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• Ubuntu ffmpeg command -i not found

  12 avril 2016, par Gerwin

  I’m a beginner with Ubuntu and I need to setup a streaming server for my company, I’ve installed NGINX and FFMPEG, but when I call ffmpeg -i in the ~/ffmpeg/ffmpeg directory it returns an error command not found but when I call ./ffmpeg -i it returns a list with configurations.. why does ffmpeg -i not work and how can I fix it ?

  I think that the Path Enviroment Variable is incorrect but how would I go abouts changing said variable ? I’m not that experienced with Ubuntu / CMD programming / FFMPEG configuration.

  Sources - https://trac.ffmpeg.org/wiki/CompilationGuide/Ubuntu
  https://github.com/arut/nginx-rtmp-module/wiki/Control-module
  and http://docs.unified-streaming.com/tutorials/live/broadcast-247.html#continuous-timestamps

• Revision 1220b49c89 : arm : Fix building vp8_mse16x16_neon.c with MSVC Use the right return values - v

  16 septembre 2014, par Scott LaVarnway

  Changed Paths :
   Modify /vp8/encoder/arm/neon/vp8_mse16x16_neon.c

  
  
  arm : Fix building vp8_mse16x16_neon.c with MSVC

  Use the right return values - vadd_s64 returns int64x1_t, not
  a normal int64_t.

  Change-Id : Ife17213087c1dfb5faaa647f804d2fd140f3a0eb

• PHP variable into FFMPEG

  14 juillet 2015, par kunal

  i am making web tool which should be able to search the file within the Archive and then get the duration of the video with FFMPEG Code.

  for search the file in the Archive , here is my code !

   $command ='find /mnt/archiev/ -name '.$_POST['MXF'].'.mxf';
  
  
  
      if (!($stream = ssh2_exec($con, $command))) {
  
                      echo "fail: unable to execute command\n";
  
                  } else {
  
                      $errorStream = ssh2_fetch_stream($stream, SSH2_STREAM_STDERR);
  
  
  
                      $FILE = stream_get_contents($stream); 
  
  
  
  / check if file exist or not and then run the Next command.
  
  
  
  if(!($FILE))
  
  {
  
          echo "file Doesnt Exist in the Archieve. please enter the correct file ID";
  
          ssh2_exec($con, "logout");
  
          exit;
  
  }
  
  elseif
  
  { 
  
  
  
  $commandA= ffmpeg -i '.$FILE.' 2>&1 | grep "Duration:"';
  
   (!($stream2 = ssh2_exec($con, $command))) {
  
                          echo "fail: unable to execute command\n";
  
                      } else {
  
                          $errorStream2 = ssh2_fetch_stream($stream2, SSH2_STREAM_STDERR);
  
  
  
                          $Duration = stream_get_contents($stream);
  
                          var_dump($duration);
  
  }
  
  }

  My problem is this code returns me NUll value , but it supposed to return me the Duration of video !

  Here $FILE has the file Path , where searched File exist but when i use this with ffmpeg code it returns null

  does anyone have idea how can i make it work, i need to be able to find the files within the archiev and then with stream_get_contens() funcation i get the path of the video and this path i need to use within the FFMPEG as a input but it doesnt work and return the NULL.

  which suppossed to retrun the video Duration.

  please help !!!

  thanks in adavance.