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• Bash : sort find results using part of a filename

  13 novembre 2015, par utt50

  I have 3 webcams set up in a building, uploading still images to a webserver. I’m using ffmpeg to encode the jpgs to mp4 video.

  The directories are set up like this :

  Cam1/201504
  
  Cam1/201505
  
  Cam2/201504
  
  Cam2/201505
  
  Cam3/201504
  
  Cam3/201505

  I’m using the following bash loop/ffmpeg parameters to make one video per camera, per year. This works well so far (well... except that my SSD is rapidly degrading in performance - too many simultaneous read/write operations ?) :

  find Cam2/2013* -name "*.jpg" -print0 | xargs -0 cat | ffmpeg -f image2pipe -framerate 30 -vcodec mjpeg -i - -vcodec libx264 -profile:v baseline -level 3.0 -movflags +faststart -crf 19 -pix_fmt yuv420p -r 30 "Cam2-2013-30fps-19crf.mp4"

  The individual files are named like this (confusing ffmpeg’s built-in file sequencer) :

  Cam1_2015052413543201.jpg
  
  Cam1_2015052413544601.jpg
  
  Cam2_2015052413032601.jpg
  
  Cam2_2015052413544901.jpg

  I now need to create one video for an entire year across all 3 cameras, ordered by timestamp. To accomplish this, I need to sort the find results by the segment of the filename after the underscore.

  What do I pipe the find output to to accomplish this ? For example, the files above would be ordered like this :

  Cam2_2015052413032601.jpg
  
  Cam1_2015052413543201.jpg
  
  Cam1_2015052413544601.jpg
  
  Cam2_2015052413544901.jpg

  Any help is very much appreciated !

• How to use original names when using find -exec ?

  20 novembre 2015, par ironsand

  There are .mp4 files I want to convert.

  $ find . -name '*.mp4'
  
  ./01.mp4
  
  ./02.mp4
  
  ./03.mp4

  I expected to output files copy-01.mp4, copy-02.mp4 and copy-03.mp4 with this command.

  find . -name '*.mp4' -exec ffmpeg -i {} -c copy -aspect 16:9 copy-{} ";"

  But it failed with errors Unable to find a suitable output format for 'copy-'.
  I thought {} represents the file name, isn’t it ?

  How can I use original file names when using -exec option of find ?

  The find version is :

  $ find --version
  
  find (GNU findutils) 4.4.2
  
  Copyright (C) 2007 Free Software Foundation, Inc.
  
  License GPLv3+: GNU GPL version 3 or later /gnu.org/licenses/gpl.html>
  
  This is free software: you are free to change and redistribute it.
  
  There is NO WARRANTY, to the extent permitted by law.
  
  
  
  Written by Eric B. Decker, James Youngman, and Kevin Dalley.
  
  Built using GNU gnulib version e5573b1bad88bfabcda181b9e0125fb0c52b7d3b
  
  Features enabled: O_NOFOLLOW(disabled) LEAF_OPTIMISATION FTS() CBO(level=0)

  This is xargs version.

  xargs --version
  
  xargs (GNU findutils) 4.4.2
  
  Copyright (C) 2007 Free Software Foundation, Inc.
  
  License GPLv3+: GNU GPL version 3 or later /gnu.org/licenses/gpl.html>
  
  This is free software: you are free to change and redistribute it.
  
  There is NO WARRANTY, to the extent permitted by law.
  
  
  
  Written by Eric B. Decker, James Youngman, and Kevin Dalley.
  
  Built using GNU gnulib version e5573b1bad88bfabcda181b9e0125fb0c52b7d3b

  Result of ffmpeg

  $ find * -type f -name '*.mp4' -exec ffmpeg -i {} -c copy -aspect 16:9 copy-{} ";"
  
  
  
  # almost same outputs several times here.
  
  
  
  ffmpeg version N-50911-g9efcfbe Copyright (c) 2000-2013 the FFmpeg developers
  
    built on Mar 13 2013 21:26:48 with gcc 4.7.2 (GCC)
  
    configuration: --enable-gpl --enable-version3 --disable-w32threads --enable-avisynth --enable-bzlib --enable-fontconfig --enable-frei0r --enable-gnutls --enable-libass --enable-libbluray --enable-libcaca --enable-libfreetype --enable-libgsm --enable-libilbc --enable-libmp3lame --enable-libopencore-amrnb --enable-libopencore-amrwb --enable-libopenjpeg --enable-libopus --enable-librtmp --enable-libschroedinger --enable-libsoxr --enable-libspeex --enable-libtheora --enable-libtwolame --enable-libvo-aacenc --enable-libvo-amrwbenc --enable-libvorbis --enable-libvpx --enable-libx264 --enable-libxavs --enable-libxvid --enable-zlib
  
    libavutil      52. 19.100 / 52. 19.100
  
    libavcodec     55.  0.100 / 55.  0.100
  
    libavformat    55.  0.100 / 55.  0.100
  
    libavdevice    54.  4.100 / 54.  4.100
  
    libavfilter     3. 45.103 /  3. 45.103
  
    libswscale      2.  2.100 /  2.  2.100
  
    libswresample   0. 17.102 /  0. 17.102
  
    libpostproc    52.  2.100 / 52.  2.100
  
  Input #0, mov,mp4,m4a,3gp,3g2,mj2, from '24.mp4':
  
    Metadata:
  
      major_brand     : mp42
  
      minor_version   : 0
  
      compatible_brands: mp42isomavc1
  
      creation_time   : 2012-11-01 13:42:12
  
      encoder         : HandBrake 0.9.8 2012071700
  
    Duration: 00:24:58.62, start: 0.000000, bitrate: 474 kb/s
  
      Stream #0:0(und): Video: h264 (Main) (avc1 / 0x31637661), yuv420p, 640x256, 341 kb/s, 29.97 fps, 29.97 tbr, 90k tbn, 180k tbc
  
      Metadata:
  
        creation_time   : 2012-11-01 13:42:12
  
      Stream #0:1(und): Audio: aac (mp4a / 0x6134706D), 48000 Hz, stereo, fltp, 127 kb/s
  
      Metadata:
  
        creation_time   : 2012-11-01 13:42:12

• ffmpeg : Could not find tag for codec none in stream #2

  20 août 2022, par StOMicha

  To add a second audio track to a video having already one audio, I tried

  


  $ ffmpeg -i 1.mp4 -i 2.m4a -map 0   -map 1:a -c:v copy -shortest __out.mp4
Could not find tag for codec none in stream #2, codec not currently supported in container
Could not write header for output file #0 (incorrect codec parameters ?): Invalid argument


  


  From here, I added the -v option :

  


  ffmpeg -i 1.mp4 -i 2.m4a -map 0 -map 1:av -c:v copy -shortest __out.mp4
Stream map '1:v' matches no streams.


  


  The file 2.m4a has the correct audio. How to fix this ?