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Médias (16)

Mot : - Tags -/mp3

Autres articles (64)

  • Publier sur MédiaSpip

    13 juin 2013

    Puis-je poster des contenus à partir d’une tablette Ipad ?
    Oui, si votre Médiaspip installé est à la version 0.2 ou supérieure. Contacter au besoin l’administrateur de votre MédiaSpip pour le savoir

  • Support de tous types de médias

    10 avril 2011

    Contrairement à beaucoup de logiciels et autres plate-formes modernes de partage de documents, MediaSPIP a l’ambition de gérer un maximum de formats de documents différents qu’ils soient de type : images (png, gif, jpg, bmp et autres...) ; audio (MP3, Ogg, Wav et autres...) ; vidéo (Avi, MP4, Ogv, mpg, mov, wmv et autres...) ; contenu textuel, code ou autres (open office, microsoft office (tableur, présentation), web (html, css), LaTeX, Google Earth) (...)

  • HTML5 audio and video support

    13 avril 2011, par

    MediaSPIP uses HTML5 video and audio tags to play multimedia files, taking advantage of the latest W3C innovations supported by modern browsers.
    The MediaSPIP player used has been created specifically for MediaSPIP and can be easily adapted to fit in with a specific theme.
    For older browsers the Flowplayer flash fallback is used.
    MediaSPIP allows for media playback on major mobile platforms with the above (...)

Sur d’autres sites (8894)

  • Celery to process task and modify the model fields

    15 juillet 2015, par Robin

    I would like to convert video into mp4 using ffmpeg and celery for the asynchronous task. When user uploads a video, it will be for the original_video and save it. After that I want celery to convert it into a different version for the mp4_720 field. However I am confused on how to apply that logic using celery.

    app.models.py :

    class Video(models.Model):
       title = models.CharField(max_length=75)
       pubdate = models.DateTimeField(default=timezone.now)
       original_video = models.FileField(upload_to=get_upload_file_name)
       mp4_720 = models.FileField(upload_to=get_upload_file_name, blank=True, null=True)
       converted = models.BooleanField(default=False)

    app.views.py :

    def upload_video(request):
       if request.POST:
           form = VideoForm(request.POST, request.FILES)
           if form.is_valid():
               video = form.save(commit=False)
               video.save()

               // Celery to convert the video
               convert_video.delay(video)

               return HttpResponseRedirect('/')
       else:
           form = VideoForm()
       return render(request, 'upload_video.html', {
           'form':form
       })

    app.tasks.py :

    @app.task
    def convert_video(video):

       // Convert the original video into required format and save it in the mp4_720 field using the following command:
       //subprocess.call('ffmpeg -i (path of the original_video) (video for mp4_720)')

       // Change the converted boolean field to True

       // Save

    Basically my question is how to save the converted video in mp4_720. Your help and guidance will be very much appreciated. Thank you.

    ** update **

    What I want that method to do is first convert the video.original_video and then save the converted video in the video.mp4_720 field. If all has been done correctly, change the video.converted to True. How do I define the method to do so ?

  • Convert wma stream to mp3 stream with C# and ffmpeg

    24 septembre 2012, par user1363468

    Is it possible to convert a wma stream to an mp3 stream real time ?

    I have tried doing something like this but not having any luck :

       WebRequest request = WebRequest.Create(wmaUrl);
       HttpWebResponse response = (HttpWebResponse)request.GetResponse();
       int block = 32768;
       byte[] buffer = new byte[block];

       Process p = new Process();
       p.StartInfo.UseShellExecute = false;
       p.StartInfo.ErrorDialog = false;
       p.StartInfo.RedirectStandardInput = true;
       p.StartInfo.RedirectStandardOutput = true;
       p.StartInfo.RedirectStandardError = true;
       p.StartInfo.FileName = "c:\\ffmpeg.exe";
       p.StartInfo.Arguments = "-i - -y -vn -acodec libspeex -ac 1 -ar 16000 -f mp3 ";

       StringBuilder output = new StringBuilder();

       p.OutputDataReceived += (sender, e) =>
       {
         if (e.Data != null)
         {
           output.AppendLine(e.Data);
           //eventually replace this with response.write code for a web request
         }
       };

       p.Start();
       StreamWriter ffmpegInput = p.StandardInput;

       p.BeginOutputReadLine();

       using (Stream dataStream = response.GetResponseStream())
       {
          int read = dataStream.Read(buffer, 0, block);

          while (read > 0)
          {
             ffmpegInput.Write(buffer);
             ffmpegInput.Flush();
             read = dataStream.Read(buffer, 0, block);
          }
       }

       ffmpegInput.Close();

       var getErrors = p.StandardError.ReadToEnd();

    Just wondering if what I am trying to do is even possible (Convert byte blocks of wma to byte blocks of mp3). Open to any other possible C# solutions if they exist.

    Thanks

  • Streaming FFMPEG RTSP in C#

    1er mars 2015, par Andrew Simpson

    I wish to stream an RTSP feed from my camera through my C# client app and eventually recieve it on my server.

    To test it I decided to stream it through my client and then recieve the jpeg frames from it as well.

    I 1st tested my command line arguments in a DOS window.

    It worked in that it stream to an output file without incident.

    So, now I ported it over to my C# app and used the Process Class.

    This is the code :

      Task.Run(() =>
       {
           try
           {
               process.Start();
               byte[] buffer = new byte[200000];
               baseStream = process.StandardOutput.BaseStream as FileStream;
               bool gotHeader = false;
               bool imgFound = false;
               int counter = 0;
               while (true)
               {
                   byte bit1 = (byte)baseStream.ReadByte();
                   buffer[counter] = bit1;
                   if (bit1 == 217 && gotHeader)
                   {
                       if (buffer[counter - 1] == 255)
                       {
                           byte[] jpeg = new byte[counter];
                           Buffer.BlockCopy(buffer, 0, jpeg, 0, counter);
                           using (MemoryStream ms = new MemoryStream(jpeg))
                           {
                               pictureBox1.Image = Image.FromStream(ms);
                               ms.Close();
                           }
                           imgFound = true;
                       }
                   }
                   else if (bit1 == 216)
                   {
                       if (buffer[counter - 1] == 255)
                       {
                           gotHeader = true;
                       }
                   }
                   if (imgFound)
                   {
                       counter = 0;
                       buffer = new byte[200000];
                       imgFound = false;
                       gotHeader = false;
                   }
                   else
                   {
                       counter++;
                   }
               }
           }
           catch (Exception ex2)
           {
               //log error here
           }
       });

    But I do not get any images I just get the byte value of 255 at this line :

    buffer[counter] = bit1;

    So.. what am I doing wrong please ?

    Thanks