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• exec() just run when i access target php in browser

  28 septembre 2016, par Mohammad Shojaa

  i use this code to run another php for some work (ffmpeg convert)

      $binpath = get_option('binpath','/usr/bin/php');
  
      $command = $binpath." -cli -f ".ABSPATH."/videocron.php";
  
      exec( "$command > /dev/null &", $arrOutput );

  but when i upload a video and run this code don’t convert video for ever.

  but when i access to videocron.php from browser all videos i uploaded convert suddenly !!!

  i use alternative exec function(system(); exec(); passthru(); shell_exec();)
  and i check videocron.php by readable function, it is readable.

  even i change owner videocron.php to nobody user

  in mod_security log i get this error :

  [Tue Sep 20 23:01:11 2016] [error] [client 37.156.10.171] ModSecurity: Multipart parsing error (init): Multipart: Boundary not found in C-T. [hostname "codenevis.net"] [uri "/lib/upload-ffmpeg.php"] [unique_id "V@GAb38AAAEAAGrk2QoAAAAH"]

  but even i unistalll mod_security it don’t work automatically.

  but in all don’t convert video until i access to videocron.php from browser !

• ENOENT error when trying to access output with ffmpeg + node.js

  29 juin 2020, par John Grayson

  I am running ffmpeg in a lambda function to do some video processing. My problem is the processed video is not being outputted/saved. Therefore, when I try to access the processed video, I get the error :

  


  ERROR  Error retrieving video to upload [Error: ENOENT: no such file or directory

  


  Relevant parts of my code :

  


  const { spawnSync } = require("child_process");

exports.handler = async (event, context) => {
  spawnSync(
    "/opt/ffmpeg/ffmpeg",
    [
      "-i",
      `/tmp/myfile`,
      'title="Test 123"',
      `/tmp/processed_file`,
    ],
    { stdio: "inherit" }
  );
}



  


  The conversion file itself does not return any errors, but when I try to access processed_file, I get the ENOENT error. I also used an fs.readdir to see what files actually exist in /tmp and the only file there was myfile. Therefore, my processed video truly did not save correctly.

  


  Does anyone know what I might be doing wrong here ? Thanks !

  


• Cannot access the files in the subdirectories [FFmpeg]

  9 décembre 2019, par Ahmet Mehmet

  I try to do a loop job in bash. For example, I want to know some video files’ media info with using ffmpeg using in a loop :

  for i in * */* */*/*; do
  
      ffmpeg -i "$i" -hide_banner
  
  done

  But if I want to access up to 10 subdirectories, I must use */ symbol 10 times and this is so bad. Have can do this operation more pratic and pro way :) ?

  I tried oguz ismail’s solution and it’s worked, thanks for that. But I have an another problem : This time I tried to take an input file to an output file like this :

  find . -c:v copy -c:a copy -i {} \;

  But I got an error something like "At least one output file must be specified", because I couldn’t specify an output. How can I do that ?