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• Stream H264 raw data on RTSP server

  1er janvier, par Aitazaz

  I have H264 hex string data saved in a list.
The data is in correct format as it is being received, I am trying to stream it to RTSP server.

  


  I have stream the data in realtime as it is from a dashcam.

  


  The RTSP server is deployed but when I stream frames to it, the connection is created and then ends in an instant (does not last for a second)

  


  The code is mentioned below which performs this streaming task.

  


  def h264_stream_to_rtsp(data_list, rtsp_url):
    try:
        ffmpeg_command = [
            "ffmpeg", 
            "-f", "h264",
            "-i", "-",
            "-vcodec", "libx264",
            "-preset", "fast",
            "-f", "rtsp",
            "-analyzeduration", "5000000",
            "-probesize", "5000000", 
            rtsp_url  # The RTSP URL to stream to
        ]
        
        ffmpeg_process = subprocess.Popen(ffmpeg_command, stdin=subprocess.PIPE)

        for index, hex_data in enumerate(data_list):
            # print(f"Processing hex data {index + 1}/{len(data_list)}...")

            if len(hex_data) % 2 != 0:
                hex_data = '0' + hex_data  # Append a leading zero if length is odd

            binary_data = binascii.unhexlify(hex_data)

            ffmpeg_process.stdin.write(binary_data)

        ffmpeg_process.stdin.close()

        ffmpeg_process.wait()
        print("Stream completed.")

    except KeyboardInterrupt:
        print("Stopping live stream.")
    except Exception as e:
        print(f"Error: {e}")


  


  Logs from the RTSP server are mentioned below :

  


  2025/01/01 10:56:04 INF [RTSP] [conn 20.174.9.78:35474] opened
2025/01/01 10:56:04 INF [RTSP] [session 1d2bb871] created by 20.174.9.78:35474
2025/01/01 10:56:04 INF [RTSP] [session 1d2bb871] is publishing to path 'live', 1 track (H264)
2025/01/01 10:56:04 INF [RTSP] [session 1d2bb871] destroyed: torn down by 20.174.9.78:35474
2025/01/01 10:56:04 INF [RTSP] [conn 20.174.9.78:35474] closed: EOF
2025/01/01 10:56:48 INF [RTSP] [conn 20.174.9.78:54448] opened
2025/01/01 10:56:48 INF [RTSP] [session b6a95e71] created by 20.174.9.78:54448
2025/01/01 10:56:48 INF [RTSP] [session b6a95e71] is publishing to path 'live', 1 track (H264)
2025/01/01 10:56:48 INF [RTSP] [session b6a95e71] destroyed: torn down by 20.174.9.78:54448


  


  How can I stream continuously ?

  


• Can I use the file buffer or stream as input for fluent-ffmpeg ? I am trying to avoid saving the video locally to get its path before removing

  22 avril 2023, par Moath Thawahreh

  I am receiving the file via an api, I was trying to process the file.buffer as input for FFmpeg but it did not work, I had to save the video locally first and then process the path and remove the saved video later on.
I don't want to believe that there is no other way to solve this and I have been looking for solutions and workarounds but it was all about ffmpeg input as a path.

  


  I would love to find a solution using fluent-ffmpeg because it has some other great features, but I won't mind any suggestions for compressing the video using any different approaches if it's more efficient

  


  Again my code below works fine but I have to save the video and then remove it I am hoping for a more efficient solution :

  


    fs.writeFileSync(&#x27;temp.mp4&#x27;, file.buffer);&#xA;&#xA;    // Resize the temporary file using ffmpeg&#xA;    ffmpeg(&#x27;temp.mp4&#x27;) // here I tried pass file.buffer as readable stream,it receives paths only &#xA;      .format(&#x27;mp4&#x27;)&#xA;      .size(&#x27;50%&#x27;)&#xA;      .save(&#x27;resized.mp4&#x27;)&#xA;      .on(&#x27;end&#x27;, async () => {&#xA;        // Upload the resized file to Firebase&#xA;        const resizedFileStream = bucket.file(`video/${uniqueId}`).createWriteStream();&#xA;        fs.createReadStream(&#x27;resized.mp4&#x27;).pipe(resizedFileStream);&#xA;&#xA;        await new Promise<void>((resolve, reject) => {&#xA;          resizedFileStream&#xA;            .on(&#x27;finish&#x27;, () => {&#xA;              // Remove the local files after they have been uploaded&#xA;              fs.unlinkSync(&#x27;temp.mp4&#x27;);&#xA;              fs.unlinkSync(&#x27;resized.mp4&#x27;);&#xA;              resolve();&#xA;            })&#xA;            .on(&#x27;error&#x27;, reject);&#xA;        });&#xA;&#xA;        // Get the URL of the uploaded resized version&#xA;        const resizedFile = bucket.file(`video/${uniqueId}`);&#xA;        const url = await resizedFile.getSignedUrl({&#xA;          action: &#x27;read&#x27;,&#xA;          expires: &#x27;03-17-2025&#x27;, // Change this to a reasonable expiration date&#xA;        });&#xA;&#xA;        console.log(&#x27;Resized file uploaded successfully.&#x27;);&#xA;      })&#xA;      .on(&#x27;error&#x27;, (err) => {&#xA;        console.log(&#x27;An error occurred: &#x27; &#x2B; err.message);&#xA;      });&#xA;</void>

  


• FFmpeg get frame rate

  22 septembre 2021, par zhin dins

  I have several images and I am reproducing them in 78.7ms, I am creating like the 80s video effect. But, I am unable to find the correct ms, and this images with the original videos are unsync.

  


  I dumped the video to images using this command => ffmpeg -i *.mp4 the80effect/img-%d.jpg And now, I have 48622 frames. The video FPS is 24

  


  So, 48622/24 = 2025 +- I cannot use 2025ms since those images will load very slow. And the and the approximate value is 78.7ms per frame/image

  


  How can I find the correct value ? The video duration in seconds is 2026. I have tried all math to find this but I'm failing. How many images (one frame) per msCould you help me ? Thank you.