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• Unable find an ffmpeg binary for your Android system

  22 juillet 2024, par Ayush Thakur

  Working on a project where I need to use FFmpeg library in Kotlin to work on some audio files. However I'm unable to initialize the ffmpeg library itself.

  


  this is the error I'm getting

  


  Could not find an ffmpeg binary for your Android system. Did you forget calling: 'new AndroidFFMPEGLocator(this);' ?
2024-07-22 18:48:33.910 11800-11800 PipeDecoder             com.example.sangeet                  E  Tried to unpack a statically compiled ffmpeg binary for your architecture to: /data/user/0/com.example.sangeet/cache/ffmpeg
2024-07-22 18:48:33.923 11800-11800 AndroidRuntime          com.example.sangeet                  E  FATAL EXCEPTION: main (Ask Gemini)
                                                                                                    Process: com.example.sangeet, PID: 11800
                                                                                                    java.lang.Error: Decoding via a pipe will not work: Could not find an ffmpeg binary for your system


  


  @HiltAndroidApp
class Sangeet: Application(){
    override fun onCreate() {
        super.onCreate()
        provideFirebaseApp(this)
        FFmpegKitConfig.setLogLevel(Level.AV_LOG_INFO)
        FFmpegKitConfig.enableLogCallback { Log.d("ffmpeg",it.message) }
        initializeFFmpegKit()
    }
    private fun initializeFFmpegKit() {
        // This method should be sufficient to ensure FFmpegKit is ready to use
        val ffmpegSession = FFmpegKit.execute("ffmpeg -version")
        if (ReturnCode.isSuccess(ffmpegSession.returnCode)) {
            Log.d("FFmpeg", "FFmpeg is ready to use.")
        } else {
            Log.e("FFmpeg", "Failed to initialize FFmpeg: ${ffmpegSession.failStackTrace}")
            initializeFFmpegBinary()
        }
    }
    private fun initializeFFmpegBinary() {
        val ffmpegBinaryPath = filesDir.absolutePath + "/ffmpeg"
        val binaryFile = File(ffmpegBinaryPath)
        if (!binaryFile.exists()) {
            Log.e("FFmpeg", "FFmpeg binary not found at $ffmpegBinaryPath")
            // Copy or download the FFmpeg binary to this path
        } else {
            Log.d("FFmpeg", "FFmpeg binary found at $ffmpegBinaryPath")
        }
    }
}


  


  Tried using AndroidFFMPEGLocator(this) ; as suggested by the compiler in my code but unknown reference error is coming for the above line of code.

  


  Also tried using FFmpegKit.init(this) function but init is also not being recognised by the compiler

  


• ffmpeg fast seek not working for MP4 over HTTP

  27 juillet 2024, par Gmanicus

  I'm attempting to download snapshots from a video provided by the U.S House of Representatives :

  


  https://houseliveprod-f9h4cpb9dyb8gegg.a01.azurefd.net/east/2024-04-11T08-55-12_Download/video_3000000_1.mp4


  


  I am using fluent-ffmpeg in Node to execute this command :

  


  ffmpeg('https://houseliveprod-f9h4cpb9dyb8gegg.a01.azurefd.net/east/2024-04-11T08-55-12_Download/video_3000000_1.mp4')
  .inputOption(`-ss 03:33:33`)
  .outputOptions([
     '-vframes 1'
  ])
  .output('test.png')

// Effectively:
// ffmpeg -ss 03:33:33 -i  -y -vframes 1 test.png


  


  My intention is to fast-seek to the desired timestamp and take a snapshot over HTTP. However, when doing so, the performance is not great. A snapshot takes about 10s per 3hrs of video and seems to increase fairly linearly at that rate.

  


  However, when using ffmpeg on the same video locally, it's super fast ! Sub-500ms regardless of the desired timestamp.

  


  Is there some magic that could be done via ffmpeg options or perhaps some sort of technique with manual requests to get a snapshot at the desired segment of video more efficiently ?

  


• ffmpeg fast seek large MP4 over HTTP

  28 juillet 2024, par Gmanicus

  I'm attempting to download snapshots from a video provided by the U.S House of Representatives :

  


  https://houseliveprod-f9h4cpb9dyb8gegg.a01.azurefd.net/east/2024-04-11T08-55-12_Download/video_3000000_1.mp4


  


  I am using fluent-ffmpeg in Node to execute this command :

  


  ffmpeg('https://houseliveprod-f9h4cpb9dyb8gegg.a01.azurefd.net/east/2024-04-11T08-55-12_Download/video_3000000_1.mp4')
  .inputOption(`-ss 03:33:33`)
  .outputOptions([
     '-vframes 1'
  ])
  .output('test.png')

// Effectively:
// ffmpeg -ss 03:33:33 -i  -y -vframes 1 test.png


  


  My intention is to fast-seek to the desired timestamp and take a snapshot over HTTP. However, when doing so, the performance is not great. A snapshot takes about 10s per 3hrs of video and seems to increase fairly linearly at that rate.

  


  However, when using ffmpeg on the same video locally, it's super fast ! Sub-500ms regardless of the desired timestamp.

  


  Is there some magic that could be done via ffmpeg options or perhaps some sort of technique with manual requests to get a snapshot at the desired segment of video more efficiently ?