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• Converting video with ffmpeg from a script not in the root folder

  30 octobre 2017, par Daniel Ormerod

  I am using ffmpeg to convert videos, create thumbnails etc.

  I made the below function to convert a video and when I run it in a script in the root folder it converts ok.

  However, I am using ajax to upload the video and the script is located /ajax/upload-video.php and when I run it in that folder it fails to convert.

  I have tried sending the $src and $dest up with ../ before the filenames to go back a folder but it isn’t working.

  Can anybody help ?

  Do I need to add something to the $command line to tell it to go back a folder ?

  These are the variables being used in the function :

  $ffmpegpath = 'ffmpeg.exe';
  
  $src = 'videos/video1.wmv';
  
  $dest = 'videos/video1.mp4';

  I have tried :

  $ffmpegpath = 'ffmpeg.exe';
  
  $src = '../videos/video1.wmv';
  
  $dest = '../videos/video1.mp4';

  And the function :

  function convert_video($src, $dest) {
  
  
  
      global $ffmpegpath;
  
  
  
      if (!file_exists($src)) {
  
  
  
          echo '<p>The file does not exist</p>';
  
  
  
      } else {
  
  
  
          $command = "$ffmpegpath -i $src $dest";
  
  
  
          @exec($command, $ret);
  
  
  
          if (!file_exists($dest)) {
  
  
  
              echo '<p>The file failed to create</p>';
  
  
  
          } else {
  
  
  
              if (filesize($dest)==0) {
  
  
  
                  echo '<p>The file created but has not filesize</p>';
  
  
  
              } else {
  
  
  
                  echo '<p>File Created Successfully</p>';
  
  
  
              }
  
  
  
          }
  
  
  
      }
  
  
  
  }

• Script bash to compress .mp4 with subfolders and another destination folder

  28 octobre 2017, par Aurélien Péruchon

  I’m trying to create a script to convert all .mp4 videos into subfolders.
  My hierarchy is :

  Folder_1/
   Videos_encoded/
   Videos_orig/
   first-video.mp4
   video_2/
   video-in-folder-video_2.mp4

  I want to compress all .mp4 (with into subfolders) are in the Videos-orig/ to the videos_encoded as the destination folder.

  I tried :

  find /home/user/Folder_1/videos_orig/ -type d | while read ligne     
  
  do  
  
  cd "$ligne"          
  
     for i in *.mp4;
  
      do 
  
         ffmpeg -y -i "$i" -ar 44100 -c:v libx265 -b:v 1000 -c:a mp3 -b:a 128k /home/user/Folder_1/videos_encoded"$(basename "${i/.mp4}").mp4"
  
      done     
  
  done

  But I have the error message : **.mp4 no such file or directory* (result of ffmpeg command).

  I don’t understand ...

  There is it a better way to perform this project ?

  Thanks you very much in advance for your help :)

  Regards

• ffmpeg program doesn't running on shell script with java Application

  20 octobre 2017, par Hae-Yoon Jo

  I code java Application and running Linux shell-script when java App running on Linux server.
  The linux shell-script is running. But, i need runnning ffmpeg program by shell.

  1. the ffmpeg is running with shell-script command by ./shellName.sh

  2. ffmpeg is not running with java App run by .

     • only ffmpeg command in shell.
     • working mkdir command
     • working pwd command

  #!/bin/bash
  
  echo -n "ffmpeg cmd :"
  
      /home/popsline/ffmpeg -i /home/popsline/sub02_chocolat.mp4 -r 0.14 -ss 00:00:20 -t 10:00:00 -vframes 10 -f image2 -y /home/popsline/img/iamges%d.png
  
  mkdir /home/username/test
  
  pwd

  Java code.

  HomeController.java refer sh.java as Object.
  so codes is follows :

  HomeController.java

  /**
  
   * Simply selects the home view to render by returning its name.
  
   */
  
  @RequestMapping(value = "/", method = RequestMethod.GET)
  
  public String home(Locale locale, Model model) {
  
      logger.info("Welcome home! The client locale is {}.", locale);
  
  
  
      Sh sh = new Sh();
  
      sh.shRun();
  
  
  
      return "home";
  
  }

  sh.java

  private static final Logger logger = LoggerFactory.getLogger(HomeController.class);
  
  
  
  public void shRun(){
  
  
  
      Runtime rt = Runtime.getRuntime();
  
      Process proc = null;
  
      InputStream is = null;
  
      BufferedReader bf = null;
  
  
  
      try {
  
          String[] cmd = {
  
                  "/bin/sh"
  
                  , "-c"
  
                  , "/usr/local/bin/creaThum.sh"
  
          };
  
  
  
          proc = rt.exec(cmd);
  
          proc.getInputStream();
  
          is = proc.getInputStream();
  
          bf = new BufferedReader(new InputStreamReader(is));
  
  
  
          while (true) {
  
              String info = bf.readLine();
  
              if(info == null || info.equals("")){
  
                  break;
  
              }
  
              logger.info("info haeyoon:: " + info);
  
          }
  
      } catch (Exception e) {
  
          logger.info(e.getMessage());
  
      }
  
  }