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• How to run a ffmpeg command in python with file paths containing spaces ?

  21 juillet 2023, par tomatochan

  I'm developing a program in Python that requires the use of FFMPEG. In one step, I need to create a video from a text file containing the list of images (path and duration) that need to be assembled to make a video. To do this, I use the following code :

  


  cmd = [ffmpeg, "-y", "-f", "concat", "-safe", "0", "-i", tmp, "-c:v", "libx264", "-r", "25", "-pix_fmt", "yuv420p", out]
subprocess.run(cmd)
# os.system(" ".join(cmd)) # returns same error


  


  What returns the error : The syntax of the file, directory or volume name is incorrect.

  


  I know that paths can be problematic when they contain spaces, and as my username has one, I've taken care to quote the paths in such a way that :

  


  ffmpeg = "C:\Users\John Doe\Documents\ffmpeg\bin\ffmpeg.exe"
tmp = "C:\Users\John Doe\Desktop\path\to\file.txt"
out = "C:\Users\John Doe\Desktop\path\to\video.mp4"


  


  When I print(" ".join(cmd)), this is what I get in my terminal :

  


  "C:\Users\John Doe\Documentsffmpeg\binffmpeg.exe" -y -f concat -safe 0 -i "C:\Users\John Doe\Desktop\path\to\file.txt" -c:v libx264 -r 25 -pix_fmt yuv420p "C:\Users\John Doe\Desktop\path\to\video.mp4"


  


  However, the problem persists.
Has anyone ever had this problem and managed to solve it ?

  


  I've also tried the method where you have to escape the spaces (taking care to replace the \ with / and then the with \ ) but nothing works... The error persists.

  


  For your information, here are the contents of one of my .txt files

  


  file C:\Users\John Doe\Desktop\path\to\image_1.png
duration 0.04
file C:\Users\John Doe\Desktop\path\to\image_2.png
duration 0.04
file C:\Users\John Doe\Desktop\path\toimage_3.png
duration 0.04


  


  When I quote the paths in the .txt files

  


  

  • subprocess gives me the error :
PermissionError: [WinError 5] Access denied

  


  • os.system gives me the error :

  


  


  C:\Users\John' is not recognized as an internal or external command, an executable program or a command file.
The syntax of the file, directory or volume name is incorrect.


  


• How to run a command in python with file paths containing spaces ?

  24 juillet 2023, par tomatochan

  I'm developing a program in Python that requires the use of FFMPEG. In one step, I need to create a video from a text file containing the list of images (path and duration) that need to be assembled to make a video. To do this, I use the following code :

  


  cmd = [ffmpeg, "-y", "-f", "concat", "-safe", "0", "-i", tmp, "-c:v", "libx264", "-r", "25", "-pix_fmt", "yuv420p", out]
subprocess.run(cmd)
# os.system(" ".join(cmd)) # returns same error


  


  What returns the error : The syntax of the file, directory or volume name is incorrect.

  


  I know that paths can be problematic when they contain spaces, and as my username has one, I've taken care to quote the paths in such a way that :

  


  ffmpeg = '"C:\Users\John Doe\Documents\ffmpeg\bin\ffmpeg.exe"'
tmp = '"C:\Users\John Doe\Desktop\path\to\file.txt"'
out = '"C:\Users\John Doe\Desktop\path\to\video.mp4"'


  


  When I print(" ".join(cmd)), this is what I get in my terminal :

  


  "C:\Users\John Doe\Documentsffmpeg\binffmpeg.exe" -y -f concat -safe 0 -i "C:\Users\John Doe\Desktop\path\to\file.txt" -c:v libx264 -r 25 -pix_fmt yuv420p "C:\Users\John Doe\Desktop\path\to\video.mp4"


  


  However, the problem persists.
Has anyone ever had this problem and managed to solve it ?

  


  I've also tried the method where you have to escape the spaces (taking care to replace the \ with / and then the with \ ) but nothing works... The error persists.

  


  For your information, here are the contents of one of my .txt files

  


  file C:\Users\John Doe\Desktop\path\to\image_1.png
duration 0.04
file C:\Users\John Doe\Desktop\path\to\image_2.png
duration 0.04
file C:\Users\John Doe\Desktop\path\toimage_3.png
duration 0.04


  


  When I quote the paths in the .txt files

  


  

  • subprocess gives me the error :
PermissionError: [WinError 5] Access denied

  


  • os.system gives me the error :

  


  


  C:\Users\John' is not recognized as an internal or external command, an executable program or a command file.
The syntax of the file, directory or volume name is incorrect.


  


• Android Samsung Galaxy S2 / S3 device bitmap rendering to ImageView issue

  18 décembre 2014, par Steve

  I am stuck in a very strange Bitmap rendering issue with Samsung Android devices. Let me discuss in brief what I have done.

  I am taking frame from a video and rendering it in a ImageView using ffmpeg. Following code gives me a bitmap object in return from JNI callback.

      img_convert_ctx = sws_getContext(pCodecCtx->width,
  
              pCodecCtx->height, pCodecCtx->pix_fmt, target_width,
  
          target_height, PIX_FMT_RGB24, SWS_BICUBIC, NULL, NULL,NULL);
  
  
  
      sws_scale(img_convert_ctx,(const uint8_t* const *) 
  
          pFrame->data,pFrame->linesize, 0, pCodecCtx->height,pFrameRGB->data, 
  
  pFrameRGB->linesize);

  Next, I’m just setting the Bitmap to ImageView. Now the issue is the Bitmap I get is rendering very well in maximum devices except Samsung S2/S3.

  A>Working well In :- Screen Shot 1

  1. Nexus 4
  2. HTC One / HTC One x
  3. LG Optimus
  4. Sony Experia
  5. Samsung Galaxy S Plus / Samsung Exhibit (Android 2.3)

  Issue With :-
  B>Samsung Galaxy S2 & S3 : The second screen shot.

  For Case B, A part of the video is rendering at the right side if you notice.

  I have tried saving the Bitmap I get from JNI as jpg in SD card and read that again to set the ImageView and it works. I Don’t understand what is going wrong with the raw Bitmap that I get from JNI callback, is it with Samsung S2 Hardware ? Please someone help me on this.