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Video d’abeille en portrait
14 mai 2011, par
Mis à jour : Février 2012
Langue : français
Type : Video
Autres articles (51)
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Personnaliser les catégories
21 juin 2013, parFormulaire de création d’une catégorie
Pour ceux qui connaissent bien SPIP, une catégorie peut être assimilée à une rubrique.
Dans le cas d’un document de type catégorie, les champs proposés par défaut sont : Texte
On peut modifier ce formulaire dans la partie :
Administration > Configuration des masques de formulaire.
Dans le cas d’un document de type média, les champs non affichés par défaut sont : Descriptif rapide
Par ailleurs, c’est dans cette partie configuration qu’on peut indiquer le (...) -
HTML5 audio and video support
13 avril 2011, parMediaSPIP uses HTML5 video and audio tags to play multimedia files, taking advantage of the latest W3C innovations supported by modern browsers.
The MediaSPIP player used has been created specifically for MediaSPIP and can be easily adapted to fit in with a specific theme.
For older browsers the Flowplayer flash fallback is used.
MediaSPIP allows for media playback on major mobile platforms with the above (...) -
Support audio et vidéo HTML5
10 avril 2011MediaSPIP utilise les balises HTML5 video et audio pour la lecture de documents multimedia en profitant des dernières innovations du W3C supportées par les navigateurs modernes.
Pour les navigateurs plus anciens, le lecteur flash Flowplayer est utilisé.
Le lecteur HTML5 utilisé a été spécifiquement créé pour MediaSPIP : il est complètement modifiable graphiquement pour correspondre à un thème choisi.
Ces technologies permettent de distribuer vidéo et son à la fois sur des ordinateurs conventionnels (...)
Sur d’autres sites (8842)
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drawtext with ffmpeg python
22 mai 2024, par Wolf WolfI am trying to add a text to a video using ffmpeg and python.
I tried to do this in the following ways, but it didn't work.


first


(
 ffmpeg
 .input(in_video)
 .filter('drawtext',
 fontsize=30,
 fontfile=r"D:\projects\python\editor_bot\downloads\Candara.ttf",
 text='test test test.',
 x='if (eq(mod(t\\, 15)\\, 0)\\, rand(0\\, (w-text_w))\\, x)',
 y='if (eq(mod(t\\, 10)\\, 0)\\, rand(0\\, (h-text_h))\\, y)')
 .output(f'output-final.mp4')
 .run()
 )



second


fil = fr"drawtext=text='test test test':fontsize=30:fontfile=':\projects\python\editor_bot\downloads\Candara.ttf':x='if (eq(mod(t\, 15)\, 0)\, rand(0\, (w-text_w))\, x)':y='if (eq(mod(t\, 10)\, 0)\, rand(0\, (h-text_h))\, y)'"
 (
 ffmpeg
 .input(in_video)
 .output(f'output-final.mkv', filter_complex=fil)
 .run()
 )



But by running this command


ffmpeg -i v1.mp4 -filter:v drawtext="fontsize=30:fontfile=candara.ttf:text='testtest test.':x=if(eq(mod(t\,15)\,0)\,rand(0\,(w-text_w))\,x):y=if(eq(mod(t\,10)\,0)\,rand(0\,(h-text_h))\,y)" -c:a copy -c:v libx264 -preset slow -crf 18 V13.mkv



In the terminal, what I want is done exactly


thanks


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how to combine all chunk videos path into text file using ffmpeg
31 juillet 2017, par Megha CSTask is to create final output video by combining all chunk videos recording from webcam using ffmpeg.
For that, created process with passing the ffmpeg command as argument and save all chunk videos to local folder.
code snippet :
process =new Process();
process.StartInfo.FileName = Directory.GetCurrentDirectory() + @"\ffmpeg.exe";
process.StartInfo.Arguments = "-re -rtbufsize 1000M -f dshow -i video=" + "\"" + vidDevName + "\"" + " -acodec libvo_aacenc -ab 48kb -ar 22050 -ac 2 -b:a 128k -vcodec libx264 -r 25 -s 480x360 -pix_fmt yuv420p -preset medium -segment_time 10 -f segment output%03d.mp4";
process.Start();Its working fine. But now, have to create text file of listing all chunk videos path and can create final output video by using "-f concat -safe 0 -i mylist.txt -c copy output.mp4" as an argument.
Am stuck in creating text file with listing all chunk videos path in c#.
I have used (for %i in (*.wav) do @echo file ’%i’) > mylist.txt to create text file. Its working fine in command prompt but not in C# application.
So please suggest on this. -
Execute mp4box cmd via java got error
6 novembre 2015, par Ducthiensorry when I tag ffmpeg because I couldn’t tag MP4Box.But I have proplem with excuted with ffmpeg via javacode too.
I read at How to execute cmd commands via Java but i can’t find my proplem.I’m tested commands in cmd, it was ok :
MP4Box -dash 10000 -dash-profile live -segment-name output- seg -rap
-bs-switching no input.mp4but when i executed cmd via java code , i get error :
Error - only one input file found as argument, please check usage
Below is my code, has something wrong ?
package com.uit.reformatvideo;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.logging.Logger;
public class ExecuteComandToFormatVideo {
public final static String LINK_MP4BOX = "C:/MP4Box/Tools/MP4Box.exe";
public final static String CREATE_MPD_ECLIPSE = "mp4box -dash 10000 -frag 1000 -rap -bs-switching no";
public final static String CREATE_MPD_IE = "MP4Box -dash 10000 -dash-profile live -segment-name output-seg -rap -bs-switching no";
private static final Logger log = Logger.getLogger(ExecuteComandToFormatVideo.class.getName());
public static void main(String[] args) throws IOException, InterruptedException {
String s = null;
try {
// run the Unix "ps -ef" command
// using the Runtime exec method:
String lsCmd[] = new String [2];
lsCmd[0] = LINK_MP4BOX;
lsCmd[1] = "MP4Box -dash 10000 -dash-profile live -segment-name output-seg -rap -bs-switching no input.mp4";
Process p = Runtime.getRuntime().exec(lsCmd);
p.waitFor();
BufferedReader stdInput = new BufferedReader(new
InputStreamReader(p.getInputStream()));
BufferedReader stdError = new BufferedReader(new
InputStreamReader(p.getErrorStream()));
// read the output from the command
System.out.println("Here is the standard output of the command:\n");
while ((s = stdInput.readLine()) != null) {
System.out.println(s);
}
// read any errors from the attempted command
System.out.println("Here is the standard error of the command (if any):\n");
while ((s = stdError.readLine()) != null) {
System.out.println(s);
}
System.exit(0);
}
catch (IOException e) {
System.out.println("exception happened - here's what I know: ");
e.printStackTrace();
System.exit(-1);
}
}
}Here was out put :
Here is the standard output of the command :
Here is the standarderror of the command (if any) : Error - only one
input file found as argument, please check usage