lambda: S3BotoStorage(location='media')

    I can add any other info if needed to help me solve my problem.

  • how to implement streaming feautre on our website

    14 février 2023, par Mohamed Taha

    we are building a website -for education purpose -and want to add streaming function on it

    &#xA;

    our website like a social media platform so someone want to strat streaming (the media will be either from camera or screen sharing )

    &#xA;

    from where i can start

    &#xA;

    i have searched about this topic and i arrived at knowing the theortical steps to stream video&#xA;_ capture ,encoding , mixin ,send to server&#xA;but though i don't know where to start too

    &#xA;

    i found tool called FFmpeg can do this but on windows platform and i think won't help.

    &#xA;