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• How to run a command in python with file paths containing spaces ?

  24 juillet 2023, par tomatochan

  I'm developing a program in Python that requires the use of FFMPEG. In one step, I need to create a video from a text file containing the list of images (path and duration) that need to be assembled to make a video. To do this, I use the following code :

  


  cmd = [ffmpeg, "-y", "-f", "concat", "-safe", "0", "-i", tmp, "-c:v", "libx264", "-r", "25", "-pix_fmt", "yuv420p", out]
subprocess.run(cmd)
# os.system(" ".join(cmd)) # returns same error


  


  What returns the error : The syntax of the file, directory or volume name is incorrect.

  


  I know that paths can be problematic when they contain spaces, and as my username has one, I've taken care to quote the paths in such a way that :

  


  ffmpeg = '"C:\Users\John Doe\Documents\ffmpeg\bin\ffmpeg.exe"'
tmp = '"C:\Users\John Doe\Desktop\path\to\file.txt"'
out = '"C:\Users\John Doe\Desktop\path\to\video.mp4"'


  


  When I print(" ".join(cmd)), this is what I get in my terminal :

  


  "C:\Users\John Doe\Documentsffmpeg\binffmpeg.exe" -y -f concat -safe 0 -i "C:\Users\John Doe\Desktop\path\to\file.txt" -c:v libx264 -r 25 -pix_fmt yuv420p "C:\Users\John Doe\Desktop\path\to\video.mp4"


  


  However, the problem persists.
Has anyone ever had this problem and managed to solve it ?

  


  I've also tried the method where you have to escape the spaces (taking care to replace the \ with / and then the with \ ) but nothing works... The error persists.

  


  For your information, here are the contents of one of my .txt files

  


  file C:\Users\John Doe\Desktop\path\to\image_1.png
duration 0.04
file C:\Users\John Doe\Desktop\path\to\image_2.png
duration 0.04
file C:\Users\John Doe\Desktop\path\toimage_3.png
duration 0.04


  


  When I quote the paths in the .txt files

  


  

  • subprocess gives me the error :
PermissionError: [WinError 5] Access denied

  


  • os.system gives me the error :

  


  


  C:\Users\John' is not recognized as an internal or external command, an executable program or a command file.
The syntax of the file, directory or volume name is incorrect.


  


• Requesting header information of a file

  11 janvier 2012, par 0v3rrid3

  is there anyway I can request only the header information of any media. For example I just want to request header information of any video file so as to find its video length. I tried using ffmpeg -i {video_url} and did the work but I noticed that it actually downloads the given media in local storage and returns back the header information which obviously increases roundtrip time.

  So I would really appreciate if there is any idea for finding the length of media in a fly. BTW I have a ruby on rails application where I need to implement this.

• ffmpeg watermark

  8 mai 2018, par tomi

  I am using a static compiled lib of FFMPEG gotten from BAMBUSER for android.
  The problem I am facing now is that FFMPEG version gotten from BAMBUSER does not support watermarking.

  ffmpeg -sameq -i mirror_watermark.mp4 -vf "movie=mirror_watermark.png [logo]; [in][logo] overlay=main_w-overlay_w:main_h-overlay_h [out]" output.mp4
  
  No such filter: 'movie'
  
  
  
  ./configure --list-filters | grep movie
  
  returns nothing

  So I guess I have to use a newer version of FFMPEG but I do not know how to get started since with the BAMBUSER everything was already set I just added certain encoders and decoders to their script.