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• Why PyAudio doesn't read 'mp3' ?

  22 octobre 2020, par freshITmeat

  I tried to read file that I give with absolute path.
When I run my code first that I see is this message :

  


  D:\prog\datascience\anaconda\lib\site-packages\pydub\utils.py:170: RuntimeWarning: Couldn't find ffmpeg or avconv - defaulting to ffmpeg, but may not work
  warn("Couldn't find ffmpeg or avconv - defaulting to ffmpeg, but may not work", RuntimeWarning)


  


  I tried this :

  


  PATH_TO_FFMPEG = 'D:\\prog\\ffmpeg-win-2.2.2\\ffmpeg.exe'
pydub.AudioSegment.converter = r'D:\\prog\\ffmpeg-win-2.2.2\\ffmpeg.exe'


  


  And I separately installed ffmpeg with pip. But it didn't help.
When I try this :

  


  raw_sound = pydub.AudioSegment.from_mp3(file=track_path)


  


  where track_path is correct absolute path generated automatically.
So I got this this error :

  


  Traceback (most recent call last):&#xA;  File "D:\prog\PyCharm Community Edition 2020.2.2\plugins\python-ce\helpers\pydev\pydevd.py", line 1448, in _exec&#xA;    pydev_imports.execfile(file, globals, locals)  # execute the script&#xA;  File "D:\prog\PyCharm Community Edition 2020.2.2\plugins\python-ce\helpers\pydev\_pydev_imps\_pydev_execfile.py", line 18, in execfile&#xA;    exec(compile(contents&#x2B;"\n", file, &#x27;exec&#x27;), glob, loc)&#xA;  File "D:/testtask2/test_task/testtask/get_mffc.py", line 165, in <module>&#xA;    slice_all_in_a_dir(&#x27;May 27 2020 LNC/Hydrophone 1/raw_records&#x27;)&#xA;  File "D:/testtask2/test_task/testtask/get_mffc.py", line 70, in slice_all_in_a_dir&#xA;    slice_samples(track_path= [file],&#xA;  File "D:/testtask2/test_task/testtask/get_mffc.py", line 48, in slice_samples&#xA;    raw_sound = pydub.AudioSegment.from_mp3(file=track_path)&#xA;  File "D:\prog\datascience\anaconda\lib\site-packages\pydub\audio_segment.py", line 738, in from_mp3&#xA;    return cls.from_file(file, &#x27;mp3&#x27;, parameters=parameters)&#xA;  File "D:\prog\datascience\anaconda\lib\site-packages\pydub\audio_segment.py", line 680, in from_file&#xA;    stdin_data = file.read()&#xA;AttributeError: &#x27;list&#x27; object has no attribute &#x27;read&#x27;&#xA;python-BaseException&#xA;</module>

  


• How to combine/concatenate videos stored in AWS S3 bucket based on title of the file name

  9 juin 2020, par orangecube

  I am using a service that allows me to record videos that get automatically pushed to a folder (submissions) in an S3 bucket. There are multiple videos however they need to be grouped together and concatenated so the output is one video per group.

  



  So, basically, any tips on how I can take videos based on the title and stitch them together ?

  



  Example :

  



  Submissions folder will have :

  



  a-100-2.mp4
a-200-6.mp4
b-123-5.mp4


  



  Expected output in processed folder :

  



  a.mp4     - (both 'a' videos get stitched together)
b.mp4     - (only 'b' gets sent over since there is only one video.)


  



  Thanks in advance !

  



  Edit : Some additional and detailed information below if it helps.

  



  The files will be labeled with :
name-location-video_token-stream_token.mp4

  



  Need help creating a script or process that will concatenate the videos using the procedure outlined below :

  



  Processing rules (back end) :

  



  


  1. Check if videos have same video_token in ‘submissions folder’. If so, keep the newest one and delete old ones.

  


  2. Take all videos in ‘submissions folder’ with same name and location in title and concatenate the videos. Save output video to a new folder in the bucket labeled as the location for the folder name. 
Output file name : 
name-location-year.mp4.

  


  



  EXAMPLE :

  



  Submissions folder :
joey-toronto-001-354.mp4

  



  joey-toronto-001-241.mp4 - this will be deleted

  



  joey-toronto-103-452.mp4

  



  alex-montreal-352-232.mp4

  



  alex-montreal-452-223.mp4

  



  Resulting output :

  



  Toronto folder :

  



  Joey-toronto-2020.mp4

  



  Montreal folder :

  



  Alex-montreal-2020.mp4

  


• MobileFFMPEG Output file #0 does not contain any stream

  30 septembre 2020, par Alhaj

  I am using implementation 'com.arthenica:mobile-ffmpeg-full:4.4'

  


  I just want o crop audio file to 10 second to 20 second

  


  '''
fun cropAudio(input :String)

  


      val newFileName = UUID.randomUUID().toString()

    val location: String = getBatchDirectoryName()!!

    val output: String = location + "/" + newFileName + ".mp3"

    val temp=" -i $input -ss 60 -to 70 $output"

    Log.e("alhaj", " a $s")

    FFmpeg.execute(temp, object : ExecuteCallback {

        fun onSuccess(message: String?) {
            uploadOnFirebase(output, title)
            mediaPlayer.stop()
            Log.e("alhaj", message!!)
        }

        override fun apply(executionId: kotlin.Long, returnCode: Int) {
            if (returnCode == RETURN_CODE_SUCCESS) {
                Log.i("alhaj", "Async command execution completed successfully.");
            } else if (returnCode == RETURN_CODE_CANCEL) {
                Log.i("alhaj", "Async command execution cancelled by user.");
            } else {
                Log.i("alhaj", String.format("Async command execution failed with rc=%d.", returnCode));
            }
        }
    }.toString())
}


  


  '''

  


  but i am getting error

  


  '''

  


  2020-09-30 03:13:41.079 10300-10410/com.example.touchmeadmin I/mobile-ffmpeg : Output #0, mp3, to ' -i /storage/emulated/0/AJ backup/songs/Maroon 5 - Memories (Official Video) ( 256kbps cbr ).mp3 -ss 60 -to 70 /storage/emulated/0/Android/data/com.example.touchmeadmin/files/Music/830350fd-5218-4ee0-bd99-0dd50b802930.mp3' :
2020-09-30 03:13:41.079 10300-10410/com.example.touchmeadmin E/mobile-ffmpeg : Output file #0 does not contain any stream

  


  '''