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rtp mpg stream using jrtplib occurred error "illegal timestamp unit"
13 avril 2013, par socketI wanna code rtp video stream sender and use VLC to play it in the LAN. I just have a mpeg4 file "a.mpg". And in my opinion, jrtplib can pack the packed well, so I think I can use sendPacket() function directly to send the mpg file. code below :
#include
#include
#include
#include
#include
#include
#include
#include <iostream>
#include
using namespace jrtplib;
using namespace std;
int main()
{
RTPSession s;
RTPSessionParams sparam;
s.SetTimestampUnit(160.0/104857.0);//~
RTPUDPv4TransmissionParams tparam;
tparam.SetPortbase(9000);
int status=s.Create(sparam,&tparam);
if(status<0)
{
cerr<<"error 1"</~
s.SetDefaultMark(false);
s.SetDefaultTimestampIncrement(160);//~~
unsigned char buf[160];
FILE*f=fopen("a.mpg","rb");
while(!feof(f))
{
fread(buf,1,160,f);
RTPTime delay(0.02);//~
bool ret=false;
status=s.SendPacket(buf,160);
if(status<0)
{
cerr<<"error 3"<code></iostream>Then, I compile it :
g++ jrtpsend.cpp -ljrtp -I /usr/local/include/jrtplib3
After that, I run the program but error occurred :
kl@kl-ubuntu:~/code/RTP$ ./a.out
error 1
Speficied an illegal timestamp unit for the the RTCP packet builderActually, I didn't know timestamp exactly. When I use ffplay to play a.mpg showing that :
Input #0, mpeg, from 'a.mpg':q= 0KB vq= 0KB sq= 0B f=0/0
Duration: 00:01:00.69, start: 0.529089, bitrate: 556 kb/s
Stream #0:0[0x1e0]: Video: mpeg1video, yuv420p, 640x480 [SAR 239:182 DAR 478:273], 104857 kb/s, 25 fps, 25 tbr, 90k tbn, 25 tbc
Stream #0:1[0x1c0]: Audio: mp2, 44100 Hz, stereo, s16p, 128 kb/s2.46 A-V : -0.003 fd= 7 aq= 2KB vq= 33KB sq= 0B f=0/0
So, I use the data 104857kb/s in the code (setTimestampUnit()), but I have no idea whether I use it correctly.
All in all, please give me some suggestion how to run the program well or ...
Best regards :-)