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• What is wrong part in my Android code with ffmpeg ?

  6 janvier 2016, par Marko androshenko

  I want to get mixed video.(Image + Video)
  Total duration of original video is 180 sec. I want to put image to the front of video. So, I made some code in android studio.
  But I can not look any toast.
  What is wrong ? How to check the end of process ?

  ...
  path = "libray folder" ;
  ...

      private class ProcessVideo extends AsyncTask {
  
              @Override
  
              protected Void doInBackground(Void... params) {
  
  
  
                  Process ffmpegProcess = null;
  
  
  
                  try {
  
            // initialize command for process video
  
                // library is video process library.
  
                      String[] command ={path,"-i", input, "-r", "1", "-q:v", "2", "-f", "image", input};
  
  
  
  
  
                      ffmpegProcess = new ProcessBuilder(ffmpegCommand).redirectErrorStream(true).start();
  
  
  
                      OutputStream ffmpegOutStream = ffmpegProcess.getOutputStream();
  
                      BufferedReader reader = new BufferedReader(new InputStreamReader(ffmpegProcess.getInputStream()));
  
  
  
                      String line;
  
  
  
                      Log.v(THISTAG,"***Starting FFMPEG***");
  
                      while ((line = reader.readLine()) != null)
  
                      {
  
  // in progress 
  
                          Log.v(THISTAG,"***"+line+"***");
  
                      }
  
  // finish all process
  
                      Log.v(THISTAG,"***Ending FFMPEG***");
  
                      videoProcessFinishFlag = true;
  
  
  
                  } catch (IOException e) {
  
                      e.printStackTrace();
  
                  }
  
  
  
                  if (ffmpegProcess != null) {
  
                      ffmpegProcess.destroy();
  
                  }
  
                  return null;
  
              }
  
  
  
              protected void onPostExecute(Void... result) {
  
  // show result
  
                 Toast toast = Toast.makeText(VideoEditorActivity.this, "Done Processing Video", Toast.LENGTH_LONG);
  
                  toast.show();
  
              }
  
          }

• Efficiently streaming a remote file into ffmpeg

  17 janvier 2016, par YZats

  My use case requires transcoding a remote MOV file that can’t be stored locally. I was hoping to use http protocol to stream the file into ffmpeg. This works, but I’m observing this to be a very expensive operation with (seemingly) redundant network traffic, so am looking for suggestions.

  What I see is that ffmpeg starts out with a Range request “0-“ (which brings in the entire file), followed by a number of open-ended requests (no ending offset) at different positions, each of which makes the http server return large chunks of the file again and again, from the starting position to the very end.

  For example, http range requests for a short 10MB file look like this :

  bytes=0-   
  
  bytes=10947419-
  
  bytes=36-
  
  bytes=3153008-
  
  bytes=5876422-

  Is there another input method that would be more network-efficient for my use case ? I control the server where the video file resides, so I’m flexible in what code runs there.

  Any help is greatly appreciated

• Loading a remote file into ffmpeg efficiently

  17 janvier 2016, par YZats

  My use case requires transcoding a remote MOV file that can’t be stored locally. I was hoping to use http protocol to stream the file into ffmpeg. This works, but I’m observing this to be a very expensive operation with (seemingly) redundant network traffic, so am looking for suggestions.

  What I see is that ffmpeg starts out with a Range request “0-“ (which brings in the entire file), followed by a number of open-ended requests (no ending offset) at different positions, each of which makes the http server return large chunks of the file again and again, from the starting position to the very end.

  For example, http range requests for a short 10MB file look like this :

  bytes=0-   
  
  bytes=10947419-
  
  bytes=36-
  
  bytes=3153008-
  
  bytes=5876422-

  Is there another input method that would be more network-efficient for my use case ? I control the server where the video file resides, so I’m flexible in what code runs there.

  Any help is greatly appreciated