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Sur d’autres sites (4394)
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Revision 45367 : [source:_plugins_/step Step]. Deux déclarations conditionnelles pour ...
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Downloader downloads high quality video but muted
5 avril 2023, par Stef-LevI have created a next.js video downloader and I want to download videos of the highest quality. When I trigger the download I only get a muted mp4 file (in high quality) and a muted mp3 file. Here is the api file. How could I download the video, the audio and then merge them with ffmpeg correctly ?


import ytdl from "ytdl-core";
import fs from "fs";
import { Server } from "socket.io";
import ffmpeg from "fluent-ffmpeg";

export default async function handler(req, res) {
 if (res.socket.server.io) {
 console.log("Socket is already running");
 res.end();
 return;
 }
 console.log("Socket is initializing");
 const io = new Server(res.socket.server);
 res.socket.server.io = io;

 io.on("connection", async (socket) => {
 console.log(socket.id, "socketID");

 const sendError = async (msg) => {
 socket.emit("showError", msg);
 };

 const sendProgress = async (msg) => {
 console.log(msg);
 socket.emit("showProgress", msg);
 };

 const sendComplete = async (msg) => {
 console.log(msg);
 socket.emit("showComplete", msg);
 };

 const downloadVideo = async (url) => {
 try {
 const videoInfo = await ytdl.getInfo(url);
 const outputPath = path.join(
 process.cwd(),
 "mp4s",
 `${videoInfo.videoDetails.title}.mp4`
 );
 const audioPath = path.join(
 process.cwd(),
 "mp4s",
 `${videoInfo.videoDetails.title}.mp3`
 );

 const videoFormat = ytdl.chooseFormat(videoInfo.formats, {
 quality: "highestvideo",
 filter: "videoonly",
 });
 const audioFormat = ytdl.chooseFormat(videoInfo.formats, {
 quality: "highestaudio",
 filter: "audioonly",
 });
 const videoStream = ytdl(url, { quality: videoFormat.itag });
 const audioStream = ytdl(url, { quality: audioFormat.itag });

 const videoOutput = fs.createWriteStream(outputPath);
 const audioOutput = fs.createWriteStream(audioPath);

 audioStream.pipe(audioOutput);
 videoStream.pipe(videoOutput);

 let downloadedBytes = 0;
 let totalBytes =
 videoFormat.contentLength || videoInfo.length_seconds * 1000000;

 videoOutput.on("data", (chunk) => {
 downloadedBytes += chunk.length;
 const progress = Math.round((downloadedBytes / totalBytes) * 100);
 sendProgress({ progress });
 });

 videoOutput.on("error", (err) => {
 console.error(err);
 sendError({
 status: "error",
 message: "An error occurred while writing the video file",
 });
 });

 audioOutput.on("error", (err) => {
 console.error(err);
 sendError({
 status: "error",
 message: "An error occurred while writing the audio file",
 });
 });

 videoOutput.on("finish", () => {
 audioOutput.on("finish", () => {
 if (fs.existsSync(outputPath) && fs.existsSync(audioPath)) {
 const outputFile = path.join(
 process.cwd(),
 "mp4s",
 `${videoInfo.videoDetails.title}-with-audio.mp4`
 );
 const command = ffmpeg()
 .input(outputPath)
 .input(audioPath)
 .outputOptions("-c:v copy")
 .outputOptions("-c:a aac")
 .outputOptions("-b:a 192k")
 .outputOptions("-strict -2")
 .output(outputFile)
 .on("end", () => {
 fs.unlink(outputPath, () => {});
 fs.unlink(audioPath, () => {});
 sendComplete({
 status: "success",
 });
 })
 .on("error", (err) => {
 console.error("ffmpeg error:", err.message);
 sendError({
 status: "error",
 message:
 "An error occurred while processing the audio and video files",
 });
 });
 command.run();
 } else {
 console.error("Output or audio file not found");
 sendError({
 status: "error",
 message: "Output or audio file not found",
 });
 }
 });
 });
 } catch (error) {
 console.error(error);
 sendError({
 status: "error",
 message: "An error occurred while downloading the video",
 });
 }
 };
 socket.on("downloadVideo", downloadVideo);
 });
 res.end();
}



I am also using socket.io to show the progress in the frontend, but for some reason I don't get the progress correctly. Is it possible to do that ?