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GetID3 - Bloc informations de fichiers
9 avril 2013, par
Mis à jour : Mai 2013
Langue : français
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Autres articles (102)
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MediaSPIP 0.1 Beta version
25 avril 2011, parMediaSPIP 0.1 beta is the first version of MediaSPIP proclaimed as "usable".
The zip file provided here only contains the sources of MediaSPIP in its standalone version.
To get a working installation, you must manually install all-software dependencies on the server.
If you want to use this archive for an installation in "farm mode", you will also need to proceed to other manual (...) -
Liste des distributions compatibles
26 avril 2011, parLe tableau ci-dessous correspond à la liste des distributions Linux compatible avec le script d’installation automatique de MediaSPIP. Nom de la distributionNom de la versionNuméro de version Debian Squeeze 6.x.x Debian Weezy 7.x.x Debian Jessie 8.x.x Ubuntu The Precise Pangolin 12.04 LTS Ubuntu The Trusty Tahr 14.04
Si vous souhaitez nous aider à améliorer cette liste, vous pouvez nous fournir un accès à une machine dont la distribution n’est pas citée ci-dessus ou nous envoyer le (...) -
HTML5 audio and video support
13 avril 2011, parMediaSPIP uses HTML5 video and audio tags to play multimedia files, taking advantage of the latest W3C innovations supported by modern browsers.
The MediaSPIP player used has been created specifically for MediaSPIP and can be easily adapted to fit in with a specific theme.
For older browsers the Flowplayer flash fallback is used.
MediaSPIP allows for media playback on major mobile platforms with the above (...)
Sur d’autres sites (10257)
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"Pixel format 'yuvj420p' is not supported" when converting image to video using CUDA hardware acceleration
11 février 2020, par laurentI’m trying to convert an image to a video using CUDA hardware acceleration but I can’t get it to work.
The basic command I have is this one :
ffmpeg -y -hwaccel cuvid -i tests/MediaSamples/portrait_0.jpg -t 10 out.mp4
And I’m getting this error :
[AVHWFramesContext @ 0x32d3f00] Pixel format 'yuvj420p' is not supported
[mjpeg @ 0x2d18480] Error initializing a CUDA frame pool
cuvid hwaccel requested for input stream #0:0, but cannot be initialized.
Error while decoding stream #0:0: Invalid argumentI’ve tried setting the pixel format like so, but that didn’t help :
ffmpeg -y -hwaccel cuvid -pix_fmt yuv420p -i tests/MediaSamples/portrait_0.jpg -t 10 out.mp4
I’ve also tried many other flags but can’t get anything to work. Any idea what the issue might be ?
For information this is the full log :
ffmpeg version N-96615-gc35382a Copyright (c) 2000-2020 the FFmpeg developers
built with gcc 5.4.0 (Ubuntu 5.4.0-6ubuntu1~16.04.12) 20160609
configuration: --enable-nonfree --disable-shared --enable-gpl --enable-openssl --enable-libx264 --enable-cuda-sdk --enable-nvenc --enable-cuda --enable-cuvid --enable-libnpp --extra-cflags='-I/usr/local/ssl/include -I/usr/local/cuda/include -I/usr/local/include -L/usr/local/ssl/lib -Wl,-rpath=/usr/local/ssl/lib' --extra-ldflags=-L/usr/local/cuda/lib64
libavutil 56. 38.100 / 56. 38.100
libavcodec 58. 67.101 / 58. 67.101
libavformat 58. 37.100 / 58. 37.100
libavdevice 58. 9.103 / 58. 9.103
libavfilter 7. 73.100 / 7. 73.100
libswscale 5. 6.100 / 5. 6.100
libswresample 3. 6.100 / 3. 6.100
libpostproc 55. 6.100 / 55. 6.100
Input #0, image2, from 'tests/MediaSamples/portrait_0.jpg':
Duration: 00:00:00.04, start: 0.000000, bitrate: 40237 kb/s
Stream #0:0: Video: mjpeg (Progressive), yuvj420p(pc, bt470bg/unknown/unknown), 1600x900 [SAR 72:72 DAR 16:9], 25 tbr, 25 tbn, 25 tbc
Stream mapping:
Stream #0:0 -> #0:0 (mjpeg (native) -> h264 (libx264))
Press [q] to stop, [?] for help
[AVHWFramesContext @ 0x32d3f00] Pixel format 'yuvj420p' is not supported
[mjpeg @ 0x2d18480] Error initializing a CUDA frame pool
cuvid hwaccel requested for input stream #0:0, but cannot be initialized.
