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• Anomalie #4729 (Nouveau) : problème d’affichage dans la colone date

  13 avril 2021, par Franck D

  Hello, j’ai essayer en local mais aussi chez ovh en php 8 et cela fait pareil.
  spip SPIP 3.3.0-dev GIT [master : 235be9bc] sans même un article dedans

  Installation d’un spip tout neuf vierge avec uniquement gd2 et les miniatures d’aciver et le plug simplog que j’ai eu via svp
  J’ai fait l’ajout d’un fichier mes_options après l’installation avec dedans :
  define(’_NO_CACHE’, -1) ;
  define(’_INTERDIRE_COMPACTE_HEAD_ECRIRE’, true) ;
  error_reporting(E_ALL^E_NOTICE) ;
  ini_set ("display_errors", "On") ;
  define(’SPIP_ERREUR_REPORT’,E_ALL) ;
  $GLOBALS[’taille_des_logs’] = 500 ;
  define(’_MAX_LOG’, 500000) ;
  define(’_LOG_FILELINE’,true) ;
  define(’_LOG_FILTRE_GRAVITE’,8) ;
  define(’_DEBUG_SLOW_QUERIES’, true) ;
  define(’_BOUCLE_PROFILER’, 5000) ;

  Je viens de me rendre compte qu’il y a un problème, si je clique pour un affichage à deux ans, pour un tableau (voir copie d’écran)

• C# FFmpeg rtsp byte stream

  3 septembre 2023, par Jesse

  How can I open a constant byte stream that I can read while it's playing ? I am able to get a single image with a resolution of 100:75, but when I bump up the resolution the process never finishes.

  



  I need help improving the performance this method, I'm sure it's possible but I know very little about FFmpeg.

  



  I'd like to be able to :

  



  

  1. List item

  


  2. Get a full res image

  


  3. Read while the process is running

  


  4. Constantly read byte output from a live stream

  


  



  This is how I get the single image, it's running on a background thread.

  



  string stream = "-i " + url + " -vf scale=100:75 -an -vframes 1 -r 1 -f image2pipe pipe:bmp";

var process = new Process();
process.StartInfo.FileName = ffmpeg.exe;
process.StartInfo.Arguments = stream;
process.StartInfo.UseShellExecute = false;
process.StartInfo.RedirectStandardInput = true;
process.StartInfo.RedirectStandardOutput = true;
process.StartInfo.RedirectStandardError = true;
process.StartInfo.CreateNoWindow = true;

process.Start();
process.WaitForExit();

Stream outputReader = process.StandardOutput.BaseStream;

byte[] buffer = new byte[16*1024];
using (MemoryStream ms = new MemoryStream())
{
    int read;
    while ((read = outputReader.Read(buffer, 0, buffer.Length)) > 0)
    {
        ms.Write(buffer, 0, read);
    }

    BitmapImage bitmapImage = new BitmapImage();
    bitmapImage.BeginInit();
    bitmapImage.StreamSource = new MemoryStream(ms.ToArray());
    bitmapImage.EndInit();

    bitmapImage.Freeze();
    Image = bitmapImage;
}


  


• C# FFmpeg rtsp byte stream

  18 février 2015, par Jesse

  How can I open a constant byte stream that I can read while it’s playing ? I am able to get a single image with a resolution of 100:75, but when I bump up the resolution the process never finishes.

  I need help improving the performance this method, I’m sure it’s possible but I know very little about FFmpeg.

  I’d like to be able to :

  1. List item
  2. Get a full res image
  3. Read while the process is running
  4. Constantly read byte output from a live stream

  This is how I get the single image, it’s running on a background thread.

  string stream = "-i " + url + " -vf scale=100:75 -an -vframes 1 -r 1 -f image2pipe pipe:bmp";
  
  
  
  var process = new Process();
  
  process.StartInfo.FileName = ffmpeg.exe;
  
  process.StartInfo.Arguments = stream;
  
  process.StartInfo.UseShellExecute = false;
  
  process.StartInfo.RedirectStandardInput = true;
  
  process.StartInfo.RedirectStandardOutput = true;
  
  process.StartInfo.RedirectStandardError = true;
  
  process.StartInfo.CreateNoWindow = true;
  
  
  
  process.Start();
  
  process.WaitForExit();
  
  
  
  Stream outputReader = process.StandardOutput.BaseStream;
  
  
  
  byte[] buffer = new byte[16*1024];
  
  using (MemoryStream ms = new MemoryStream())
  
  {
  
      int read;
  
      while ((read = outputReader.Read(buffer, 0, buffer.Length)) > 0)
  
      {
  
          ms.Write(buffer, 0, read);
  
      }
  
  
  
      BitmapImage bitmapImage = new BitmapImage();
  
      bitmapImage.BeginInit();
  
      bitmapImage.StreamSource = new MemoryStream(ms.ToArray());
  
      bitmapImage.EndInit();
  
  
  
      bitmapImage.Freeze();
  
      Image = bitmapImage;
  
  }