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Autres articles (71)
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Gestion des droits de création et d’édition des objets
8 février 2011, parPar défaut, beaucoup de fonctionnalités sont limitées aux administrateurs mais restent configurables indépendamment pour modifier leur statut minimal d’utilisation notamment : la rédaction de contenus sur le site modifiables dans la gestion des templates de formulaires ; l’ajout de notes aux articles ; l’ajout de légendes et d’annotations sur les images ;
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Dépôt de média et thèmes par FTP
31 mai 2013, parL’outil MédiaSPIP traite aussi les média transférés par la voie FTP. Si vous préférez déposer par cette voie, récupérez les identifiants d’accès vers votre site MédiaSPIP et utilisez votre client FTP favori.
Vous trouverez dès le départ les dossiers suivants dans votre espace FTP : config/ : dossier de configuration du site IMG/ : dossier des média déjà traités et en ligne sur le site local/ : répertoire cache du site web themes/ : les thèmes ou les feuilles de style personnalisées tmp/ : dossier de travail (...) -
Les autorisations surchargées par les plugins
27 avril 2010, parMediaspip core
autoriser_auteur_modifier() afin que les visiteurs soient capables de modifier leurs informations sur la page d’auteurs
Sur d’autres sites (8602)
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Wave64 (.w64) file format : question regarding chunk GUIDs
24 janvier 2023, par pduI am having trouble understanding the headers of the Wave64 (.w64) files generated by
ffmpeg
and especially the GUIDs.

The specification


I have found this document which describes the file format and the GUIDs. I have also found other websites (here and here) that (indirectly) point to the same document. So this document is the only thing I have.


According to this document the GUIDs are 128bits/16bytes long and should start with the FourCC of the Wave file format, but in lowercase instead of uppercase (see page 3). It also says that the 64bits fields are stored in little-endian (see item 3 of the list page 1), but it does not say anything about 128bits fields (but it should be the same).
For example the GUID for the RIFF chunk is :
66666972-912E-11CF-A5D6-28DB04C10000
.

The problem


When I open a .w64 file generated by
ffmpeg
with an hex editor, I get this :72 69 66 66 2E 91 CF 11 A5 D6 28 DB 04 C1 00 00
. At the beginning,76 69 66 66
stands forriff
in ASCII. We can see that0x66666972
from the spec was indeed stored in little-endian order (so far, so good). If we continue, we have2E 91
andCF 11
, which are still little-endian for0x912E
and0x11CF
. But now it gets weird : the following group of bytes are :A5 D6
and28 DB 04 C1 00 00
for0xA5D6
and0x28DB04C10000
in the spec. So it is in big-endian now ?

For reference, the relevant
ffmpeg
source files are wavenc.c, w64.h and w64.c.
I have also found this thread where someone implemented a .wav to .w64 converter (see the .7z attachment in the first post) and the GUIDs are stored in the same way asffmpeg
.

Conclusion


Seeing that two different implementations are doing the same thing, it probably means that I am missing something. Do you have any explanation ?


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Big question of Target size, or video bitrate must be specified when using two-pass
14 juillet 2022, par RojojunI tried to solve the error which is Target size, or video bitrate must be specified when using two-pass.


But I couldn't find how to solve it and how to find path of video exactly I attached my code below this post


Please give me some tips of solving the problem !


@Service
public class ThumbnailService {

 public HashMap exportThumbnail(File file) throws Exception {
 // file is from controller and form-data
 //String inputPath = "Users/hojunna/Download/my/";
 //String outputPath = "/usr/local/video/thumbnail/";

 String ffmpegBasePath = "/opt/homebrew/bin/";
 FFmpeg ffmpeg = new FFmpeg(ffmpegBasePath+"ffmpeg"); 
 FFprobe ffprobe = new FFprobe(ffmpegBasePath+"ffprobe"); 
 
 FFmpegBuilder builder = new FFmpegBuilder()
 .setInput("/Users/hojunna/Desktop/" + file) 
 //.overrideOutputFiles(true) 
 //.addExtraArgs("-ss", "00:00:01") 
 .addOutput("/Users/hojunna/Desktop/test.jpg") 
 .setFrames(1)
 .setVideoFilter("select='gte(n\\,10)',scale=200:-1")
 .done();

 FFmpegExecutor executor = new FFmpegExecutor(ffmpeg, ffprobe); 
 executor.createJob(builder).run(); 
 executor.createTwoPassJob(builder).run(); 

 HashMap resultMap = new HashMap();
 return resultMap;
 }
}



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How can I tell subprocess to answer "y" to a commandline question ?
13 mai 2022, par FaindirnomainzeinI'm automating an ffmpeg command but when the file exists already, it asks me if I have to "Overwrite [y/N]" and it stalls the entire script until I have to enter "y" myself in the console. How can I automate that ?


for file in all_files_in_dir:
 output = file.split('.')[0]
 subprocess.call(f'ffmpeg -hide_banner -i {file} -map 0:s:1 {output}.srt')



I have to enter "y" myself (as seen in green), then press enter everytime a file is already found. The answer will be "y", so I can hardcode the answer "y" if need be.