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Médias (17)
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Matmos - Action at a Distance
15 septembre 2011, par
Mis à jour : Septembre 2011
Langue : English
Type : Audio
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DJ Dolores - Oslodum 2004 (includes (cc) sample of “Oslodum” by Gilberto Gil)
15 septembre 2011, par
Mis à jour : Septembre 2011
Langue : English
Type : Audio
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Danger Mouse & Jemini - What U Sittin’ On ? (starring Cee Lo and Tha Alkaholiks)
15 septembre 2011, par
Mis à jour : Septembre 2011
Langue : English
Type : Audio
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Cornelius - Wataridori 2
15 septembre 2011, par
Mis à jour : Septembre 2011
Langue : English
Type : Audio
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The Rapture - Sister Saviour (Blackstrobe Remix)
15 septembre 2011, par
Mis à jour : Septembre 2011
Langue : English
Type : Audio
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Chuck D with Fine Arts Militia - No Meaning No
15 septembre 2011, par
Mis à jour : Septembre 2011
Langue : English
Type : Audio
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Sur d’autres sites (9900)
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how to choose ffmpeg video mp3 audio version id ?
7 juin 2013, par UlteriorI am having issues on ffmpeg encoded video files audio tracks. My encoded video contains ID for audio track as extracted from mediainfo :
I use CODEC_ID_MP3 in guess_format "mov" container for quicktime
Audio
ID : 2
Format : MPEG Audio
Format version : Version 2
Format profile : Layer 3
Codec ID : .mp3
Duration : 2s 916ms
Bit rate mode : Constant
Bit rate : 128 Kbps
Channel(s) : 1 channel
Sampling rate : 16.0 KHz
Compression mode : Lossy
Stream size : 45.3 KiB (2%)
Language : EnglishThis is not recognized on a vanilla codecless installation of windows 7, only played by k-lite codec libmad
I have noticed, that another test file contains similar mp3 track and is played by media player OK :
Audio
ID : 2
Format : MPEG Audio
Format version : Version 1
Format profile : Layer 3
Mode : Joint stereo
Mode extension : MS Stereo
Codec ID : 6B
Duration : 1mn 9s
Bit rate mode : Constant
Bit rate : 320 Kbps
Channel(s) : 2 channels
Sampling rate : 44.1 KHz
Compression mode : Lossy
Stream size : 2.67 MiB (38%)
Writing library : LAME3.98The difference I noticed is in Format version number and Codec ID, which is Version 2 from ffmpeg output - I couldnt locate this version setting in ffmpeg source files, so my question is - is there a way to influence this format version identificator and set the codec id as in above playable video ?
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Evolution #4080 : Raccourci puce : se débarasser de l’image
1er octobre 2018Je vote pour le caractère
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Generate waveforms for audio files with large amount of channels
3 mai 2021, par motioI want to generate .png files displaying the waveforms of interleaved audio .wav files using the FFmpeg libraries. http://ffmpeg.org/documentation.html


If the interleaved audio file contains maximum 8 channels, I manage to successfully achieve this using the following command line :


ffmpeg -i 8_channels_input.wav -y -filter_complex "showwavespic=s=1920x1200:split_channels=1" -frames:v 1 8_channels_waveform_output.png



However, if the interleaved audio file contains more than 8 channels, FFmpeg gives the following :




Input #0, wav, from '30_channels_input.wav' : Duration : 00:00:02.08,
bitrate : 31752 kb/s Stream #0:0 : Audio : pcm_s24le ([1][0][0][0] /
0x0001), 44100 Hz, 30 channels, s32 (24 bit), 31752 kb/s Stream
mapping : Stream #0:0 (pcm_s24le) -> showwavespic showwavespic ->
Stream #0:0 (png) Press [q] to stop, [?] for help [auto_resampler_0 @
0x7faf5d60a3c0] Cannot select channel layout for the link between
filters auto_resampler_0 and Parsed_showwavespic_0. [auto_resampler_0
@ 0x7faf5d60a3c0] Unknown channel layouts not supported, try
specifying a channel layout using 'aformat=channel_layouts=something'.
Error reinitializing filters ! Failed to inject frame into filter
network : Invalid argument Error while processing the decoded data for
stream #0:0 Conversion failed !