Error while decoding stream #0:0: Invalid argument
[libx264 @ 0x2d1e840] using SAR=1/1
[libx264 @ 0x2d1e840] using cpu capabilities: MMX2 SSE2Fast SSSE3 SSE4.2 AVX FMA3 AVX2 LZCNT BMI2
[libx264 @ 0x2d1e840] profile High, level 4.0
[libx264 @ 0x2d1e840] 264 - core 148 r2643 5c65704 - H.264/MPEG-4 AVC codec - Copyleft 2003-2015 - http://www.videolan.org/x264.html - options: cabac=1 ref=3 deblock=1:0:0 analyse=0x3:0x113 me=hex subme=7 psy=1 psy_rd=1.00:0.00 mixed_ref=1 me_range=16 chroma_me=1 trellis=1 8x8dct=1 cqm=0 deadzone=21,11 fast_pskip=1 chroma_qp_offset=-2 threads=24 lookahead_threads=4 sliced_threads=0 nr=0 decimate=1 interlaced=0 bluray_compat=0 constrained_intra=0 bframes=3 b_pyramid=2 b_adapt=1 b_bias=0 direct=1 weightb=1 open_gop=0 weightp=2 keyint=250 keyint_min=25 scenecut=40 intra_refresh=0 rc_lookahead=40 rc=crf mbtree=1 crf=23.0 qcomp=0.60 qpmin=0 qpmax=69 qpstep=4 ip_ratio=1.40 aq=1:1.00
Output #0, mp4, to 'out.mp4':
Metadata:
encoder : Lavf58.37.100
Stream #0:0: Video: h264 (libx264) (avc1 / 0x31637661), yuvj420p(pc), 1600x900 [SAR 72:72 DAR 16:9], q=-1--1, 25 fps, 12800 tbn, 25 tbc
Metadata:
encoder : Lavc58.67.101 libx264
Side data:
cpb: bitrate max/min/avg: 0/0/0 buffer size: 0 vbv_delay: N/A
frame= 0 fps=0.0 q=0.0 Lsize= 0kB time=00:00:00.00 bitrate=N/A speed= 0x
video:0kB audio:0kB subtitle:0kB other streams:0kB global headers:0kB muxing overhead: unknown
Conversion failed! -
Ffmpeg "no directory found" when passing in a path to the mp3 file
21 février 2020, par Eugene LevinsonHow my code should work :
Join the voice channel with the user who sent the command
Download the video using the link
Save it as random 16 digit number .mp3
Then pass the path to the FFmpeg player to play
My code :
The random 16 digit number
def get_digits(amount):
st = ""
for i in range(amount):
n = random.randint(0,9)
st = st + str(n)
return int(st)Downloading the file
def get_path(url):
#checking if the directory exists
os.makedirs('Music', exist_ok=True)
title = YouTube(url).streams.get_highest_resolution().title
current_directory = pathlib.Path(__file__).parent.absolute()
print(str(current_directory))
#name for the music
name = str(get_digits(16))
YouTube(url).streams.filter(only_audio=True).order_by("bitrate").desc().first().download("Music",name )
return str(str(current_directory) + "/Music/" + name + ".mp3")This gets called on command play
#function to connect to a voice chat
async def join_auth(ctx):
try:
channel = ctx.author.voice.channel
vc = await channel.connect()
return vc
except Exception as e:
logg("Exception occured when joining a voice channel: " + str(e),"error",str(ctx.guild.name), str(ctx.guild.id))The error I get :
C:\Users\Eugene\Desktop\Discord bot/Music/4343941300524002.mp3: No such file or directory
But the directoryC:\Users\Eugene\Desktop\Discord bot\Music
exists and it does contain the4343941300524002.mp3
file. Does anyone know why do I get the error ? -
How to use https input with ffmpeg "amovie" filter ?
19 septembre 2023, par standacI'm applying a filter on my audio file before adding it to the video. This is the command I use :



ffmpeg -y -i video-input.mp4 -f lavfi -i "amovie=audio.mp3:loop=0,asetpts=N/SR/TB,afade=in:st=0:d=1,afade=out:st=92:d=2" -shortest -c:v copy -c:a aac -strict -2 video-output.mp4




I would like to use a https input :



ffmpeg -y -i video-input.mp4 -f lavfi -i "amovie=https://www.xxxx.com/audio.mp3:loop=0,asetpts=N/SR/TB,afade=in:st=0:d=1,afade=out:st=92:d=2" -shortest -c:v copy -c:a aac -strict -2 video-output.mp4




But this is the error I get :



[Parsed_amovie_0 @ 0x55da3a414a40] Failed to avformat_open_input 'https'
[lavfi @ 0x55da3a436660] Error initializing filter 'amovie' with args 'https://www.xxxx.com/audio.mp3:loop=0'
amovie=https://www.xxxx.com/audio.mp3:loop=0,asetpts=N/SR/TB: No such file or directory




From the "amovie" documentation on ffmpeg :



filename: The name of the resource to read (not necessarily a file; it can also be a device or a stream accessed through some protocol).




How can I use a https input in my audio filter ?