Here is the related documentation (c.f. bottom of the page) :
https://trac.ffmpeg.org/wiki/AudioChannelManipulation


My problem is :
I need to generate the visual waveforms of audio files containing up to 30 channels.
All my attempts were unsuccessful so far (I am trying to define custom channel layouts and I am not sure if I am on the right track here).


To simplify, I need to complete/modify the following command to make it work :


ffmpeg -i 30_channels_input.wav -y -filter_complex "showwavespic=s=1920x1200:split_channels=1" -frames:v 1 30_channels_waveform_output.png 



[EDIT] Remarks :


I manage to generate the waveforms of a 10 channels input by combining existing layouts :


ffmpeg -i 10_channels_input.wav -y -filter_complex "aformat=channel_layouts=7.1+downmix, showwavespic=s=1920x1200:split_channels=1" -frames:v 1 10_channels_waveform_output.png



However, if you attempt to do it for a 30 channels input by combining 5x 6.0 layouts :


ffmpeg -i 30_channels_input.wav -y -filter_complex "aformat=channel_layouts=6.0+6.0+6.0+6.0+6.0, showwavespic=s=1920x1200:split_channels=1" -frames:v 1 30_channels_waveform_output.png



FFmpeg gives the following :




[auto_resampler_0 @ 0x7ffd7002a480] [SWR @ 0x7ffd7013a000] Rematrix is
needed between 30 channels and 6.0 but there is not enough information
to do it [auto_resampler_0 @ 0x7ffd7002a480] Failed to configure
output pad on auto_resampler_0 Error reinitializing filters ! Failed to
inject frame into filter network : Invalid argument Error while
processing the decoded data for stream #0:0




My assumption is that I need to create a custom layout using 30 unique channel IDs (c.f. https://trac.ffmpeg.org/wiki/AudioChannelManipulation bottom of the page) instead of combining existing layouts.


It seems that only 25 channel IDs are available though. Creating a custom layout with 30 channels is maybe not possible at all...


[EDIT 2] Remarks :


I finally found the documentation I was looking for. But it still seems that generating the waveforms of 30 channels would be difficult.


Here is how to create custom layouts :
https://ffmpeg.org/ffmpeg-utils.html




A custom channel layout can be specified as a sequence of terms,
separated by ’+’ or ’|’. Each term can be :


the name of a standard channel layout (e.g. ‘mono’, ‘stereo’, ‘4.0’,
‘quad’, ‘5.0’, etc.) the name of a single channel (e.g. ‘FL’, ‘FR’,
‘FC’, ‘LFE’, etc.) a number of channels, in decimal, followed by ’c’,
yielding the default channel layout for that number of channels (see
the function av_get_default_channel_layout). Note that not all channel
counts have a default layout. a number of channels, in decimal,
followed by ’C’, yielding an unknown channel layout with the specified
number of channels. Note that not all channel layout specification
strings support unknown channel layouts. a channel layout mask, in
hexadecimal starting with "0x" (see the AV_CH_* macros in
libavutil/channel_layout.h. Before libavutil version 53 the trailing
character "c" to specify a number of channels was optional, but now it
is required, while a channel layout mask can also be specified as a
decimal number (if and only if not followed by "c" or "C").


See also the function av_get_channel_layout defined in
libavutil/channel_layout.h.




e.g.


Therefore, for 11 channels input :


ffmpeg -i 11_channels_input.wav -y -filter_complex "aformat=channel_layouts=FL+FR+FC+BL+BR+BC+SL+SR+WL+WR+TBL, showwavespic=s=1920x1200:split_channels=1" -frames:v 1 11_waveform_output.png



—> worked for me


while :


ffmpeg -i 11_channels_input.wav -y -filter_complex "aformat=channel_layouts=11c, showwavespic=s=1920x1200:split_channels=1" -frames:v 1 11_waveform_output.png



—> does not work


But :


ffmpeg -i 24_channels_input.wav -y -filter_complex "aformat=channel_layouts=24c, showwavespic=s=1920x1200:split_channels=1" -frames:v 1 24_waveform_output.png



—> does work


and finally, what I am still trying to achieve :


ffmpeg -i 30_channels_input.wav -y -filter_complex "aformat=channel_layouts=30c, showwavespic=s=1920x1200:split_channels=1" -frames:v 1 30_waveform_output.png



—> does not work


p.s.


- 

- I execute these commands in sub shells via Ruby scripts (puts %x...)
- My system : macOS 10.15.6 | zsh | FFmpeg 4.4 | Ruby 2.6.3